Thank you very much Martin and Chel Hee. Indeed both approach works but
Martin's approach covers whole function while Chel Hee's concentrates on
problem line.
Also another thanks to Martin for lesson on error handling which I desperately
need.
ce
-Original Message-
From: "Chel He
It seems that you would like to make a spaghetti plot (in a longitudinal
data analysis). You can use the function 'interaction.plot()'.
> with(my.df, interaction.plot(TIME, ID, X))
I hope this helps.
Chel Hee Lee
On 12/06/2014 02:24 AM, arun wrote:
Not sure whether it is a scatterplot or
I am very happy to see the message replied by Martin Morgan. He
provides an example how to use the function 'withRestarts()'. I
personally like his approach; however, the function 'tryCatch()'
evaluates the first argument 'expression'. That's, this function can be
placed on anywhere. It see
Excuse the inaccuracy, the warning is "value label missing". the same
variable is considered as factor (w/ values ranging from a to b) in one
dataset, as int in another. I want it to be a factor in both.
I think I am missing a package, the output is.
Error in head(dfrm[, "variable"]) : object 'df
On Dec 6, 2014, at 3:54 PM, Edoardo Prestianni wrote:
> hello,
>
> I have imported a couple of .dta datasets, but a variable, instead of being
> labeled as factor (w/ values ranging from a to b) is labeled as integer.
>
> How can I fix this? I am sorry if it is a rookie question but I don't fin
On 12/06/2014 02:53 PM, ce wrote:
Dear all,
Let's say I have this script , below. tryCatch indeed catches the error but
exists, I want function to continue and stay in the loop. I found very
examples of withRestarts on internet to figure it out. Could you help me how to
do it ?
myfunc <-
hello,
I have imported a couple of .dta datasets, but a variable, instead of being
labeled as factor (w/ values ranging from a to b) is labeled as integer.
How can I fix this? I am sorry if it is a rookie question but I don't find
the command googling.
Thanks everyone for their help,
--
Edoard
Dear all,
Let's say I have this script , below. tryCatch indeed catches the error but
exists, I want function to continue and stay in the loop. I found very
examples of withRestarts on internet to figure it out. Could you help me how to
do it ?
myfunc <- function()
{
while(1)
{
x <- r
Hello
I use R to run a simple model of rainfall interception by vegetation:
rainfall falls on vegetation, some is retained by the vegetation (part of
which can evaporate), the rest falls on the ground (quite crude but very
similar to those used in SWAT or MikeSHE, for the hydrologists among you).
I
"\\" is stored as a single backslash, just as "\n" is a single newline
character. It is printed with an extra backslash.
> nchar("\\")
[1] 1
> cat(paste0("\\", "\n"))
\
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Sat, Dec 6, 2014 at 11:00 AM, Prof J C Nash (U30A)
wrote:
> This i
fname = "John"; lname = "Smith"
ans <- paste( fname, " \\ ", lname )
cat( ans)
print( ans )
Note that ans only has one backslash in it, but print gives you a
source-suitable string with the escape character.
---
Jeff Newmill
Thanks. Now why didn't I think of that? However, it underlines that
there is an implicit call to print(), which processes the string rather
than simply dumping it to the screen. That's something to remember (and
I should have!).
Best, JN
On 14-12-06 02:30 PM, Ben Tupper wrote:
> Hi,
>
> When yo
Hi,
When you call paste without assigning the value it returns to anything it runs
through the print command. So, while your string may contain escapes, using
print will not present escapes as you are expecting them. In this case you
could wrap cat() around your paste command.
> cat(paste(
This is NOT critical. It arose due to a fumble fingers when developing
an R example, but slightly intriguing.
How could one build a string from substrings with a single backslash (\)
as separator. Here's the reproducible example:
fname = "John"; lname = "Smith"
paste(fname, lname)
paste(fname, ln
dear
I am interested about"A semiparametric recurrent events model with
time-varying coefficients*"*
> I want to analyze my data with related R program but i could not get it
from its correspondence.
the similar program in frailtypack exict but only used Gamma or Lognormal
frailty whereas in th
Not sure whether it is a scatterplot or just a plot with 3 lines. If it is the
latter,
library(reshape2)
matplot(acast(my.df, TIME~ID, value.var='X'), type='l', col=1:3, ylab='X',
xlab='TIME')
legend('bottomright', inset=.05, legend=LETTERS[1:3], pch=1, col=1:3)
A.K.
On Friday, December 5,
Firstly, there is no fa() function in base R. There is one in package psych(),
which has a maintainer, etc.
I guess that it is because fa() does a non-orthogonal factor rotation and its
print method knows about it, whereas the default print method for loadings
assumes that rotations are orthogo
OK, I got it , you helped me a lot , tks very much. :)
--
PO SU
mail: desolato...@163.com
Majored in Statistics from SJTU
At 2014-12-06 14:12:45, "Jeff Newmiller" wrote:
>If you run R CMD check on your package successfully, then that file will be
>generated as needed automatically. If
Yeah, i can write some roxygen2 which transformed to .RD files.
The pdf of a package in the cran is not a vignette? That's to say some
packages have not vignettes?
And the pdf version is generated by me or cran ? If by me , how can i generate
it from my .RD files.
i am writing a package, s
19 matches
Mail list logo
