Hi,
It is better to show the example data using ?dput(). Here, it is not clear
whether the columns are character columns or lists.
##If it is the latter case
dat1 - data.frame(V1=I(list(1:3, c(1,2,4), c(2,3,4,5))), V2= I(list(c(3,6,5),
c(7,10,9), 2:5)))
dat1$V3 - mapply(`c`,mapply(`-`,
Hi Luigi
Only minor changes needed.
When you go back to a normal xyplot the rules of ratio variables apply the
x-axis default in your case something like pretty(range(x)
So the x-axis limits range from 0-1
and the panel limits therefore are 0-1 +/- 4%
With strip stripplot being categorical the
Hi Luigi
Only minor changes needed.
When you go back to a normal xyplot the rules of ratio variables apply the
x-axis default in your case something like pretty(range(x)
So the x-axis limits range from 0-1
and the panel limits therefore are 0-1 +/- 4%
With strip stripplot being categorical the
HI,
I guess this should be a bit faster.
#1st case
dat1$V3 - lapply(seq_along(dat1$V2),function(i) c(dat1$V2[[i]][-1] -
head(dat1$V1[[i]],-1), tail(dat1$V1[[i]],1)))
#2nd case
dat2$V3 - unlist(lapply(seq_along(lst1[,2]),function(i)
paste(c(lst1[,2][[i]][-1] - head(lst1[,1][[i]], -1),
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When: 7 - 11 July 2014
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Kind regards,
Alain Zuur
--
Dr. Alain F.
Hello,
My name is Merve from Abant Ä°zzt Baysal University. I want to produce
simulative data using R, but I couldn't do. I want to produce n=200, 5
likert type, 20 items and normally distributed data. The normal
distribution is provided by total scores of each of 200 person. I produce
this kind
Dear R experts:
I have updated my R yesterday to version 3.1 and the usual command line
navigation in R stopped working. Specifically, tab key moves the cursor and
does not compete a command, up-arrow key produces ^[[A, instead of
recalling the last command, similarly for other keys. I cannot
Hi all,
I have this data set,
dput(Ts)
structure(list(V1 = c(3, 17, 29, 12, 4.5, 1, 0.5, 0, 0, 0, 1.2,
1.8, 1.5, 0.5, 0, 47.7, 0.3, 0, 2, 0, 5.5, 8, 27.5, 69, 29, 24.5,
57.5, 40, 1, 14.5, 0, 0, 0, 0, 0, 0, 1.5, 2, 0, 0, 0, 0, 7, 29.5,
77, 11.5, 33, 38, 36, 8, 28, 11, 11, 0, 17, 0, 51, 0.5, 5,
I have this dataframe:
df-structure(list(date = structure(c(1395874800, 1395874800, 1395874800,
1395874800, 1395874800), class = c(POSIXct, POSIXt), tzone = ),
hour = structure(c(-2209121804, -2209121567, -2209121005,
-2209118616, -2209116160), class = c(POSIXct, POSIXt), tzone = ),
Hi Dila,
Try:
Ts1 - Ts
Ts[,-11] - lapply(Ts[,-11], function(x) {x[is.na(x)] - Ts[is.na(x), 11]; x})
#or
Ts1[,-11][is.na(Ts1[,-11])] -rep(Ts1[,11],10)[is.na(Ts1[,-11])]
identical(Ts,Ts1)
#[1] TRUE
A.K.
On Tuesday, April 29, 2014 8:53 AM, dila radi dilarad...@gmail.com wrote:
Hi all,
I have
Dear all,
I am having some difficulties understanding how the .combine option in
the foreach function of the foreach package works.
I think I understand the examples in the manual using rbind, cbind and c.
However if I write my own function (no particular purpose in mind,
just to figure out how
Hello,
thank you for accepting me into the list.
I have the following dataframe:
row.names X Y Z 000_001 000_002 000_003
1sample samplesample sample
2sample2 Au5 Au32
Hi,
Try this:
for (i in 1:10) Ts[is.na(Ts[,i]),i] - Ts$V11[is.na(Ts[,i])]
Massimiliano
- Messaggio originale -
Da: dila radi dilarad...@gmail.com
A: r-help@r-project.org
Inviato: Martedì, 29 aprile 2014 10:46:32
Oggetto: [R] Replacing NA's in the data set
Hi all,
I have this data set,
Dear all,
I have a problem in installing the the package zelig. I have window 32
bit operating system and R- 3.0.1 version. zelig' package is not
compatible with R-3.0.1 version. Please help me how to install the package
zelig . If any other package is available in replace of zelig', kindly
Dear all,
I have a problem in installing the the package zelig. I have window 32
bit operating system and R- 3.0.1 version. zelig' package is not
compatible with R-3.0.1 version. Please help me how to install the package
zelig . If any other package is available in replace of zelig', kindly
Hello!
I need some help. I'd like to make a button in Excel which performes
functions wrote in R. Is there is any macros to do this? I don't want to
use RExcel.
Thank you very much!
Sincerely yours,
Olga
[[alternative HTML version deleted]]
__
When I read in your data, I get the following since I am in the EDT time
zone:
df-structure(list(date = structure(c(1395874800, 1395874800, 1395874800,
+ 1395874800, 1395874800), class = c(POSIXct, POSIXt), tzone = ),
+ hour = structure(c(-2209121804, -2209121567, -2209121005,
+
Hi
I can be mistaken but isn't it a question to Microsoft help? Did you try to ask
them?
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Olga Albutova
Sent: Tuesday, April 29, 2014 5:05 PM
To: r-help@r-project.org
Dear,
This is a very efficient way. I have checked some values and it is what is
was looking for.
