Re: [R] Pb with date time sequence with period<1sec

Plus, current dates are an awful lot of seconds since 1970-01-01, so the relative error on second-scale differences is bigger than you might think: > as.numeric(Sys.time()) [1] 1441874878 and since relative representation errors are of the order 1e-16, the corresponding absolute errors are

[R] Counting occurrences of a set of values

Can anyone suggest a way of counting how frequently sets of values occurs in a data frame? Like table() only with sets. So for a dataset: V1, V2, V3 1, 2, 1 1, 3, 2 1, 2, 1 1, 1, 1 The output would be something like: 1,2,1: 2 1,3,2: 1 1,1,1: 1 Thank you, Thomas Chesney This message and

Re: [R] Counting occurrences of a set of values

On 10/09/2015 9:11 AM, Thomas Chesney wrote: > Can anyone suggest a way of counting how frequently sets of values occurs in > a data frame? Like table() only with sets. Do you want 1,2,1 to be the same as 1,1,2, or different? What about 1,2,2? For sets, those are all the same, but for most

Re: [R] Counting occurrences of a set of values

Have a look at the dplyr package library(dplyr) n <- 1000 data_frame( V1 = sample(0:1, n, replace = TRUE), V2 = sample(0:1, n, replace = TRUE), V3 = sample(0:1, n, replace = TRUE) ) %>% group_by(V1, V2, V3) %>% mutate( Freq = n() ) ir. Thierry Onkelinx Instituut voor natuur- en

Re: [R] Counting occurrences of a set of values

Dear Thomas, How about this? > table(apply(Data, 1, paste, collapse=",")) 1,1,1 1,2,1 1,3,2 1 2 1 I hope this helps, John > -Original Message- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Thomas > Chesney > Sent: September 10, 2015 9:11 AM > To:

[R] how to split row elements [1] and [2] of a string variable A via srtsplit and sapply

Hi, I have a data.frame x1, of which a variable A needs to be split by element 1 and element 2 where separator is ":". Sometimes could be three elements in A, but I do not need the third element. Since R does not have a SCAN function as in SAS, C=scan(A,1,":"); D=scan(A,2,":"); I am using a

Re: [R] Counting occurrences of a set of values

df <- data.frame( V1= 1, V2= c( 2, 3, 2, 1), V3= c( 1, 2, 1, 1)) dfO <- df[ do.call( order, df), ] dfOD <- duplicated( dfO) dfODTrigger <- ! c( dfOD[-1], FALSE) dfOCounts <- diff( c( 0, which( dfODTrigger))) cbind( dfO[ dfODTrigger, ], dfOCounts) V1 V2 V3 dfOCounts 4 1 1 1 1 3 1

Re: [R] how to split row elements [1] and [2] of a string variable A via srtsplit and sapply

try this: > x <- read.table(text = "A B + 1:29439275 0.46773514 + 5:85928892 0.81283052 + 10:128341232 0.09332543 + 1:106024283:ID 0.36307805 + 3:62707519 0.42657952 + 2:80464120 0.89125094", header = TRUE, as.is = TRUE) > > temp <- strsplit(x$A, ":") > x$C <- sapply(temp, '[[',

[R] r function idea: minimize() to turn reproducible_example.R into minimal_reproducible_example.R

just going to throw this idea out there in case it's something that anyone wants to pursue: if i have an R script and i'm hitting some unexpected behavior, there should be some way to remove extraneous objects and manipulations that never touch the line that i'm trying to reproduce. automatically

Re: [R] how to split row elements [1] and [2] of a string variable A via srtsplit and sapply

... Alternatively, you can avoid the looping (i.e. sapply) altogether by: do.call(rbind,strsplit(x[[1]],":"))[,-3] [,1] [,2] [1,] "1" "29439275" [2,] "5" "85928892" [3,] "10" "128341232" [4,] "1" "106024283" [5,] "3" "62707519" [6,] "2" "80464120" These can then be added to the

