Beware of Sys.Date, since it returns GMT, so depending on your local timezone
you may be surprised by the result. I prefer to explicitly set the TZ
environment variable and use Sys.time to get local time. You can use trunc() to
chop off the time part.
I would start with this example, which is available from base R, without
additional packages, to help understand the suggestions that follow.
> unclass(as.POSIXlt(Sys.Date()))
$sec
[1] 0
$min
[1] 0
$hour
[1] 0
$mday
[1] 5
$mon
[1] 10
$year
[1] 114
$wday
[1] 3
$yday
[1] 308
$isdst
[1] 0
at
On 05-11-2014, at 14:41, Noha Osman wrote:
> Hi Folks
>
> Iam a new user of R and I have a question . Hopefully anyone help me in that
> issue
>
>
> I have that dataset as following
>
> Sample Population Species Tissue R GB
> 1 Bari1_062-1 Bari1 ret
While you should definitely read the tutorial that Don is referring
to, I'd recommend you take a different approach and use more R
idiomatic code here.
In base R, this could be addressed with few approaches. Look for help
on the following functions:
* tapply
* by
* aggregate
I'd rather rec
On 11/5/2014 5:41 AM, Noha Osman wrote:
Hi Folks
Iam a new user of R and I have a question . Hopefully anyone help me in that
issue
I have that dataset as following
Sample Population Species Tissue R GB
1 Bari1_062-1 Bari1 ret seed 94.52303 80.7
Have you read the tutorial that comes with the R distribution? This is a very
basic database calculation that you will
encounter (or some slight variation of it) over and over. The solution is a
few lines of code, and someone may write it
out for you, but if no one does
You have 20 population
Hi everyone:
My question is about the function "StructTS" of the core package "stats", which
fits by maximum likelihood the basic structural time series model.
According to theory and the references given in "?StructTS", the covariance
matrix of the initial state vector is a diagonal matrix. Ho
Hi Folks
Iam a new user of R and I have a question . Hopefully anyone help me in that
issue
I have that dataset as following
Sample Population Species Tissue R GB
1 Bari1_062-1 Bari1 ret seed 94.52303 80.70346 67.91760
2 Bari1_062-2 Bari1
Disclaimer: This question is more about HTML than R, but since I am using
rmarkdown, I am not sure of a better forum to ask this. The code example below
produces two column HTML output. If you run the example you will see that the
"" paragram starts off at the bottom of the first column an
This is fixed in version 2.37-8 of the survival package, which has been in my "send to
CRAN real-soon-now" queue for 6 months. Your note is a prod to get it done. I've been
updating and adding vignettes.
Terry Therneau
On 11/05/2014 05:00 AM, r-help-requ...@r-project.org wrote:
I am receiv
Hi,
I fitted a genetic model using kinship2 and I compared it with MTDFReml program
output.
The residual variance of both are very close but the genetic variance are very
differents.
The output are:
MTDFReml:
genetic variance = 1.24015
residual variance = 5.93424
R (Kinship2):
genetic varian
Dear Federic
You need to do something like
function(p, weights = NULL, data = NULL, subset = NULL, na.action =
na.fail) { # but you will have Day, Month, Year, data
# instead of the first three
if(is.null(data)) data <- sys.frame(sys.parent())
mf <- match.call()
mf$data <- NULL
mf
Hi
single date and vector of dates is something quite different. Your bithday is
single date, birthdays of country population is vector of dates.
You want to check that some columns in your data are those you want directly
inside the function?
Or you just want to be able to select columns on y
Dear PIKAL,
I am using a data frame not a single value. I wanted to add a new column
"DOY" on a dataset. I made it but I want to make it General. i.e. You will
see in the dataset I am using columns names (Year,month and day.) What if I
have this information in other columns names? In this function
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