On 11/12/14 20:09, Michael Selevan wrote:
This makes sense, thank you for the thorough response!
One follow up question though. Would your #2 option be the same as, say,
not using the rand.gen at all and providing the following parameters
instead?
y3 - arima.sim(n=10, list(ar=0.8),
Thanks for all the help! Ill give them a shot and compare the results.
On Thu, Dec 11, 2014 at 12:29 AM, Rolf Turner r.tur...@auckland.ac.nz
wrote:
On 11/12/14 20:09, Michael Selevan wrote:
This makes sense, thank you for the thorough response!
One follow up question though. Would your #2
Hello
I would like to find an elegant way of calculating
c(rep(1, 43), rep(2,43),, rep(10,43))
Any idea ?
Thank you
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tel : 04.67.61.75.38
port: 06.47.43.55.31
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Hello,
Try the following.
unlist(lapply(1:10, function(n) rep(as.character(n), 43)))
Hope this helps,
Rui Barradas
Em 11-12-2014 10:12, Arnaud Michel escreveu:
Hello
I would like to find an elegant way of calculating
c(rep(1, 43), rep(2,43),, rep(10,43))
Any idea ?
Thank you
Hi Michel,
What about
rep(1:10, each=43)
If you need to have characters, you could do something like:
as.character(1:10)
HTH,
Ivan
--
Ivan Calandra, ATER
University of Reims Champagne-Ardenne
GEGENA² - EA 3795
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51100 Reims, France
+33(0)3 26 77 36 89
Hello
I am struggling with data frames and would appreciate some help please.
I have a data set of 13 observations and 80 variables. The first column
is the names of different political area boundaries (e.g. MHad, LBNW,
etc), the first row is a vector of variable names concerning various
Hi Sun,
If I understood correctly (a reproducible example would be of great
help), it seems you're struggling with factors. Read on this topic to
better understand how it works.
For your plots, you would need to set the labels with the argument
'xlab' for plot(). To access the names of the
Hi,
I have a very simple Cox regression model in which I need to include a
nested random effect: individual nested in treatment. I know how to pass a
single random effect - e.g. frailty(id)- but how can I specify the nested
random (id nested in treatment) effect using frailty?
The equivalent in
If you are using 'read.csv' (or 'read.table') to input, then use the 'as.is
= TRUE' parameter to prevent the conversion to factors of the data.
You can also do as.character(df$col_with_factors) to get the character
values back.
Jim Holtman
Data Munger Guru
What is the problem that you are
Dear R Community,
I wish to create 5 preceding dates from the date variable by ID. How
could I create such dates? The code should consider leap year.
Thanks
Sample data follows:
structure(list(id = 1:12, date = structure(c(9L, 6L, 11L, 8L,
7L, 5L, 4L, 3L, 12L, 1L, 10L, 2L), .Label =
Here is a reproducible example
d - read.csv(text=Name,Age\nBob,2\nXavier,25\nAdam,1)
str(d)
'data.frame': 3 obs. of 2 variables:
$ Name: Factor w/ 3 levels Adam,Bob,Xavier: 2 3 1
$ Age : int 2 25 1
Do you get something similar? If not, show us what you have (you
could trim it
Hi
I have stumbled upon a problem when using gregexpr and regmatches, with the
following error-message:
Error in iconv(x, latin1, ASCII) :
'x' must be a list of NULL or raw vectors
The data:
(1)
I have two journal articles and after some regex manipulation I am at the
following
The sample data you provided has the variable 'date'. Since the type of
this variable is 'factor', you may try to convert type of variable from
'factor' to 'date' as shown in the below:
x$rval - as.Date(x$date, format=%d%b%Y)-5
x
id date case rval
1 1 27apr19931
Here is an example of converting the 'date' your dataframe to 'time'
(POSIXct) and then taking the first 'time' and creating the 5 previous days
from that date:
id date case
1 1 27apr19931
2 2 13feb20051
3 3 29may20021
4 4 22sep20051
5 5 18dec19911
6 6
Hello William, Ivan and Jim
I appreciate your replies.
I did suppress the factors using stringsAsFactors=FALSE and in that way
was able to progress some more on getting a sense of the data set, so
thanks for that suggestion. I had previously overlooked it.
Also thanks William, I never
Ggplot2 also depends on factors, so learn about them asap. It does have some
support for automatically converting strings to factors in some cases, but it
doesn't always work the way you want it to.
---
Jeff Newmiller
Sun Shine wrote
with(MHP.def, {plot(as.integer(MHP.def$Names),cH.E, axes=FALSE,
xlab='Area') axis(side=2) axis(side=1, at=seq_along(levels(MHP.def$Names)),
lab=levels(MHP.def$Names))})
Error: unexpected symbol in with(MHP.def, {plot(as.integer(MHP.def$Names),
MHP.def$cH.E, axes=FALSE,
Thank you Karim,
I'll try that.
Thanks!
Raff
Sent from my iPhone
On Dec 10, 2014, at 1:48 PM, Karim Mezhoud kmezh...@gmail.com wrote:
Hi,
Could you try rbind.na.R function.
karim
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c/ /'_;kmezhoud
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http://bioinformatics.tn/
On Wed, Dec 10,
I am trying to write a script to run occupancy analysis for very large
sets of data for multiple species. I have in the past used PRESENCE but
would like to use R. I am having trouble getting the ObsCov into the
data frame. I get the following error message:
Your query is incoherent, at least to me. If others are similarly
flummoxed and you receive no useful reply, read and follow the posting
guide (link below) to provide code, data, etc. for a minimal example
to explain what you wish to do. In PLAIN TEXT -- no HTML.
Cheers,
Bert
Bert Gunter
Thank you so much Phil,
I will try that.
Best
On Wed, Dec 10, 2014 at 9:42 PM, Phil Chalmers rphilip.chalm...@gmail.com
wrote:
As well, the mirt package contains a function for DIF using likelihood
ratio tests via multiple-group estimation methods (the multiple group
estimation generally goes
Dear R users,
I'd like to make 4 by 7 matrices as many as possible with natural numbers 1
through 28 such that each matrix have different elements of each column.
For example,
simply here is one
a1 - matrix(1:28, 4,7)
a1
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[1,]159 13 17
On Dec 11, 2014, at 4:38 PM, Kathryn Lord wrote:
Dear R users,
I'd like to make 4 by 7 matrices as many as possible with natural numbers 1
through 28 such that each matrix have different elements of each column.
I was tempted to respond:
We're very sorry. The Soduko Challenge Contest was
Hi,
Is there a plotmath symbol like LaTeX's \mapsto?
I need this comparably often, for example if you want to plot a
two-place function in one variable (and thus would like to have
ylab=t \mapsto f(t,s), for example). If there is such a symbol, I'd
be great to have it as an example on ?plotmath.
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