Hi
Anyway. AFAIK your code looks OK to me, provided you want find the number of
rows without NA in each file.
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Sarah Goslee
> Sent: Tuesday, July 22, 2014 8:22 AM
> To: D
Hi Darius,
This is the main R-help list. We don't know anything about your Coursera
class, including what your code is supposed to do. Not only that, this list
has a no homework policy.
You need to use the discussion group associated with your course, or
whatever materials it provides, to get ass
Hi there,
I am Darius and I am taking the R Programming course in Coursera. I have a
problem that I had spent so much looking for the problem. I wrote my code
and I believe that the code works perfectly fine because it produces the
result as what the course demanded. However, when I tried to submi
Hi Carol,
On 07/21/2014 09:10 PM, Richard M. Heiberger wrote:
l = list(c(1,2), c(3,5,6), c(7))
sapply(l, `[`, 1)
Using sapply() works but won't be very efficient if you have a very long
list. If you worry about efficiency, you can do the following (using the
IRanges package from Bioconductor)
Hi Carol,
On 07/21/2014 01:33 PM, carol white wrote:
Might be a trivial question but how to identify the odd and even indices of a
vector?
x = c(1,z,w,2,6,7)
el of odd indices= 1,w,6
el of even indices= z,2,7
The easiest way is to subset your vector with c(TRUE, FALSE) to keep
only the odd
Ms. White:
Unless I have seriously misjudged, you really really really need to go
through an R tutorial -- An Intro to R ships with R, but there are
many on the web -- before posting here further. You do not appear to
have made much of an effort to learn even the basics, and I consider
it unfair t
l = list(c(1,2), c(3,5,6), c(7))
sapply(l, `[`, 1)
On Mon, Jul 21, 2014 at 3:55 PM, carol white wrote:
> Hi,
> If we have a list of vectors of different lengths, how is it possible to
> retrieve the first element of the vectors of the list?
>
>
> l = list(c(1,2), c(3,5,6), c(7))
>
> 1,3,7 shoul
## these functions assume the argument is integer
odd <- function(x) x%%2 != 0
even <- function(x) x%%2 == 0
evenb <- function(x) !odd(x)
odd(1:10)
even(1:10)
evenb(1:10)
On Mon, Jul 21, 2014 at 4:33 PM, carol white wrote:
> Might be a trivial question but how to identify the odd and even ind
On Jul 21, 2014, at 12:10 PM, Ronald Kölpin wrote:
> Dear R-Community,
>
> I'm trying to estimate the parameters of a probability distribution
> function by maximum likelihood estimation (using the stats4 function
> mle()) but can't seem to get it working.
>
> For each unit of observation I hav
Hi John,
Thanks for your reply (1 month later lol).
In fact maybe the point is that I do not understand exactly the role of latent
variables (what they are, and how to define them in R) in SEM.
Do you have any suggestion of easy basic literature on SEM that can help me
with that?
Most things I h
Might be a trivial question but how to identify the odd and even indices of a
vector?
x = c(1,z,w,2,6,7)
el of odd indices= 1,w,6
el of even indices= z,2,7
given the def of odd and even in
https://stat.ethz.ch/pipermail/r-help/2010-July/244299.html
should a loop be used?
for (i in 1: length(
Dear R-Community,
I'm trying to estimate the parameters of a probability distribution
function by maximum likelihood estimation (using the stats4 function
mle()) but can't seem to get it working.
For each unit of observation I have a pair of observations (a, r)
which I assume (both) to be log-nor
Dear Terry/All,
I was trying to use your explanation of the standard error estimate from
survfit.coxph() to verify the standard error estimates for the method of
log(log(S)), but couldn't get the estimates correct. Here is an example using
the lung dataset:
> fit<-coxph(Surv(time,status)~wt.
Hi,
If we have a list of vectors of different lengths, how is it possible to
retrieve the first element of the vectors of the list?
l = list(c(1,2), c(3,5,6), c(7))
1,3,7 should be retrieved
Thanks
Carol
[[alternative HTML version deleted]]
__
I need that duplicated indicate all row indices (occurences) that are
duplicated. In your example, rows 2,3,4,5,8
Thanks.
