On Thu, 5 Jun 2014 14:58:11 +0200
Giulia Fassio giuliafas...@gmail.com wrote:
Hello,
someone know if it is possible to use R to calculate distance by sea
between two geographic coordinates? I have many points in the sea and
I want to create a matrix using R of the length of trajectories
Tell me if I'm wrong, but I am guessing that you are trying to
calculate the minimum distance between two points, given the presence
of barriers between them. For this problem, I have been using cost
distances. By giving a raster representing the cost of crossing one
cell of the landscape, the
Hi,
Please check this link:
http://stats.stackexchange.com/questions/25956/what-formula-is-used-for-standard-deviation-in-r
A.K.
It is my understanding that the R function SD finds the standard deviation of a
random variable or a list. Please consider the following list: { 1, 2, 3 }. I
claim
could you provide a reproducible example ?dput is your friend
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
On Sat, Jun 7, 2014 at 11:22 AM, Michael Willmorth
mwillmo...@clearwater-research.com wrote:
I'm teaching myself how to use rake() in the R
Firstly, you both need to subscribe to the mailing list. Please go to
https://stat.ethz.ch/mailman/listinfo/r-help and subscribe. In this way
you will also get emails from people asking questions and may benefit or
even contribute help to another. There are several other specialty help
lists
On 07.06.2014 23:34, Milan Bimali wrote:
Dear R Community,
I am in process of developing an R package which in turn depends on a
package that is not available in CRAN but has to be downloaded from a web
source (as follows). Could someone guide me on how to include the package
listed in
Yet another way which returns the row and column of the items you want
rc - which(t(x[,-c(1,ncol(x))]),arr.ind=TRUE) #this identifies the rows and
columns but is one column off
rc[,1] - rc[,1] +1 #this adjusts the columns
colnames(rc) - c(col,row)
rc #show them
Bill
On Jun 6, 2014, at
Dear All,
seeking input (or assurance) that I am using the optFederov in AlgDesign
apropriatelly...
I have:
require(AlgDesign)
c -seq(1,64,by=0.1)
econ=9.16
ic=4.796
hill=1.217
x=5.618
eff -econ-(ic*(c^hill/(x^hill+c^hill)))
cand.list -data.frame(c=c,eff=eff,econ=econ,ic=ic,hill=hill,x=x)
Dear list-members,
I discover recently bbmle package from an answer in r-list. It makes
some analyses more easily to solve. However I have one problem using
fixed parameter of mle2 and one question about parametrization of mle2.
I send the question directly to the maintainer of the package but
Dear William,
Thanks to your answer, i no longer waste time trying to get a solution for
this question. I'm waiting your next release.
Tham
--
View this message in context:
http://r.789695.n4.nabble.com/plot-in-package-psych-with-function-error-bars-by-tp4691632p4691877.html
Sent from the
Thanks so much!
The 'truncnorm' package did the trick for me! Such variables are uncommon in
my field (psychology), so this is the first time I stumbled across this kind
of distribution.
--
View this message in context:
Hi,
You may try:
fun1 - function(len, low, high, mean, sd) {
x - rnorm(len * 2, mean, sd)
x - x[x high x low]
x[1:len]
}
##slow
fun2 - function(len, low, high, mean, sd) {
i - 1
while (i len) {
x - rnorm(1, mean, sd)
if (x high x low) {
i -
Hi VP,
Not sure what you wanted.
Perhaps:
library(XML)
URL -
http://money.securebank.in/index.php?option=com_dashboardview=historyItemid=56startdate=01/01/2013enddate=6/9/2014exchange=MCXsid=1;
doc - htmlParse(URL)
tableNodes - getNodeSet(doc, //table)
dat1 - readHTMLTable(tableNodes[[4]],
Thanks Max and Duncan for the replies.
To Max in particular I would say that ready code written in possibly non-optimal
style (though I did not read enough of caret to have an opinion on that code
in particular) would be good practice too.
