Jane Shevtsov wrote:
I am trying to use the plotmo package to generate a partial dependence
plot
for a CART model created with rpart. When running plotmo, I get Error:
get.plotmo.y returned the wrong length (got 204938 expected 205000). The
rpart predict function does indeed return 204938
Hi all,
I'd like to do a scatterplot where some of the values, out of a subset,
are plotted differently in color and shape.
I've worked around the following code but I don't manage to make it right.
Any help greatly appreciated!
# My data
dd - iris
iris$Code - 1:150
# A selection of my data
Hi
Please do not use html formating in your post. It does not bring any advantage.
See inline.
From: Verena Weinbir [mailto:vwein...@gmail.com]
Sent: Thursday, May 29, 2014 3:33 PM
To: PIKAL Petr
Subject: Re: [R] Dataframe: Average cells of two rows and replace them with one
row
Hey,
Thank you
Amber Dawn Nolder wrote 2014-05-28 23:16:
Hello,
I am an R novice, and I am using the partykit package to create
regression trees. I used the following to generate the trees:
ctree(y~x1+x2+x3+x4,data=my_data,control=ctree_control(testtype =
Bonferroni, mincriterion = 0.90,
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Beatriz
Sent: Friday, May 30, 2014 9:37 AM
To: R Help
Subject: [R] Scatter plot selection points
Hi all,
I'd like to do a scatterplot where some of the values, out of a
Hi Ptr,
Thanks for your email however, I cannot make the code work.
Also, I quite like the ifelse approach. I find it very clean.
Cheers
On 30/05/2014 15:57, PIKAL Petr wrote:
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On
Hi
-Original Message-
From: Beatriz [mailto:aguitatie...@hotmail.com]
Sent: Friday, May 30, 2014 10:08 AM
To: PIKAL Petr; R Help
Subject: Re: [R] Scatter plot selection points
Hi Ptr,
Thanks for your email however, I cannot make the code work.
Errors? What code you tried?
Hello,
lm() is designed to work with data.frames, not with matrices. You can
change your code to something like
dat - data.frame(price, pred1 = c(5,6,3,4,5), pred2 = c(2,1,8,5,6))
fit - lm(price ~ pred1 + pred2, data = dat)
and then use the fitted model to do predictions. You don't have to
Hi Petr,
Initially your code didn´t work because 'Code' wasn't in uppercase. It
works now! :) The only thing is that I wanted in red the codes 3.5.
Optional code:
sel - iris[iris$Sepal.Width3.5,Code]
plot(iris$Sepal.Length ~ iris$Sepal.Width,
col=ifelse(iris$Code %in% sel, red, black),
Hi
My code worked. Your code did not work because you was not aware that R
distinguish case of letters :)
-Original Message-
From: Beatriz [mailto:aguitatie...@hotmail.com]
Sent: Friday, May 30, 2014 12:21 PM
To: PIKAL Petr; R Help
Subject: Re: [R] Scatter plot selection points
. I selected a smoother spline (df=2).
(3) the two plots at the end show (1) the risk (exp(linear predictor)) for
combinations of CONTINUOUS and DICHOTOMOUS and (2) a ratio (risk for A vs
risk for B), which I think is what you wanted.
Chris
library(survival)
set.seed(20140530)
nn - 1000
Hello,
I am trying to re-estimate parameters and standard errors in a mean regression
equation by simultaneously running a GARCH (1,1) variance equation. This should
be relatively straightforward, but I cannot for the life of me get it to work.
This has taken up several weeks of my life
Dear R users,
Hi, thank you so much for your help in advance.
I have been using Stata but new to R. For my paper revision using Aalen's
survival analysis, I need to use R, as the command including Aalen's survival
seems to be available in R (32-bit, version 3.1.0 (2014-04-10)) but less ready
On May 29, 2014 9:45 PM, Stephen Meskin actu...@umbc.edu wrote:
Thanks Greg for your response. Is there a work around?
A work around for what?
Of course this begs the question as to Why is attach part of the sample
session in App. A of the introductory manual?
Because people find it
Hello again R People:
I fit an ARIMA model on a particular data set with x_1, ,x_n. Point
x_(n+1) becomes available. I now want to produce a forecast without
updating the model. Is there a way to do that within R, or do I need to
write my own function, please?
Thanks!
Sincerely,
erin
R version 3.1.0 (2014-04-10) -- Spring Dance
Copyright (C) 2014 The R Foundation for Statistical Computing
Platform: i386-w64-mingw32/i386 (32-bit)
library(rJava)
Error : .onLoad failed in loadNamespace() for 'rJava', details:
call: dirname(this$RuntimeLib)
error: a character vector
Dear R users,
I am writing to ask your advice with regard to the computer requirements
(RAM, architecture, processor, hard drive) in order to run R smoothly on
large datasets.
I will be running commands with many bootstrap replications (2000) on the
datasets of 10 firms.