Carol
On Monday, July 21, 2014 9:17 PM, William Dunlap wrote:
Can you give an example of duplicated() not working on the rows of a matrix?
Here is an example where i
Terry, I figured out that variance of log(-log(S)) should be (1/H^2)var(H), not
(1/S^2)var(H)!
Thanks
John
e...@mayo.edu>; "r-help@r-project.org"
Sent: Monday, July 21, 2014 11:41 AM
Subject: Re: standard error of survfit.coxph()
Dear Terry,
I was try
Since your boss is Excel based, you might want to give the appearance
of staying in
that environment. Take a look at RExcel and RWord, both at rcom.univie.ac.at
RExcel is a seamless integration of Excel and R.
See the book R through Excel that Erich Neuwirth (the author of
RExcel) and I wrote.
ht
I'm designing an R based application for my boss. It's not much, but
it might save him some time. What it will be doing is reading data
from an MS-SQL database and creating a number of graphs. At present,
he must log into one server to run a vendor application to display the
data in a grid. He then
Dear Bernado,
This isn't really a suitable topic to pursue on the r-help list, so I'll just
comment briefly:
On Mon, 21 Jul 2014 17:34:52 -0700
Bernardo Santos wrote:
> Hi John,
>
> Thanks for your reply (1 month later lol).
> In fact maybe the point is that I do not understand exactly the r
If you are going to drive a car you should learn to drive. Read the
basic intro material for R.
Where does the function "readdata" come from? The syntax you use
(having an assignment inside the function call) is let us say unorthodox
and highly inadvisable.
Since you got an error reading
On 7/20/2014 12:50 AM, Kevin Kunzmann wrote:
Hi,
I have developed a package and would like to switch documentation to
roxygen2 from manual :) However
>roxygen2::roxygenize()
First time using roxygen2 4.0. Upgrading automatically...
Loading required package: nleqnslv
Error in
It's a hack but this works:
cairo_pdf("utftext.pdf", family="Calibri")
plot(0:1,0:1, type="n")
points(0.2, 1, pch=16)
mtext(
text = "pch=16 (\U25CF)",
side = 3,
at = 0.2,
line = 1,
)
points(0.8, 1, pch=17); points(0.85, 1.1, pch=17, xpd=TRUE)
# par(xpd=TRUE) lets p
duplicated(x), for vector or matrix x, flags any value (row for
matrices) previously seen in x. To flag all duplicated values (rows
for matrices) you can use the following allDups() function.
allDups <- function(x) duplicated(x) | duplicated(x, fromLast=TRUE)
> In your example, rows 2,3,4,5,8
I would like to know the sum of squares for each term in my model. I used
the following call to fit the model
fit.courseCross <- lme(fixed= zGrade ~ Rep + ISE
+P7APrior+Female+White+HSGPA+MATH+Years+Course+Course*P7APrior ,
random= ~1|SID,
data = Master.complet
Can you give an example of duplicated() not working on the rows of a matrix?
Here is an example where it does work:
> m <- cbind(c(a=1,b=2,c=3,d=2,e=3,f=4,g=1,h=1), c(11,13,11,13,11,13,13,11))
> class(m)
[1] "matrix"
> m
[,1] [,2]
a1 11
b2 13
c3 11
d2 13
e3 11
f
Dear Terry,
I was trying to use your explanation of the standard error estimate from
survfit.coxph() to verify the standard error estimates for the method of
log(log(S)), but couldn't get the estimates correct. Here is an example using
the lung dataset:
> fit<-coxph(Surv(time,status)~wt.loss,l
Hi,
I am trying to answer the see if density.km (response) is affected by Direction
(continuous, integer), Layer (nominal with 12 levels) and direction (nominal
with 8 levels). There is an interaction between Layer and Direction.
