I think the OP is being vague by saying "time format" (wouldn't a small
reproducible example from the OP help right now)... if that is really another
character string laid out as described then you might have difficulty with time
zones for some values by converting to POSIXct first. If so, you c
Tena koe
For example:
myTime <- Sys.time()
myTime
[1] "2014-11-04 14:58:10 NZDT"
format(myTime, '%Y%m%d:%H%M%S')
[1] "20141104:145810"
My information in ?strptime.
HTH
Peter Alspach
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Be
Suppose I have a object in time format
2014-08-13 00:30:00
I want to convert it to a character string 20140813003000
Is is possible ?
Tjun Kiat
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__
R-help@r-projec
Dear R-help users,
I would like to produce a plot of ordered stacked coloured square where each
square would represent a level of a categorical variable CAT (aprox. 150
levels), the size of the square would represent the frequency FREQ (count) of
that level, the color would represent a proporti
Dear R-helpers
Has anyone successfully used the Webdings font on a pdf or postscript device?
I'm tearing my hair out trying to figure out how to make it work.
# It works on a png() device:
windowsFonts(Webdings = windowsFont("Webdings"))
png('Webdings.png', family = 'Webdings')
plot(-3:3,-3:3,t
On Nov 3, 2014, at 10:47 AM, Bert Gunter wrote:
> See ?strsplit using the fixed =";" argument on the column containing
> the character vector you wish to split.
>
> The trickier part is that the result is a list that needs to be
> manipulated -- ?do.call might be useful here, although I haven't
See ?strsplit using the fixed =";" argument on the column containing
the character vector you wish to split.
The trickier part is that the result is a list that needs to be
manipulated -- ?do.call might be useful here, although I haven't
thought about it seriously -- to build your data frame conta
Hello togehter,
i have a little problem, maybe anyone can help me.
I have a data.frame, which look like this one:
ID Members
1 1 ; abc; def; ghi
2 2 ; abc;
3 3 ;def;
How can I create another column for each value between 2 semicolons?
The resul
Dear all,
Probably a very stupid question.
I am trying to reproduce the example of Pinheiro & Bates pp.278--287 on
R 3.0.2 (Windows).
I'd like to run :
###
mod.nls <- nls(conc ~ SSbiexp(time, A1, lrc1, A2, lrc2), data=Indometh)
mod.lis <- nlsList(conc ~ SSbiexp(time, A1, lrc1, A2, lrc2), data=In
On Mon, 3 Nov 2014 13:51:52 +0100 atesh koul wrote:
> Hi all,
>
> I am new to using model based clustering. I am using the clustering to find
> how many clusters could be there in the data and the assignment of trials
> to these clusters.
>
> The data are hand kinematics data- 12 variables at 1
Hi all,
I am new to using model based clustering. I am using the clustering to find
how many clusters could be there in the data and the assignment of trials
to these clusters.
The data are hand kinematics data- 12 variables at 10 discrete time points
for 17 subjects. I have previously seen use o
Dear all,
about the problem shown by Foehl, I suggest one shortcut to reach the aim in a
simply way:
write.table(matrix(c("Index","Rate","Demand","Supply"),nrow=1,ncol=4,byrow=T,dimnames=NULL),
"fs.csv",sep =";", row.names=F, col.names=F)
write.table(fs, file="fs.csv", append=T, sep="," row.n
On 30/10/14 21:33, Jim Lemon wrote:
> On Fri, 31 Oct 2014 07:19:01 AM Jim Lemon wrote:
>> On Wed, 29 Oct 2014 05:12:19 PM CJ Davies wrote:
>>> I am trying to show that the red line ('yaw') in the upper of the two
>>> plots here;
>>>
>>> http://i.imgur.com/N4Xxb4f.png
>>>
>>> varies more within the
I would like to implement in R a method that was proposed in a paper recently
published in Am J Epidemiol: Adjustment for Missing Confounders in Studies
Based on Observational Databases: 2-Stage Calibration Combining Propensity
Scores From Primary and Validation Data. Am J Epidemiol. 2014;180(3)
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