shouldn't your last expression be:
if (any(tst)) big.vector.1[tst] - big.vector.2[tst]
Sure, that was a typo.
Also, I know that `%%` does not make sense neither for Inf nor for big
numbers, but `%/%` - since it's only a special case of `/` - should
make sense; it should be equivalent
Also, of the problem only occurs in RStudio then your question would need to be
asked in their support forum. They do override some standard R functions so
occasionally there are bugs introduced by that. Check if it occurs in plain R
before posting here.
Please don't post in HTML - your code is unreadable.
Using dput() to provide some of your data may also encourage people to
help you figure out what's wrong.
Without a reproducible example that includes some sample data (fake is
fine), the code you used, and some clear idea of what output you
I am trying to add a column with data to a data frame that already has
information but am getting this error:
rich.stats4 = merge(rich.stats,Location,Month,by=X.SampleID)
Error in fix.by(by.x, x) :
'by' must specify one or more columns as numbers, names or logical
I have two separate data
Hi R-Experts,
Thanks to the R package SuppDists, I can draw/plot the sampling distribution
of the Pearson (and/or Spearman) rho coefficient.
install.packages(SuppDists)
library(SuppDists)
curve(dPearson(x,85,rho=0.64),from=-1,to=1)
Do you know a package (or some packages) I could use if I want
shouldn't your last expression be:
if (any(tst)) big.vector.1[tst] - big.vector.2[tst]
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Wed, Mar 11, 2015 at 11:14 AM, William Dunlap wdun...@tibco.com
Dear Sir,
Thanks a lot for your help and guidance.
Regards
Amelia
--`--
On Wed, 11/3/15, Ben Bolker bbol...@gmail.com wrote:
Subject: Re: [R] Gamma Distribution - is there any problem with pgamma?
To: r-h...@stat.math.ethz.ch
Date: Wednesday, 11
Perfect, perfect, perfect.
Thanks very much, John.
Adrian
On Wed, Mar 11, 2015 at 10:00 PM, John McKown
john.archie.mck...@gmail.com wrote:
See if the following will work for you:
grep('^-?[0-9]+([.]?[0-9]+)?$',myvector,perl=TRUE,invert=TRUE)
myvector - c(a3, N.A, 1.2, -3, 3-2, 2.)
Hi,$I had this problem,
delete all and reconfigure ONLY with:
cd /tools
./rsyns.
cd ..
./configure --enable-R-shlib
make
make install
be sure to be in your /home
kmezhoud
On Wed, Mar 11, 2015 at 7:55 PM, peter dalgaard pda...@gmail.com wrote:
On 11 Mar 2015, at 20:05 , MacQueen, Don
Hola,
Como el tema me interesa estuve buscando un poco y parece que la
opción que tiene mejor pinta es
rgeos::gSimplify
http://www.rdocumentation.org/packages/rgeos/functions/topo-unary-gSimplify
y en caso de no estar disponible:
maptools::thinnedSpatialPoly
See if the following will work for you:
grep('^-?[0-9]+([.]?[0-9]+)?$',myvector,perl=TRUE,invert=TRUE)
myvector - c(a3, N.A, 1.2, -3, 3-2, 2.)
grep('^-?[0-9]+([.][0-9]+)?$',myvector,perl=TRUE,invert=TRUE)
[1] 1 2 5 6
The key is to match a number, and then invert the TRUE / FALSE
Hi everyone,
I need a regular expression to find those positions in a character
vector which contain something which is not a number (either positive
or negative, having decimals or not).
myvector - c(a3, N.A, 1.2, -3, 3-2, 2.)
In this vector, only positions 3 and 4 are numbers, the rest should
Dear Mr Byng,
Thanks a lot for your great help. Appreciate.
Regards
Amelia
On Wed, 11/3/15, Martyn Byng martyn.b...@nag.co.uk wrote:
Subject: RE: [R] Gamma Distribution - is there any problem with pgamma?
e...@r-project.org
Date: Wednesday, 11
What is the result of
capabilities()['tcltk']
?
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 3/9/15, 2:27 PM, Imran Akbar im...@infoscoutinc.com wrote:
Hi,
I've installed the latest version of R from source on Amazon
I am trying to replicate the twitter and word cloud example found here
https://sites.google.com/site/miningtwitter/questions/talking-about/wordclouds/wordcloud1
When implemented verbatim, I replicate results and all works fine. But, when I
make a slight modification to the code it fails in
OSX 10.10.2
R 3.1.3
XQuartz installed.
