Thank you David
Now, the problem is to list all the combinations which verify the
condition III (ie every Rapporteur has to have more or less the same
number of demandeur)
Have you any idea ?
Michel
Le 14/10/2014 13:18, david.kaeth...@dlr.de a écrit :
Hello,
here's a draft of a solution.
Hi all,
I'm trying to use the betamix function (betareg package) to create a beta
mixture model but get this error that I don't understand:
Error in lm.wfit(x, linkfun(y), weights, offset = offset[[1L]]) :
NA/NaN/Inf in 'y'
Error in lm.wfit(x, linkfun(y), weights, offset = offset[[1L]]) :
Dear All,
i am solving the following problem in my work.
The first day from April 01 that gets more than 20 mm on a single day, or
totalled
over 2 consecutive days. i.e April 01 = 92th day of the year.
The column of interest is Rain.
head(Samaru56)
Year Day Rain
1 1928 10
2 1928 2
How to estimate paremeters the of loglogistic,lognormal and 2 parameter
exponential distributions in R using fitdistr function.
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
On 2014-10-14 15:40, Sven E. Templer wrote:
Prevent graphic menues with:
options(menu.graphics = FALSE)
Same response after a pause: 'Killed'
or and define repositories:
options(repos = c(CRAN = http://cran.r-project.org;))
Same response after a pause: 'Killed'
Hi,
I could not find a nice lag operator on zoo object. Perhaps there is,
but I just couldn't find it. Basically I want the operator to return the
lagged zoo object (with one or more variables ) with the original date. For
example, if I write lag(x, -3), then I got the lagged series, but the
did you check the connection in R via for example:
head(readLines(http://cran.r-project.org/web/licenses/GPL-3;))
which should yield:
[1] GNU GENERAL PUBLIC LICENSE
[2]Version 3, 29 June 2007
[3]
[4] Copyright (C) 2007 Free Software Foundation, Inc.
On Wed, 15 Oct 2014, jpm miao wrote:
Hi,
I could not find a nice lag operator on zoo object. Perhaps there is,
but I just couldn't find it.
See ?lag.zoo.
Basically I want the operator to return the
lagged zoo object (with one or more variables ) with the original date. For
example, if I
Hi,
You probably missed the na.pad argument of the lag function (for
zoo objects).
?zoo:::lag.zoo
Regards,
Pascal
On Wed, Oct 15, 2014 at 6:00 PM, jpm miao miao...@gmail.com wrote:
Hi,
I could not find a nice lag operator on zoo object. Perhaps there is,
but I just couldn't find it.
Hi
twodays - rowSums(embed(Samaru56$Rain,2))
gives you sum of rain in 2 cosecutive days
sel - which(twodays20)
gives you vector of row numbers in which above condition results in TRUE value
Samaru56[sel,]
selects these rows
Regards
Petr
-Original Message-
From:
Hi
is
plot(11:20, ylim=c(0,40))
abline(h=40)
what you want?
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of PO SU
Sent: Tuesday, October 14, 2014 11:33 AM
To: R. Help
Subject: [R] how to ajust y-axis
I just found a curious behaviour of regexp and I'd like to share with y'all.
gsub(^([[:alnum:]\\[\\]]*).*, \\1, array[n] - 10, perl=T) #
works as expected (array[n])
gsub(^([[:alnum:]\\[\\]]*).*, \\1, array[n] - 10, perl=F) #
doesn't work (a)
I didn't find anything in the documentation explain
Hi, this sound like u are calculating cummulative rainfall, this can also be
done in excel, then import the matrix to R, hope can help,
Franklin, Maseno, Kenya.
On Wednesday, October 15, 2014 1:02 PM, PIKAL Petr petr.pi...@precheza.cz
wrote:
Hi
twodays - rowSums(embed(Samaru56$Rain,2))
Hi,
I would like to apply the vcov function from the survey package for the
variables api00 and api99 grouped by the stype variable which can assume H,
M and E categories.
