Hello!
I have a cbind type question, please: Suppose I have the following:
dog <- 1:3
cat <- 2:4
tree <- 5:7
and a character vector
big.char <- c("dog","cat","tree")
I want to end up with a matrix that is a "cbind" of dog, cat, and tree.
This is a toy example. There will be a bunch of variabl
Thank you very much, everybody!
On Thu, Apr 23, 2015 at 10:38 AM, Duncan Mackay wrote:
> Hi Dimitri
>
> here is a quick crude way (needs some polishing)
>
> data.frame(a = rep(x$a,sapply(sapply(x$b, strsplit, ", "), length)), b=
> unlist(sapply(x$b, strsplit, ", ")))
>
> Duncan
>
> Duncan Mackay
Are there missing values in your data? If so, try adding
the argument
na.action = na.exclude
to your original call to glm or lm. It is like the default
na.omit except that it records which rows were omitted
(because they contained missing values) and fills in
the corresponding entries in the p
Hello,
In the following code, any characters matching "/|@| \\|") will be changed to
a space.
> library(tm)
> toSpace <- content_transformer(function(x, pattern) gsub(pattern, " ", x))
> docs <- tm_map(docs, toSpace, "/|@| \\|")
What code would transform all non-letters to a space? (What goes
Hi all,
Given a simple logistic regression on a training data set using glm,
the number of predicted values is less than the number of observations
in the training set:
> fit.train.pred <- predict(fit, type = "response")
> nrow(train)
[1] 62660
> length(fit.train.pred)
[1] 58152
>
As a relative
Hi R-help,
I've looked at google, the Rscript documentation and the Rscript --help
output and haven't found much on this. So, here's my question:
I have a rather long script that runs on various input datasets. It is
quite convenient to run the script from the Terminal command line with
"Rscrip
Apologies for cross-posting
We would like to announce the following statistics course in Palm Cove,
Australia.
Course1: GLM with R (Bayesian and frequentist)
Location: Palm Cove, Australia
Date: 11-14 August 2015
Price: 475 GBP
Course website: http://www.highstat.com/statscourse.
I am are currently evaluating risk factors associated with a virus A ,
incidence among patients with a follow-up sample of 312. Overall, the
virus incidence rate is estimated at 4.7 per 100 pyr, 95% CI
(3.0-7.4), with a total follow-up time of 383.9 person years and 18
incidence cases.
How can I d
Hi R-help,
I've looked at google, the Rscript documentation and the Rscript --help
output and haven't found much on this. So, here's my question:
I have a rather long script that runs on various input datasets. It is
quite convenient to run the script from the Terminal command line with
"Rscrip
Andrés
Si prefieres escribir en español
https://stat.ethz.ch/mailman/listinfo/r-help-es
seria mejor
(That is a link to the Spanish language version of R-help)
On 23/04/2015 05:24, Andrés M wrote:
Buenas noches,
comedidamente me dirijo a ustedes para hacerles una consulta respecto a un
error que
It certainly is! Thank you.
Cheers,
Mano
On Thu, Apr 23, 2015 at 12:02 AM, Rolf Turner
wrote:
> On 22/04/15 22:43, Manoranjan Muthusamy wrote:
>
>
>
> 4.
>> How can I show the Dirichlet tile names (i.e. 1,2,3,,8) in the
>> plot?
>>
>
> There's no built-in way at the moment as far as
findAssocs() is not working, as is seen below. "Lucid" and "dreaming" occur
together quite often in the book.
The corpus is a single document, the text version of a book. Does this
function require at least two documents? If so, if I split the book in half
will I get the correlations regardi
Dear all,
I believe I have found a bug in rlm in the MASS package. Specifically, the
scale estimate can be wrong when there are no outliers. The following code
snippet is an example:
dose <- c(0,1,2,0,1,2)
response <- c(0.659,1.633,3.621,1.803,3.093,4.424)
line <- c(1,1,1,2,2,2)
k2 <- seq(1.5,5
Will I be able to do a prediction similar to above with random forest and
compare both the predict survival time result from AFT model and the
Survival Random forest model ?