I want to find the days called dry-weather days. It depends but in my case
it is a dry day if on this day the precipitation N is equal or less than
0.3 mm and if on the day before the day with N =
Well, I suppose you might be able to use VBA to invoke a shell (command line)
which could run an R script, but that would be quite restrictive.
---
Jeff NewmillerThe . . Go Live...
Hi,
It is better to show example data using ?dput().
dat - structure(list(row.names = 1:4, XYZ = c(sample, sample2,
sample3, sample4), `000_001` = c(sample, Au5, C, C
), `000_002` = c(sample, Au32, C, Au4), `000_003` = c(sample,
Au5, A, AC)), .Names = c(row.names, XYZ, 000_001,
000_002,
Hi Peter,
Unfortunately neither of the modifications to the LIB flag worked. I tried:
export CAIRO_LIBS='-L${HOME}/usr/local/lib -lcairo'
This actually gave me an error like this:
.
configure: CAIRO_CFLAGS=-I/home/fong/usr/local/include/cairo
checking if R was compiled with the RConn
Check out
http://www.r-bloggers.com/a-million-ways-to-connect-r-and-excel/ for an
overview. See section 4.
Olga Albutova oda...@gmail.com
Sent by: r-help-boun...@r-project.org
04/29/2014 11:05 AM
To
r-help@r-project.org,
cc
Subject
[R] R in Excel
Hello!
I need some help. I'd
Dear all,
I would like to set the axis of a figure using the max() so to have
more control on the limits of the axis -- this because in the actual
case more independent figures are generated from the same dataframe
and these must have the same axis scale.
Since the figure is generated using
For anyone who has these issues, I eventually recognized that the issue had
to do with the fact the mine cairo was not being compiled with freetype
support. I had to recompile cairo with --enable-ft=yes.
Also removed the setting of the CAIRO_LIBS and CAIRO_CLAGS environment
variables in my
try this:
for (i in 1:10){
Ts[is.na(Ts[, i]), i] - Ts[is.na(Ts[, i]), 11]
}
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Tue, Apr 29, 2014 at 4:46 AM, dila radi dilarad...@gmail.com wrote:
Hi
hi, thanks for your reply
the first record for my date is 2014-03-27 and for my hour is 1899-12-30
12:03:16
I got to this point by importing some data via RODBC from an access database
Now, I would like to get a single column with the date and the time that
for the first record should be equal
You really should read the instructions before complaining. The
manual page for kmeans clearly states that it works on a
numeric matrix of data. That is not what you provided. You gave
it a distance matrix. The function pam() will work with a
distance matrix if it is properly labeled as such, but
Thanks everyone,
That's a 3000 fold speedup. Now if only I can get the same improvement on
the stMincuts iGraph algorithm.
On Fri, Apr 25, 2014 at 4:20 AM, Martin Maechler maech...@stat.math.ethz.ch
wrote:
Stefan Evert stefa...@collocations.de
on Fri, 25 Apr 2014 09:09:31 +0200
On Apr 29, 2014, at 7:14 AM, Ramesh Das wrote:
Dear all,
I have a problem in installing the the package zelig. I have window 32
bit operating system and R- 3.0.1 version.
There is quite of bit of missing information about your setup. Please read the
Posting Guide for advice about the
Here is how I would do the conversion. I start off by setting my timezone
to GMT.
#
df-structure(list(date = structure(c(1395874800, 1395874800,
+ 1395874800,
+ 1395874800, 1395874800), class = c(POSIXct, POSIXt), tzone = ),
+ hour = structure(c(-2209121804,
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Hi Luigi
This produces plenty of white space for the y axes
Y-max(my.data$copy)
stripplot(
copy ~ factor(positivity)|factor(stimulation, levels = c(Unst.,
ESAT6,CFP10,Rv3615c, Rv2654,Rv3879, Rv3873,PHA)),
my.data,
group = positivity,
hor=F,
layout = c(8,1),
Forgot to cc to list
Hi Luigi
Our emails are apparently crossing
What you are doing is referencing down ONLY to the stimulation level and not
the stimulation level + productivity level required for each of the N and P
groups
notch-0.3
stripplot(
copy ~
I cannot get the legend to display the cut points I want correctly.
Instead of doing the colors at 1, 2, 3, 4, 5 - its doing the color breaks
at odd points on the legends. The labels seem to get coded correctly
however.
# Code Below
Dear all,
I have a problem in installing the the package zelig. I have window 32
bit operating system and R- 3.0.1 version. zelig' package is not
compatible with R-3.0.1 version. Please help me how to install the package
zelig . If any other package is available in replace of zelig', kindly
Hi,
I've used the ROC function from the Epi package to plot an ROC curve and
generate descriptive statistics (i.e. sensitivity, specificity, PPV, NPV)
for what ROC considers the best predictor score - this is done automatically
by ROC on the graph. What I want to do, is get these same
Hola, estoy tratando de pasar un script de SAS a R y en SAS se usa el
comando compress para eliminar los espacios en blanco de una cadena de
caracteres, y no encuentro un comando equivalente en R.
Saben si existe el comando equivalente en R o como podria crear una funcion
que realice lo mismo?
Anduvo!
Gracias Emilio!
El 29 de abril de 2014, 16:14, Emilio L. Cano emilopezc...@gmail.comescribió:
Prueba con la función gsub:
x - hello world que pasa mundo x[1] hello world que pasa mundo
gsub( , , x)[1] helloworldquepasamundo
Un saludo,
Emilio
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