Regex [^a-zA-Z] reads as not a letter.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Hello,
I am not sure what you mean by a matrix. If you want to have a matrix, use the
function matrix, (matrix(c(dog,cat,tree),3))
but I have the feeling you really want a data frame as you are talking about
variables.
In that case simply use
mydataframe - data.frame(dog,cat,tree)
If you are
On 24/04/2015 01:22, billy am wrote:
Hi Everyone ,
Is there a place where I can download msi installer for latest version of
R?
I believe not: certainly not an official one. Consult the manual as to
how to build one if you really need one.
Thanks
Billy
[[alternative HTML
Dear fellow R-help members,
If my data is
MM DD HH
2015 04 24 01
2015 04 24 02
2015 04 24 06
Where
: year
MM:month
DD:day
HH: hour
How could I calculate the mean of the ISOdatetime(,MM,DD,HH,0,0) of
these?
Note: I set minutes and seconds to 0, as I don't have data for them.
On 24 April 2015 at 12:59, Achim Zeileis achim.zeil...@uibk.ac.at wrote:
On Fri, 24 Apr 2015, Jue Lin-Ye wrote:
Dear fellow R-help members,
If my data is
MM DD HH
2015 04 24 01
2015 04 24 02
2015 04 24 06
Where
: year
MM:month
DD:day
HH: hour
How could I calculate
Hola Sergio,
En principio las diferencias entre 32 y 64 bits están relacionadas con
cuánta RAM puede gestionar R.
Esto efectivamente puede afectar a tu problema por el nivel de profundidad
que el algoritmo simplex utilice hasta encontrar la solución y eso está
asociado con la RAM que puede
On Fri, 24 Apr 2015, Jue Lin-Ye wrote:
Dear fellow R-help members,
If my data is
MM DD HH
2015 04 24 01
2015 04 24 02
2015 04 24 06
Where
: year
MM:month
DD:day
HH: hour
How could I calculate the mean of the ISOdatetime(,MM,DD,HH,0,0) of
these?
With the mean() method? On
On 23/04/15 13:41, Albin Blaschka wrote:
Hello
Am 23.04.2015 um 09:57 schrieb Berend Hasselman:
On 23-04-2015, at 08:45, Sun Shine phaedr...@gmail.com wrote:
Hi list
Recently, when starting up RStudio, the following warning is being
displayed:
Error in tools:::httpdPort = 0L :
Hi Everyone ,
Is there a place where I can download msi installer for latest version of
R?
Thanks
Billy
[[alternative HTML version deleted]]
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On 24/04/15 10:41, Erin Hodgess wrote:
Hello!
I have a cbind type question, please: Suppose I have the following:
dog - 1:3
cat - 2:4
tree - 5:7
and a character vector
big.char - c(dog,cat,tree)
I want to end up with a matrix that is a cbind of dog, cat, and tree.
This is a toy example.
This seems like a recipe for garbage results to me, but there may be I
something you can set the error option to. See ?options.
---
Jeff NewmillerThe . . Go Live...
What are you expecting?
dog - 1:3
cat - 2:4
tree - 5:7
big.char - c(dog,cat,tree)
xx - cbind(dog, cat, tree, big.char)
gives me
xx1 - structure(c(1, 2, 3, 2, 3, 4, 5, 6, 7, dog,
cat, tree), .Dim = 3:4, .Dimnames = list(NULL, c(dog, cat,
tree, big.char)))
John Kane
Kingston ON Canada
Steve Taylor steve.tay...@aut.ac.nz
on Thu, 23 Apr 2015 23:32:00 + writes:
This works for me...
get0 = function(x) get(x,pos=1)
sapply(big.char, get0)
Note that get0() is a _ somewhat important for efficient code _
new function since R 3.2.0
so you'd rather call your
Hi Joachim,
This function allows the user to set some characters in a string to
superscript or subscript. If sup or sub are set to one or more numbers
corresponding to an index in the string, those letters will be placed
appropriately. I can't properly test this as there is some problem
with X11
Here is the big picture. I have a character vector with all of the names
of the variables in it.
I want to cbind all of the variables to create a matrix.
Doing 3 is straightforward, but many, not so much.
Hence my question.
Thanks so much for your answers!
Sincerely,
Erin
On Thu, Apr 23,
Is this what you're looking for?
dog - 1:3
bat - 2:4
tree - 5:7
big.char - c(dog,bat,tree)
do.call(cbind,lapply(big.char, get))
[,1] [,2] [,3]
[1,]125
[2,]236
[3,]347
On Thu, Apr 23, 2015 at 3:41 PM, Erin Hodgess erinm.hodg...@gmail.com wrote:
G'day Erin,
On Thu, 23 Apr 2015 20:51:18 -0400
Erin Hodgess erinm.hodg...@gmail.com wrote:
Here is the big picture. I have a character vector with all of the
names of the variables in it.
