1. Please do not post in HTML. This is a plain text list and it can get mangled.
2. Thank you for the example data and code. The problem is -- see the
Help for strip.custom() -- that strip.custom() wants a character
vector or expression for the factor.levels argument. But...
> str(dist.names)
F
n163 <- mpfr(163, 500)
is how I set up the number.
JN
On 15-07-04 05:10 PM, Ravi Varadhan wrote:
>> What about numeric constants, like `163'?
>>
>> eval(Pre(exp(sqrt(163)*pi), 120))does not work.
>>
>> Thanks,
>> Ravi
>>
>> From: David Winsemius
I would like to use a mapping to name panel strips. Directly using mapping
table does not work. What is the problem here?
my.df <- data.frame(x = rnorm(100, mean = 0, sd = 2), name = "A")
my.df <- rbind(my.df, data.frame(x = rnorm(100, mean = 0, sd = 4), name = "B"))
my.df <- rbind(my.df, data.f
What about numeric constants, like `163'?
eval(Pre(exp(sqrt(163)*pi), 120))does not work.
Thanks,
Ravi
From: David Winsemius
Sent: Saturday, July 4, 2015 1:12 PM
To: Duncan Murdoch
Cc: r-help; John Nash; Ravi Varadhan
Subject: Re: [R] : Ramanujan a
On 05/07/15 01:09, mxkuhn wrote:
Whenever I find a new rule or test with R CMD check, I tell myself
that it must be there because of some previous issue, i.e. they
probably had a good reason. I can't imagine what damage an incomplete
sentence caused beyond a bruised aura.
Fortune nomination
> On Jul 4, 2015, at 3:09 AM, Alex Kim wrote:
>
> Hi guys,
>
> Suppose I have an extremely large data frame with 2 columns and .5 mil
> rows. For example, the last 6 rows may look like this:
> .
> ..
> ...
> 89 100
> 93 120
> 95 125
> 101NA
> 115NA
> 123
> On Jul 4, 2015, at 12:20 AM, Duncan Murdoch wrote:
>
> On 04/07/2015 8:21 AM, David Winsemius wrote:
>>
>>> On Jul 3, 2015, at 11:05 PM, Duncan Murdoch
>>> wrote:
>>>
>>> On 04/07/2015 3:45 AM, David Winsemius wrote:
> On Jul 3, 2015, at 5:08 PM, David Winsemius
> wrote:
>>
You can do that with bc if you pass the entire expression to bc(...) in
quotes but in that case you will have to use bc notation, not R notation
so, for example, exp is e and atan is a.
> library(bc)
> bc("e(sqrt(163)*4*a(1))")
[1]
"262537412640768743.2500725971981856888793538563373369
Hi guys,
Suppose I have an extremely large data frame with 2 columns and .5 mil
rows. For example, the last 6 rows may look like this:
.
..
...
89 100
93 120
95 125
101NA
115NA
123NA
124NA
I would like to manipulate this data frame to output
I encountered this a few months ago and, in my case, the sentence had a noun
and verb but lacked a period at the end of the sentence. I tested that 'blah
blah blah.' would have passed in that version of R-devel.
Whenever I find a new rule or test with R CMD check, I tell myself that it must
be
I am trying to download data from here:
www.bls.gov/emp/ep_table_109.htm
I have tried using some packages (such as gdata, xlsx, XLConnext, and r2excell)
that read xls files and all failed. The error is related to the file format or
the presence of active batons in the header. Reading the file fro
Hi guys,
Suppose I have an extremely large data frame with 2 columns and .5 mil
rows. For example, the last 6 rows may look like this:
.
..
...
89 100
93 120
95 125
101NA
115NA
123NA
124NA
I would like to manipulate this data frame to output
Hi guys,
Suppose I have an extremely large data frame with 2 columns and .5 mil
rows. For example, the last 6 rows may look like this:
.
..
...
89 100
93 120
95 125
101NA
115NA
123NA
124NA
I would like to manipulate this data frame to output
On Sat, 4 Jul 2015, Duncan Mackay wrote:
Just a thought
Have you set pch colour values somewhere else?
Duncan,
Not on purpose.
see also https://stat.ethz.ch/pipermail/r-help/2010-March/230329.html
Will do.
Thanks,
Rich
__
R-help@r-project
Well 'list' in R is pretty naturally the same as R's 'atomic vector' in
scads of languages. In R the term needs special care since it's still a
'vector'.
'Degenerate dimension' is probably a helpful phrase for understanding what
is happening here.
Cheers, Mike
On Saturday, July 4, 2015, Rolf Tur
Hi ulasim77,
At a guess, what you want is to move the legend from beneath the plot
to the right side. As none of the examples from the "plotTime"
function seem to work, I'll have to use something simpler:
par(mar=c(5,4,4,8))
plot(1:5)
legend(5.4,3.2,c("First","Second","Third"),lty=1:3,col=1:3,pch=
On 04/07/2015 8:21 AM, David Winsemius wrote:
>
>> On Jul 3, 2015, at 11:05 PM, Duncan Murdoch wrote:
>>
>> On 04/07/2015 3:45 AM, David Winsemius wrote:
>>>
On Jul 3, 2015, at 5:08 PM, David Winsemius wrote:
It doesn’t appear to me that mpfr was ever designed to handle
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