Platform.field is a list of 9 different platforms and is being t
Good day everybody,
I'm a marine biologist student, working on my bachelor thesis and I'm stucked
with a statistical doubt in the process, I hope someone here could help me. My
thesis aims to understand which biological and environmental factors influences
the male aggressive rate of male
Hi,
is it possible to find the duplicated rows of a matrix without a loop or i have
to loop over the rows? duplicated doesn't seem to be helpful
Thanks
Carol
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://st
Dear All,
I have been facing problem running the following code by using
---glamADMB()--
glmmadmb(y_zibb~x+factor(z)+g, data= data_mis_model, family =
"betabinomial", link = "logit", zeroInflation=T)
where "y_zibb" contains zero inflated Beta Binomial response ,
"x" is a normal random variate
"z
We are attempting to create a short Poisson time series (between 10 and 50
datapoints) for a simulation. We want these time series to have no counts
of over 100 and not be zero-inflated. We also are trying generate various
nonlinearities, particularly of a cyclic nature. We have been attempting to
This is a question only about terminology.
Suppose I have data categorized by three factors A, B, and C, with cell means
ybar_ijk and cell frequencies n_ijk, where I, j, and k index A, B, and C
respectively. And suppose I want to summarize the results for factor A by
computing some sort of weig
Here is another approach in R (blatantly stealing Jim Holtman's code
to generate sample data):
> set.seed(1)
> n <- 100
> test <- data.frame(p = sample(10, n, TRUE)
+ , b = sample(10, n, TRUE)
+ )
> test$e <- sample(5, n, TRUE) + test$b # make sure e > b
>
> tmp1 <
-Original Message-
From: Fowler, Mark
Sent: July 21, 2014 1:56 PM
To: 'Duncan Murdoch'
Subject: RE: [R] two questions - function help and 32vs64 bit sessions
The server doesn't shut down, it just kind of shuts everybody else down.
But your mention of TEMPDIR jostled some old memory cell
Hi Paul,
Sorry for the delayed reply. I was away last week. I'm not clear what you want
confirmed about your approach.
(a) "20.57"- computing the rejection region of the analysis. The formulas
implemented at the addresses you gave in your original post are from a
reputable source - Lawless (1
On 21/07/2014 9:40 AM, Fowler, Mark wrote:
Hi Duncan,
I tried your suggestion, but no luck. The first error is no surprise, it
just confirms the address is lost. The second line suggests it worked,
but it didn't. The session is still remembering the original address.
> tools::startDynamicHelp(FA
*Hello,*
I never worked with R before my supervisor asks me to run a semiMarkov
analysis a month ago. After a long struggle, to date, the code works, but I
still get some warnings. However, because of my lack of knowledge in R I am
not possible to figure out the problems or say anything about the
Hi Duncan,
I tried your suggestion, but no luck. The first error is no surprise, it
just confirms the address is lost. The second line suggests it worked,
but it didn't. The session is still remembering the original address.
> tools::startDynamicHelp(FALSE) # shut it down
Warning message:
In file(
Hi
I want to include the plotting symbols pch=16 and pch=17 in text in
the graph used as labels.
This works:
--8<---cut here---start->8---
plot(0:1,0:1, type="n")
points(0.2, 1, pch=16)
mtext(
text = "pch=16 (\U25CF)",
side = 3,
at =
On 21/07/2014 12:24, Charles Thuo wrote:
I have just installed R 3.1.1 in a machine where R 3.0.1 is already
installed. Is it possible to use packages in the 3.0.1 on the 3.1.1.
version as the same are in a single workstation.
Perhaps, perhaps not. It depends in part on your platform which
I have just installed R 3.1.1 in a machine where R 3.0.1 is already
installed. Is it possible to use packages in the 3.0.1 on the 3.1.1.
version as the same are in a single workstation.
Charles
[[alternative HTML version deleted]]
__
R-help@
Hi,
On Monday, July 21, 2014, Shane Carey wrote:
> Hey,
>
> What version of R is required to use the plotly library?
>
> I have R version 3.0.1 and it will not allow me to install the devtools
> package or the ploty package.
>
> I have googled and searched to see what version of R I should be ru
Hey,
What version of R is required to use the plotly library?
I have R version 3.0.1 and it will not allow me to install the devtools
package or the ploty package.
I have googled and searched to see what version of R I should be running
but could not find anything.
Thanks
--
Shane
[[
43 matches
Mail list logo