Re: [R] [FORGED] Re: Help with Binning Data

On Fri, 11 Sep 2015, Rolf Turner wrote: On 11/09/15 11:57, David Winsemius wrote: The urge to imitate other statistical package that rely on profusion of dummies should be resisted. R repression functions can handle factor variables Fortune? :-) Nice! Should I include the

[R] Help with Binning Data

Dear all, I have 3-hourly temperature data from 1970-2010 for 122 cities in the US. I would like to bin this data by city-year-week. My idea is if the temperature for a particular city in a given week falls within a given range (-17.78 & -12.22), (-12.22 & -6.67), ... (37.78 & 43.33), then the

Re: [R] Help with Binning Data

On Sep 10, 2015, at 3:28 PM, Shouro Dasgupta wrote: > Dear all, > > I have 3-hourly temperature data from 1970-2010 for 122 cities in the US. I > would like to bin this data by city-year-week. My idea is if the > temperature for a particular city in a given week falls within a given > range

Re: [R] [FORGED] Re: Help with Binning Data

On 11/09/15 11:57, David Winsemius wrote: The urge to imitate other statistical package that rely on profusion of dummies should be resisted. R repression functions can handle factor variables Fortune? :-) cheers, Rolf -- Technical Editor ANZJS Department of Statistics University

Re: [R] Help with Binning Data

1. Posting in HTML largely negated your ability to provide data through dput(). Folow he posting guide and post in PLAIN TEXT only, please. 2. See ?cut . I think this will at least get you started. Cheers, Bert Bert Gunter "Data is not information. Information is not knowledge. And knowledge

Re: [R] help with svychisq

could you try this, and then not use factor(age) elsewhere? sv1 <- update( sv1 , age = factor( age ) ) if that doesn't work, is it possible for you to share a reproducible example? thanks On Thu, Sep 10, 2015 at 4:51 PM, Emanuele Mazzola wrote: > Hello, > > I’m

Re: [R] Generate a vector of values, given a vector of keys and a table?

?match as in: > y <- lk_up[match(x,lk_up[,"key"]),"val"] > y [1] "1" "1" "1" "1" "15000" "15000" "2" [8] "2" "2" "2" Bert Bert Gunter "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom." -- Clifford Stoll On

Re: [R] [FORGED] Re: Help with Binning Data

On 11/09/15 12:25, Achim Zeileis wrote: On Fri, 11 Sep 2015, Rolf Turner wrote: On 11/09/15 11:57, David Winsemius wrote: The urge to imitate other statistical package that rely on profusion of dummies should be resisted. R repression functions can handle factor variables Fortune?

Re: [R] [FORGED] Help with Binning Data

On Sep 10, 2015, at 5:25 PM, Achim Zeileis wrote: > On Fri, 11 Sep 2015, Rolf Turner wrote: > >> On 11/09/15 11:57, David Winsemius wrote: >> >> >> >>> The urge to imitate other statistical package that rely on profusion >>> of dummies should be resisted. R repression functions can handle

[R] Generate a vector of values, given a vector of keys and a table?

I apologize in advance: I must be overlooking something quite simple, but I'm failing to make progress. Suppose I have a "lookup table": Browse[2]> dput(lk_up) structure(c("1.1", "1.9", "1.4", "1.5", "1.15", "1", "1", "15000", "2", "25000"), .Dim = c(5L, 2L), .Dimnames = list(

Re: [R] ggplot2 will not install after system upgrade

This is most likely the "stringi" dependency, which is new. Follow the links from the CRAN page for "stringi" and you may find some guidance. I initially had the same problem with my Mageia install, but it's sorted now. On 3 September 2015 at 22:53, Jeff Trefftzs wrote: >

[R] help with svychisq

Hello, I’m having a weird issue with the function “svychisq” in package “survey", which would be very helpful for me in this case. I’m tabulating age categories (a factor variable subdivided into 4 categories: [18,25), [25, 45), [45,65), [65, 85) ) with respect to ethnicity/race (another

[R] kendall tau distance

Dear group how to calculate  kendall tau distance according to  Kendall_tau_distance at wikipedia  httpsen.wikipedia.orgwikiKendall_tau_distance   thanks in advance Ragia __ R-help@r-project.org mailing list -- To