From the code in the survey package manual:
data(api)
dclus1-svydesign(id=~dnum, weights=~pw, data=apiclus1, fpc=~fpc)
I believe the backslash is not considered an escape character by the extended
RE library used by R (perl=FALSE), so it is being treated as a literal. This
means that the last ] is outside the character class and is the atom that the *
applies to.
gsub(^([[:alnum:]\\[\\]]*).*, \\1, a]]]rray[n]
it might be slightly different, but i think the result is very close to a
tsl result (which hasn't been implemented).. could you use this?
mns-svyby(~api00+api99, ~stype, rclus1, svytotal,covmat=TRUE)
vcov(mns)
On Wed, Oct 15, 2014 at 9:27 AM, Daniela Droguett
I haven't looked at the source so I don't know exactly what is going on, but I
think I have a work around. While running your example I noticed that ellipse()
does not just add the ellipse to the plot produced by plot(), it replots the
figure. However, just running ellipse() without plot()
A couple of observations:
1) I'm not sure what the variable i is doing, looks like you are trying
to loop through years but perhaps you left that bit of code out for
clarity.
2) On the first loop of i you are assigning the values of
Samaru56[sow_day,] to all values in Samaru56. For future loops
On Wed, 15 Oct 2014, David L Carlson wrote:
I haven't looked at the source so I don't know exactly what is going on,
but I think I have a work around. While running your example I noticed
that ellipse() does not just add the ellipse to the plot produced by
plot(), it replots the figure.
Break down your problem into parts:
# compute two-day totals. I use filter here, but there are many ways
twoDayTotal - function (x, init = 0)
{
# init lets you supply rainfall from day previous to first in x
filter(c(init, x), c(1, 1))[-length(x)]
}
# compute the first time a logical
twodays - c(filter(x,c(1,1),sides=1))
might be more efficient with memory than the embed approach, which might be
important if more than two days were of interest.
---
Jeff NewmillerThe .
Have you looked at recent entries in the system log files in /var/log,
especially /var/log/kern.log?
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Wed, Oct 15, 2014 at 1:51 AM, r...@openmailbox.org wrote:
On 2014-10-14 15:40, Sven E. Templer wrote:
Prevent graphic menues with:
On Wed, 15 Oct 2014, David L Carlson wrote:
I haven't looked at the source so I don't know exactly what is going on,
but I think I have a work around:
plot(winters.acomp, main=Winters Creek, cex=0.5)
pdf(winters-pdf.pdf)
ellipses(mean=mn, var=vr, r=r, steps=72, thinRatio=NULL, aspanel=FALSE,
Hi R-helpers,
I have a R script (mainCall.R) which takes the value of an object *'Mon'*
as '31-may-2014' or '31-aug-2014' .
How can I run the R script by passing the value of Mon from the command
prompt?
Any help will be appreciated
Regards,
Abhinaba
[[alternative HTML version
Hi all,
I am not sure if this is the right place for this question or if there is
one more specific.
Anyway, I hope somebody can help me.
I am trying to run a GAM with beta distribution from mgcv package.
My dependent variable is a proportion continuously ranging from 0 to 1
(whales density) and
Hi what I have is a large excel doc (100 columns, 350 row) with data values
from 0-1. The end goal is for each row to have a list of colnames of which
columns contain values 0. I've been tinkering around with apply mostly and
some other functions, any help offered would be greatly
Hello There!
I have an issue reading a large text file and parsing it. I would be
grateful if you let me you can help me about? Thanks.
Javad
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
There is this great document called the R Reference that comes with the
software in which you can search for command and find the answer.
There is also a useful function called apropos that can search the help files
from the R prompt. Try apropos(command).
There is also a manual for this
Can you give the result of typing
sessionInfo()
in the session where this happens, please?
On 15/10/14 16:48, Rodrigo Tardin wrote:
Hi all,
I am not sure if this is the right place for this question or if there is
one more specific.
Anyway, I hope somebody can help me.
I am trying to run a
Rodrigo,
OK, it looks as if your mgcv help files/manual are somehow out of sync
with the package version you have loaded. 'betar' is only available from
mgcv 1.8. If you update to the current mgcv from CRAN then this problem
should be solved.
best,
Simon
ps. beta regression is only
Hi Simon,
The result of sessionInfo() is:
R version 3.1.0 (2014-04-10)
Platform: x86_64-w64-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=Portuguese_Brazil.1252 LC_CTYPE=Portuguese_Brazil.1252
[3] LC_MONETARY=Portuguese_Brazil.1252 LC_NUMERIC=C
[5] LC_TIME=Portuguese_Brazil.1252
attached base
Thanks Simon!
That worked!