I am trying to run one of the tcltk demos
This one works:
tt - tktoplevel()
label.widget - tklabel(tt, text = Hello, World!)
button.widget - tkbutton(tt, text = Push,
command = function()cat(OW!\n))
tkpack(label.widget,
Dear all,
My package 'gRbase' uses three packages from Bioconductor and these are not
automatically installed when gRbase is installed. My instructions (on the
package webpage) to users are therefore to run:
source(http://bioconductor.org/biocLite.R;);
biocLite(c(graph,RBGL,Rgraphviz))
When
Hi,
you didn't specify values in A, and you first wanted to compare bi
with Aij, but then also which bi is less/equal to zero.
For the first case, with
A - matrix(0:3,2)
b - seq(-1,5)
and a comparison function for bi less/equal to Aij like
f - function (bi) {as.integer(bi=A)}
you can iterate
Hi Erin,
If you want to use .First, just put it in the directory where you start up
your R session, use it to change all the options that you want for all
projects, then source a file to switch to the directory that you want. I
call mine SelectAnalysis.R and it just displays a list of current
Steve,
Here is one approach that works. I am calling your first data frame df.
# list all years from min to max observed in each ID
years - tapply(df$Date, df$ID, function(x) min(x):max(x))
# create a data frame based on the observed range of years
fulldf - data.frame(ID=rep(names(years),
On 11/03/2015 10:31, Bob O'Hara wrote:
Hi!
I'm trying to persuade R's regular expressions to do what I want. I
This is not R's regular expressions , but the world's regular expressions.
have a vector of strings which are names of variables, some of which
are elements of strings. I want to
Dear R forum
I have following data
amounts =
c(928906.144,156091.0576,433798.3404,993425.7224,1323976.364,649106.9339,
http://stats.stackexchange.com/questions/7268/how-to-aggregate-by-minute-data-for-a-week-into-hourly-means
On Wed, Mar 11, 2015 at 12:19 PM, Kuma Raj pollar...@gmail.com wrote:
I have a measurement that was taken in 15 minutes or more and want to
aggregate it by hour. How could I do that?
I've just found an annoyance with the behaviour of %/% which, BTW,
violated the sacred rule that for all a, and non-zero b:
a = b * (a %/% b) + a %% b
Namely, that Inf %/% n is not Inf, but NaN.
Why is this so? It's an annoyance, because in expressions like:
big.vector.1[a, b, c] -
I have a measurement that was taken in 15 minutes or more and want to
aggregate it by hour. How could I do that?
Sample data is found below
date_time concentration
26/11/2013 15:46 529.25
26/11/2013 16:03 1596
26/11/2013 16:23 1027.111
26/11/2013 16:39 1001.9
26/11/2013 16:54 -80.25
26/11/2013
On 11/03/15 20:01, Frederic Ntirenganya wrote:
Hi All,
I need a help on a loop which can compare the each component of vector to
each component of a Matrix.
Let a vector b = {b1, b2, ...,bn} and 2x2 matrix A = Aij.
I need to compare each component of the vector with each component of a
Hi!
I'm trying to persuade R's regular expressions to do what I want. I
have a vector of strings which are names of variables, some of which
are elements of strings. I want to reformat all of the variables into
a list, so (for example) beta[1] and beta[2] would be a vector in the
list. Where I'm
On 03/11/2015 01:36 AM, Søren Højsgaard wrote:
Dear all,
My package 'gRbase' uses three packages from Bioconductor and these are not
automatically installed when gRbase is installed. My instructions (on the
package webpage) to users are therefore to run:
Treat Bioconductor packages as any
Amelia Marsh amelia_marsh08 at yahoo.com writes:
Dear R forum
I have following data
amounts = c(928906.144,156091.0576,433798.3404,993425.7224,
1323976.364,649106.9339, 369967.2612,2528872.35,1226093.655,
1145446.149,1809624.453,599329.0394,2200955.213,2583318.064,
I think these dates are from some historical database, as they are
labeled BC. And the days might refer to some Epoch of ancient
calendars, maybe the Chinese Calendar whose Epoch was 105 BC (at least
if we can trust Wikipedia:
https://en.wikipedia.org/wiki/Chinese_calendar )
Alberto Monteiro
Hi,
Try
pgamma(amounts,shape_gamma,scale=scale_gamma)
as I am guessing you mean scale_gamma to be the scale of the distribution, but
are using it as the rate ( = 1 / scale) instead
Martyn
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Amelia Marsh
Hola buenos d�as:
�Conoc�is un m�todo para que dada alguna poligonal geogr�fica, pueda
simplificar el n�meros de puntos que forma el pol�gono de una forma razonable?
La idea ser�a alguna funci�n (o librer�a que pueda ayudar para tal caso) hecha
en R donde metiendo un vector de coordenadas de una
Hi All,
I need a help on a loop which can compare the each component of vector to
each component of a Matrix.
Let a vector b = {b1, b2, ...,bn} and 2x2 matrix A = Aij.
I need to compare each component of the vector with each component of a
matrix and print 1 if the component is less or equal
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