Sincerely,
--
View this message in context:
http://r.789695.n4.nabble.com/Predict-in-glmnet-for-cox-family-tp4706070p470
Thank you for the correction and the code. I had just discovered the repeated
measure error myself yesterday :-). I had not thought of using a manova. This
may work better than what I was going to do. Thanks again.
- Original Message -
> From: "c06n [via R]"
> To: "Darcy Trimpe"
> Sen
It seems that installed.packages has changed behavior in 3.2.0.
We have a local package repository containing only binaries of packages (for
Windows).
Since 3.2.0, using install.packages for a package form such a repository does
not work any more.
The solution is to add the parameter type=“binar
Hi,
Did you ever get an answer about this? It has been so so frustrating for
me...
Thanks!
On Sunday, March 22, 2015 at 11:29:28 PM UTC-4, Vindoggy ! wrote:
>
> I'm using a mac with OSX Yosemite (10.10.2), running the latest version of
> R (3.1.3). But I've been having this same issue since
Thank you both.
I just wanted to point out that before assigning the order of colors in
vector col, one should check that it corresponds with how levels are
ordered in levels(mydata$Col3).
Best,
Pablo
2015-04-23 5:46 GMT+02:00 Richard M. Heiberger :
> Pablo,
>
> I would do it similarly. I woul
Buenas noches,
comedidamente me dirijo a ustedes para hacerles una consulta respecto a un
error que me ha salido al ejecutar R. Soy estudiante de Ingeniería y estoy
basando mi tesis en un estudio estadístico usando R Studio.
Estoy trabajando una base de datos con 12 variables y 1433 datos en cada
u
Hi
I am not sure if this is more efficient than some loop
I just gave your data another column names.
> names(x)<-c("one", "two")
> x
one two
1 1 a, b, c
2 2d, e
3 3 f
> s<-(strsplit(x$two, ","))
> s
[[1]]
[1] "a" " b" " c"
[[2]]
[1] "d" " e"
[[3]]
[1] "f"
> first<-rep
Hi Dimitri
here is a quick crude way (needs some polishing)
data.frame(a = rep(x$a,sapply(sapply(x$b, strsplit, ", "), length)), b=
unlist(sapply(x$b, strsplit, ", ")))
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mac...@n
Hi Luigi
Michael answered your question about printing
lattice and ggplot require their graphics to be in print()
If you have problems in printing you may have to use
trellis.device(device = pdf, # or what ever the actual device is
file = ,
Well. Your function results in error.
> f1<-function(model){
+ vfs<<-vif(model)
+ vfs
+ ex<<-subset(vfs,vfs>=10)
+ print(ex)
+ maxx<<-which.max(ex)
+ print(maxx)
+ mm<<-vector(mode = "numeric",length = 50)
+
+ mm<<-maxx
+ maxindex<<-which.max(ex)
+ print(maxindex)
+
+ }
> F1(model1)
Error: could n
In-line below
On 23/04/2015 14:01, Bos, Roger wrote:
Dear All,
I would like to learn the proper way to set the default time zone so I get the
correct date for my files. The code below is non-reproducible (sorry) because
it is based on a file on my system, but I hope someone will be able to h
On Thu, Apr 23, 2015 at 8:01 AM, Bos, Roger
wrote:
> Dear All,
>
> I would like to learn the proper way to set the default time zone so I get
> the correct date for my files. The code below is non-reproducible (sorry)
> because it is based on a file on my system, but I hope someone will be able
I suspect Luigi that if you wrap the call to xyplot in print( )
matters might be improved.
On 23/04/2015 13:50, Luigi Marongiu wrote:
Dear all,
with the most useful help of Duncan I updated a script to plot high
density data in the form of 384 squares containing tiny plots. The
function wo
Hello!