I want to cbind all of the variables to create a matrix.
Doing 3 is straightforward, but many, not
Buenos días,
He hecho un desarrollo en mi máquina (de 64 bits) y funciona
correctamente. Se trata de un problema de programación lineal (usando
lpSolve y lpSolveAPI). El problema viene al ejecutar un caso concreto
que en la máquina del usuario (de 32 bits) nos da que no hay solución
factible para
I am amazed at the number of rather obtuse misunderstandings of the
actual nature of Erin's question.
The suggestion that Erin should read the intro to R made me smile. Erin
is a long time and highly sophisticated user of R; she has no need to
read the intro. The person who made that
I wanted to increase the size of the font in R, but when I do, I get the error
message below. I've searched on Google, and the only thing I saw is about
changing the version of X11. I'm running the current version of X11, and
running OS X Yosemite 10.10.3. I'm using a Mac Desktop, 3.2 Ghz
try lm.ridge from MASS package.
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
On 04/24/2015 06:49 AM, Franckx Laurent wrote:
Dear all
I have bumped into the dreaded 'segfault' error type when running some C++
code using .Call().
segfaults often involve invalid memory access at the C level that are best
discovered via valgrind or similar rather than gctorture. A good
Hi All,
I am wondering how to save plots in R at CentOS when X11 is not available,
any suggestion would be appreciated.
Warm Regards
Sudip
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Have just checked with R 3.2.0 and MASS 7.3-40 and there still appears to
be a problem/strangeness at around k=2.5
On 23 April 2015 at 14:09, Francis Bursa francis.bu...@quantics.co.uk
wrote:
Dear all,
I believe I have found a bug in rlm in the MASS package. Specifically, the
scale
Hello Erin,
I think you have explain your goal more detailed. Maybe I am completely
lost but as far as I understand now you only need the command cbind:
m1 - cbind(dog, dat, tree)
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
But I can't imagine that is the solution
Bonjour, je suis un nouveau dans R. Je fais actuellement mon mémoire de
mastère et je voudrais appliquer le Package BCDating. Mail il se trouve que
je reçois toujours le message d'erreur suivant:
Erreur dans if (mat_tp[r, 1] n) mat_tp - rbind(mat_tp, c(n, 1 -
mat_tp[r, :
l'argument est de
Jeff Newmiller jdnewmil at dcn.davis.ca.us writes:
This seems like a recipe for garbage results to me, but there may be I
something you can set the error option
to. See ?options.
---
Jeff Newmiller
Hi,
Currently i am working with the lm() function for some regressions required
for my project.
suppose the formula parameter in that is given by response ~ terms,after
some testing i found out that when the number of observations under terms
is less than the number of columns or features
This is very off-topic here. My suggestion would be to do as the Posting Guide
says and ask this on R-devel, or perhaps even a gdb forum. From what little I
know, valgrind might help also.
---
Jeff Newmiller
You could do something tricky like
do.call(cbind, lapply(big.char, as.name))
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
but you are usually better off creating these things as part of a list
and passing that to do.call(cbind, list).
There is a slight danger
Dear all
I have bumped into the dreaded 'segfault' error type when running some C++ code
using .Call().
I have already undertaken several attempts to debug the C++ code with gdb(),
but until now I have been unable to pinpoint the origin of the problem. There
are two elements that I think are
You really really really need to work with a local statistical expert, as
your post indicates fundamental confusion. Furthermore, statistical issues
are off topic here.
Cheers,
Bert
On Friday, April 24, 2015, Praveen kr singh pcubesi...@gmail.com wrote:
Hi,
Currently i am working with the
Bonjour,
We need more information. See Reproducibility
http://adv-r.had.co.nz/Reproducibility.html for some suggestions on how to ask
a question.
John Kane
Kingston ON Canada
-Original Message-
From: mamadouns...@gmail.com
Sent: Fri, 24 Apr 2015 13:26:32 +0100
To:
Hi everybody,
I am trying to replicate the formula shown in the attachment. I want to
estimate tau using a macroeconomic variable X at month t using k lags of the
variable X.
My code so far looks as follows:
psi - fn(...)
k - 1:K
ltau - m + theta*sum(psi*X[t-k])
Unfortunately, if I run the
Geospatial image maps or just exif tags?
Search for r exif for several leads.
Cheers, Mike
On Sat, Apr 25, 2015, 08:48 Alejo C.S. alej@gmail.com wrote:
Hi all, I have several jpeg files with lat long information. I want to make
a lat long table whit this info. Anyone knows how to do it?