Thank you in
You have given information related to the number of rows that will be involved,
but have offered nothing about the number of columns. That is okay though...
you should attempt your algorithms on progressively larger datasets to gauge
how your problem scales and use your operating system to
In the Cox regression case, the probable explanation is that you have
ties in your data; Stata and coxph may have different defaults for
handling ties. Read the manuals!
The difference in sign in the other cases is simply due to different
definitions of the models. I am sure it is well
Hello yet again.
I have written a small function which calls a couple of the C programs from
the stats base package. It's actually a modification of the arima function.
However, when I try to run it, it says that the C program is not found.
Any suggestions would be much appreciated.
Windows
On May 30, 2014, at 9:55 AM, Bond, Stephen stephen.b...@cibc.com wrote:
R version 3.1.0 (2014-04-10) -- Spring Dance
Copyright (C) 2014 The R Foundation for Statistical Computing
Platform: i386-w64-mingw32/i386 (32-bit)
library(rJava)
Error : .onLoad failed in loadNamespace() for
If you pay attention and are careful not to use any variables names
that conflict then you do not need a work around (and the conflicts
function can help you see if there are any conflicts that you may need
to worry about).
Probably the best work around is to use the with or within function
Hi,
I'm just looking into creating a GUI for my R-Script. Is it possible to
create a gui for the script and send it to somebody? Maybe as a .exe for
example
Thanks
--
Shane
[[alternative HTML version deleted]]
__
R-help@r-project.org
There are several options for creating GUIs depending on how much
control you want and how much work you are willing to put in.
One simple option is the tkexamp function in the TeachingDemos
package. This approach would require whoever receives your script to
have R running, but then they could
Possible, yes, anything is possible, but it your goal is to easily hide R from
the users then you will probably not find the project worth the effort required.
---
Jeff NewmillerThe .
hi R user, i have a problem about missing data while i calculate return in
times series. It means my time series have a lot of code of stocks, i
arrange them as type of panel data. I don't look for any solution.
For example:
CODE DATE RETURN
A 2008 NA
A 2009 0.25
A 2010
There are still a few places available to attend the following course:
Quantitative Risk Analysis with R
Fort Collins, Colorado, USA
June 16-19, 2014
This 4-day course will cover the core principles of quantitative risk
analysis and the most important risk modeling principles and techniques. The
Dear All,
I am trying for the first time to run SQL queries against a remote PostgreSQL
database via RODBC. I am able to establish a connection just fine, as shown by
getting results back from the sqlTables(), sqlColumns() and sqlPrimary Key()
functions in RODBC. However, when I try to run a
--
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PLEASE
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PLEASE
Greg, Ista, (or anyone else),
Let me take one last run at this problem.
Consider the following extract from the Appendix A text:
x - 1:20
w - 1+sqrt(x)/2
dummy - data.frame(x=x, y=x+rnorm(x)*w)
fm - lm(y~x, data=dummy)
fm1 - lm(y~x, data=dummy, weight=1/w^2)
attach(dummy)
/Make the
Hi Stephen,
See in line.
On Fri, May 30, 2014 at 4:18 PM, Stephen Meskin actu...@umbc.edu wrote:
Greg, Ista, (or anyone else),
Let me take one last run at this problem.
Consider the following extract from the Appendix A text:
x - 1:20
w - 1+sqrt(x)/2
dummy - data.frame(x=x,
Hello esteemed R experts,
I am attempting the use the 'focal' function in the raster package to calculate
the mean of an annulus (as opposed to a focal mean of a circle or square).
From what I can tell, this requires me to generate a weights matrix and use
this matrix in the focal function.
1. If you create a variable x or w or dummy, it is stored in the current
environment. You can refer to it by the name x or w or dummy. If you create a
column x in the data frame dummy, you can refer to it as dummy$x or
dummy[[x]]. That is a different x than the variable x in your current
Hi,
I have a matrix of 4.5Kx4.5K elements with column- and row names
I need to convert this matrix into a table, where one column is the name of
the row for the element, the second column is the name of the column for
the same element and the third column is the element itself.
The way I do it
library(reshape2) # you probably need to install reshape2 before this works
?melt
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#.
On May 30, 2014, at 3:07 PM, Assa Yeroslaviz wrote:
Hi,
I have a matrix of 4.5Kx4.5K elements with column- and row names
I need to convert this matrix into a table, where one column is the name of
the row for the element, the second column is the name of the column for
the same element
Hi,
You may try:
##Assuming the dataset is a matrix
mat - structure(c(FBgn0037249, FBgn0036389, FBgn0014002, FBgn0034201,
FBgn0029860, FBgn0028526, FBgn0003486, FBpp0312226, FBpp0312225,
FBpp0312224, FBpp0312223, FBpp031, FBpp0312221, FBpp0312220,
FBtr0346646, FBtr0346645, FBtr0346644,
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