I have my data frame x with 2 character columns:
x <- data.frame(a = numeric(), b = I(list()))
x[1:3,"a"] = 1:3
x[[1, "b"]] <- "a, b, c"
x[[2, "b"]] <- "d, e"
x[[3, "b"]] <- "f"
x$a = as.character(x$a)
x$b = as.character(x$b)
x
str(x)
I need to produce this data frame:
1 a
1 b
1 c
2
Is there also a version for non parametric tests like:
pairwise.wilcox.test {stats}
Met vriendelijke groeten - With kind regards,
Joachim Audenaert
onderzoeker gewasbescherming - crop protection researcher
PCS | proefcentrum voor sierteelt - ornamental plant research
Schaessestraat 18, 90
Dear All,
I would like to learn the proper way to set the default time zone so I get the
correct date for my files. The code below is non-reproducible (sorry) because
it is based on a file on my system, but I hope someone will be able to help me
anyway.
I have a file that was last modified on
The function cld() in package multcomp generates compact letter displays, but
does not format them as exponents of the group names.
-
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
-Original Message-
From
Dear all,
with the most useful help of Duncan I updated a script to plot high
density data in the form of 384 squares containing tiny plots. The
function works and it is possible to create a pdf version of the
output. but when i try to make a function out of this script, the
resulting pdf file is e
Hello
Am 23.04.2015 um 09:57 schrieb Berend Hasselman:
On 23-04-2015, at 08:45, Sun Shine wrote:
Hi list
Recently, when starting up RStudio, the following warning is being displayed:
"Error in tools:::httpdPort <= 0L :
comparison (4) is possible only for atomic and list types"
I think tha
Hi samarvir,
Your attachment didn't make it through the list filter. From your
example, you seem to want something like this:
# assume you are using the readxl package to read the data in
mydf<-read_excel("mydata.xlsx",col_types=rep("character",11))
mydatavector<-as.vector(as.matrix(mydf))
This i
(Copied to maintainer)
I'm not going to say there's an error in such an established and respected
package but I think there's an inconsistency between the help text and the
example:
> ?rcorr
Value
The diagonals of n are the number of non-NAs for the single variable
corresponding to tha
Hello,
I am working with some 2700 files in .xlsx format
Like the one attached below
I want to transform all tabular data to a single row as shown below in
example or in attachment
so that all data can be used as a variable.
and replicate all to make a single csv file which has all the data
EXAM
In this case the horizontal lines of the errorbars go output the limits.
And are therefore not displayed. Use coord_cartesian(xlim = 0:1) instead of
setting the limits in scale_x_continuous().
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
te
Thanks Thierry. So if a variable x = a, and the limits for x are [a, a+b],
is that data point considered outside the limits?
Thanks,
Axel.
On Thu, Apr 23, 2015 at 6:17 AM, Thierry Onkelinx
wrote:
> The limits are more narrow than the data. ggplot2 treats data outside the
> limits as NA.
>
> ir.
The limits are more narrow than the data. ggplot2 treats data outside the
limits as NA.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belg
Hello,
I'm getting a warning message from the reproducible example below.
Why would geom_errorbar() remove 2 cases in this case? Both upper and lower
limits of the error bar contain var1 and are within the axis limits.
df <- data.frame(var1 = seq(0, 1, 0.1), var2 = seq(0, 1, 0.1))
df$ll <- ifel
Hello all,
It is often time consuming to interpret p-values of multiple pairwise
comparisons of groups and assign them a letter code for publication
purposes. So I found this interesting link to a program that does this for
you.
http://www.jerrydallal.com/lhsp/similar.htm
I was wondering if
> On 23-04-2015, at 08:45, Sun Shine wrote:
>
> Hi list
>
> Recently, when starting up RStudio, the following warning is being displayed:
>
> "Error in tools:::httpdPort <= 0L :
> comparison (4) is possible only for atomic and list types"
>
> I think that this is specific to RStudio because s
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