Hello, all:
I am new here, and have a challenge to present some graphical data to the
user in a convenient way.
The challenge is to present a map to the user which is coloured with the
value of a variable. Say for example, temperature. This is a preexisting graph
that I can generate
Hi all, I have several jpeg files with lat long information. I want to make
a lat long table whit this info. Anyone knows how to do it? Can't find
anything in google.
Thanks a lot in advance
A.
[[alternative HTML version deleted]]
__
That's a pretty vague question, but you might be able to do it with
functions from the raster package.
Followup on this topic should be to R-sig-geo.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 4/24/15, 3:46 PM,
Plot directly to the appropriate device, e.g.
pdf(file=my.pdf)
plot(rnorm(500))
dev.off()
This is often recommendable even if you do have an on-screen graphics device
because some subtleties can get lost in translation for one device to another.
(The prototypical example is that a legend box
Hello,
Please, read and follow the posting guide and provide a minimal
reproducible example as you are encouraged to do. Moreover, write to the
list in english.
Just a quick test : have you looked at your object 'mat_tp' :
str(mat_tp)
Bon courage,
François
Le 24/04/2015 14:26, Mamadou
Hola Jesús,
Si la otra persona usa RStudio, basta con reabrir el script con el encoding
que tú uses. Menú File/Open with re-enconding. Si vais a compartir más
ficheros, lo mejor es que cree un proyecto y establezca para ese proyecto
el encoding por defecto que tú uses.
Espero te sirva, un saludo,
Hi Peter,
I did the same but I received an error stating X11 is not available.
On Fri, Apr 24, 2015 at 8:11 PM, peter dalgaard pda...@gmail.com wrote:
Plot directly to the appropriate device, e.g.
pdf(file=my.pdf)
plot(rnorm(500))
dev.off()
This is often recommendable even if you do
Reproducibility
http://adv-r.had.co.nz/Reproducibility.html
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
John Kane
Kingston ON Canada
-Original Message-
From: mikeh...@y7mail.com
Sent: Wed, 22 Apr 2015 18:52:45 + (UTC)
To:
Hi Antonio,
If you do create the map in R, you can use locator().
Jim
On Sat, Apr 25, 2015 at 8:37 AM, Antonio Serrano via R-help
r-help@r-project.org wrote:
Hello, all:
I am new here, and have a challenge to present some graphical data to the
user in a convenient way.
The
Pues entonces no sé qué decir, porque no uso Mac y desconozco si el editor
de texto que trae permite hacer algo parecido a lo que hace RStudio.
Por si acaso es factible para ti, la operación inversa también la puedes
hacer desde RStudio (que supongo tú sí lo tienes instalado): File/Save with
Hi,
Thanks so much for the hints, I think I've cracked it! The key is to
create a dummy function, continue_on_error which gets run instead of
stop when an error occurs, then reference it
with options(error=continue_on_error). Here's an example:
==
continue_on_error -
R 3.2.0
OS X
Colleagues
I have a script that has been unchanged for years but I just noticed a
difference in the output. A minimal example is:
jpeg(file=xxx.jpeg, width=4, height=2, unit=in, pointsize=12,
bg=white, res=150, quality=100)
plot(1)
graphics.off()
Perhaps:
dog - 1:3
cat - 2:4
tree - 5:7
big.char - cbind(dog,cat,tree)
big.char
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
colnames(big.char)-c(dog,cat,tree)
big.char
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
Clint Bowman
Hi Erin,
Well, if I do this:
dog - 1:3
cat - 2:4
tree - 5:7
dct-cbind(dog,cat,tree)
I get this:
dct
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
If I assume that you want to include the character vector as well:
rownames(dct)-big.char
dct
Jim
On Fri, Apr 24, 2015
On Apr 23, 2015, at 5:41 PM, Erin Hodgess erinm.hodg...@gmail.com wrote:
Hello!
I have a cbind type question, please: Suppose I have the following:
dog - 1:3
cat - 2:4
tree - 5:7
and a character vector
big.char - c(dog,cat,tree)
I want to end up with a matrix that is a cbind of
This works for me...
get0 = function(x) get(x,pos=1)
sapply(big.char, get0)
The extra step seems necessary because without it, get() gets base::cat()
instead of cat.
cheers,
Steve
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Erin Hodgess
Sent:
These are great! Thank you!
On Thu, Apr 23, 2015 at 7:14 PM, William Dunlap wdun...@tibco.com wrote:
You could do something tricky like
do.call(cbind, lapply(big.char, as.name))
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
but you are usually better
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