I did not constrain my k as you suggested, but when I saw my results, my
degrees of freedom are not larger than 1, the REML is negative and all
covariates are not significant (what it does not make sense). Is there
something wrong?
Here's the results of summary (a2)
Dear All,
I have many 50 objects they are all dataframes. Each dataframe has many rows
and four column. I simply want to do an addition of 3rd and 4th column and save
the result into 5th column. Since there are many dataframes, I don't want to do
it one by one, is there a way to loop through
Don¹t know exactly what you mean by ³passing the value of Mon from the
command prompt², but it could be
At the R prompt:
Mon - ¹31-may-2014¹
source(mainCall.R)
If, on the other hand, you mean shell prompt, then within R see
?commandArgs
On 10/15/14, 11:21 AM, Abhinaba Roy
Hola a todos, ¿que tal?
Os escribo porque llevo varios días con la siguiente duda: quiero realizar
el test de K-S para dos distribuciones lognormales, una de ellas con datos
agrupados (bucketizados).
library(stats)
# Definimos las variables
n - 100 # tamaño de la muestra
mean - 0 # media de
Hola,
Un a breve nota para recordar que hoy tendremos la reunión del Grupo de
Usuarios de R de Madrid.
- La agenda es la misma que anunciamos.
- La reunión será en la Facultad de Educación (UNED) en la sala
Fernández Huertas, planta 1ª.
Los detalles de la convocatoria los podéis
Hola Ruben,
Sí precisamente es lo que comentas, en matemáticas no se suele llamar
bucketización (este término se emplea más en informática) sino datos
agrupados. Pero la idea es la que tu mismo dices.
Respecto a las gráficas que has puesto, me han aclarado mucho sobre el
tema, gracias.
Si
Los mapas de Paro a partir de la EPA, pueden llegar como mucho a nivel
provincial para la que la muestra da datos representativos. Una
alternativa son los mapas de mortalidad, para los que hay datos con
mucho mayor nivel de detalle geográfico, véase por ejemplo esta
reciente publicación por
Hola Ruben,
Gracias por los paquetes que me comentas para realizar los contrastes de
bondad de ajuste.
Voy a seguir variando parámetros para ver los resultados que obtengo.
Un saludo y muchas gracias.
El 15 de octubre de 2014, 14:54, rubenfcasal rubenfca...@gmail.com
escribió:
Hola de
Hola Pedro,
Acabo de recordar que hace poco José Luis Cañadas (participa en esta lista)
publicó un enlace suyo a un análisis del paro en Analucía hecho con R y
publicado en RPubs. Sobre mapas asocia diferentes nivels de paro con
diferentes matices de color (rojo)...
Este es el enlace:
Buenos días, les escribo desde Venezuela.
Estoy realizando un curso sobre ciencia de datos (Coursera), en el cual
usamos R, ya he pasado un modulo de estudio sobre el R, pero, actualmente
necesitamos usar los paquetes xlsx y MySql, con la intención de leer
archivos en sus respectivos formatos.
Estimado Juan Carlos Reale
En ubuntu hay dos JDK, yo use el de oracle, no el de ubuntu, y pude
utilizar rmysql. Lo más sencillo es que busque un repositorio donde
instala JDK de oracle (no recuerdo donde pero estaba) porque es más
facil que usar la documentación del instalador desde oracle,
eo que las oreciones y los medicamentos si me estan ayudando. Hoy tengo
cita con el psiquiatra
El 15 de octubre de 2014, 9:33, r-help-es-requ...@r-project.org escribió:
Envíe los mensajes para la lista R-help-es a
r-help-es@r-project.org
Para subscribirse o anular su subscripción a
Hola,
Ando un poco desesperado con los mapas interactivos de Rcharts
https://github.com/ramnathv/rCharts+Leaflet.
Estoy intentando pintar en un mapa las cámaras de tráfico de madrid, y las
estaciones de calidad del aire, simplemente donde están, es decir, aun no
estoy recogiendo los datos de
Miguel,
Alguna experiencia con rCharts tengo pero no tengo experiencia con el
ejemplo que estás haciendo. Creo el problema es que tienes que convertir
data_ en un JSON array. Mira la siguiente respuesta de Ramnathv:
https://github.com/ramnathv/rCharts/issues/114
donde usa
toJSONArray(data_,
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