When I was a professor and I got complaints about other
Hi All,
I try to empoly Monte Carlo to find out the distribution of my data. The
code is following
library(sp)
library(rgdal)
library(raster)
x-readOGR(., finance) #get one spatial file
N.list-list()
for(i in 1:1000){
Sample.x-sample(1:7059,600) #the shp file includes 7059 points£¬and I
Here is some code with a subset of 50 cases that produces a similar set
of errors to what I got with the full data set (31,690 cases):
##
# Load survey package
#
library(survey)
##
# Create raking margins
##
pop.m01 - data.frame(m01=1:14,
Freq=c(1013620,
Hi,
I have a string something like that:
nw.str - [D][A|D][T|A:D][C|T]
And I need to split it in this way:
[D] [A|D] [T|A:D] [C|T]
Thanks!!
Regards.
Alexsandro Cândido
__
R-help@r-project.org mailing list
try this:
nw.str - [D][A|D][T|A:D][C|T]
x - strsplit(nw.str, ])
paste0(x[[1]], ']')
[1] [D] [A|D] [T|A:D] [C|T]
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Sun, Jun 8, 2014 at 4:30 PM,
On 08/06/2014, 4:30 PM, Alexsandro Cândido de Oliveira Silva wrote:
Hi,
I have a string something like that:
nw.str - [D][A|D][T|A:D][C|T]
And I need to split it in this way:
[D] [A|D] [T|A:D] [C|T]
You could probably use lookahead and lookbehind Perl regular
expressions, but this
On Jun 8, 2014, at 1:46 PM, Duncan Murdoch wrote:
On 08/06/2014, 4:30 PM, Alexsandro Cândido de Oliveira Silva wrote:
Hi,
I have a string something like that:
nw.str - [D][A|D][T|A:D][C|T]
And I need to split it in this way:
[D] [A|D] [T|A:D] [C|T]
You could probably use
Hello everybody. I am using ltm package, an following this sequence:
library(ltm)fit3 - ltm(LSAT ~ z1)factor.scores(fit2, resp.patterns =
rbind(c(0,1,1,0,0), c(0,1,0,1,0)))
And I obtain the following result:
Call:rasch(data = LSAT)
Scoring Method: Empirical Bayes
Factor-Scores for specified
Compare 7059 with nrow(x). Looks like they do not match, it is best not to
hardcode such things.
Cheers, Mike
On 9 Jun 2014 05:40, lijiaming lijiamingfore...@gmail.com wrote:
Hi All,
I try to empoly Monte Carlo to find out the distribution of my data.
The code is following
library(sp)
Hello,
I am using the bnlearn package in R to handle large amounts of data in
Bayesian networks. The variables are discrete and have more than 3
million observations.
With bn.fit function I could easily get the conditional probability
distribution. However, some variables have unobserved
Hi,
If you have library(qdap) installed:
library(qdap)
as.vector(bracketXtract(nw.str,square,with=T))
#[1] [D] [A|D] [T|A:D] [C|T]
A.K.
On Sunday, June 8, 2014 4:31 PM, Alexsandro Cândido de Oliveira Silva
a...@dpi.inpe.br wrote:
Hi,
I have a string something like that:
nw.str -
Which formula for standard deviation are you using?
If you know the population mean then you should divide by n (3 in this
case), but if you don't know the population mean and use the mean
calculated from the sample then it is more usual to use n-1 as the
denominator (this makes the variance an
This is in reference to the post here by Ray Brownrigg:
http://r.789695.n4.nabble.com/inset-one-map-on-top-of-another-map-td3848752.html
using this code with the maps package:
map(state, region= ohio, xlim=c(-85, -80), ylim=c(38, 42))
par(usr=c(-216, -66, 24, 144)) # you should be able to
(1) you hit a memory error, because you are including too many variable
levels. even if you narrowed your 16 variables down to these four, the
`rake` function would need room for matricies containing as much data as a
6-million record table:
nrow( expand.grid( data473t[ , c( 'm11' , 'm12c' ,
On Jun 8, 2014, at 6:27 PM, Alexsandro Cândido de Oliveira Silva wrote:
Hello,
I am using the bnlearn package in R to handle large amounts of data in
Bayesian networks. The variables are discrete and have more than 3 million
observations.
With bn.fit function I could easily get the
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