Pero como har�a el data frame?? Porque las cuchillas son de la misma
referencia. En realidad es para ver cada cuanto se gstan las cuchillas y ver
que pedidos hay que hacer de las mismas.
La tabla que tengo es:
25 enero-> 1 cuchilla gastada
30 enero -> 1 cuchilla gastada
3 de febrero -> 2
Hi John,
Please keep r-help copied on the reply.
What's the 'previous model'? How do you get estimates within subgroups that
'includes the overall effect'? I really cannot follow you here.
Best,
Wolfgang
--
Wolfgang Viechtbauer, Ph.D., Statistician | Department of Psychiatry and
Hi Mario,
It is at the limit of my skills so I'm not sure this will be a real
solution. But it might help you anyway (and there will be more competent
people anyway).
What does not make sense to me is why you set the names of your files
and then use them to list them with list.files()
What
Hello everyone,
So, rookie me is trying to write a smart code, so here's what I'm doing:
I have a list of a couple of hundrend files, some of which refer to different
experiments.
The naming of the file refers to the experiment and the serial number to the
topological reference on my sample.
Hi Dr. Viechtbauer,
The code provided in the metafor projects website for subgroup includes
fitting a random effects model on the entire dataset and fitting a random
effects model within subgroups. When I exactly follow this code, my
estimates and confidence intervals for estimate within each
I am using R 3.2.2 on win-7
while using predict function with e1071 (naive bayes classifier)
I am getting the following error
"Error in object$tables[[v]][, nd] : subscript out of bounds"
pl help.
regards
Parth
__
R-help@r-project.org mailing list --
The first and second argument of forest() (or more precisely, forest.default())
are for the estimates and the corresponding sampling variances, respectively.
So, if you do forest(rr, se, ...), then the function will interpret the
standard errors as if they are variances. So, you should do
Suppose I have something like the following dataframe:
samp1 <- c(60,50,20,90)
samp2 <- c(60,60,90,58)
samp3 <- c(25,65,65,90)
test <- data.frame(samp1,samp2,samp3)
I want to calculate column means. Easy enough, if I want to use all the
data within each column:
print(colMeans(test),na.rm =
There is a bug in your code: it is not
> for (i in 1:ncol(test)) { test2[which.min(test[,i]),i]==NA}
but
for (i in 1:ncos(test)) {
test2[which.min(test[, i]), i] <- NA
}
Otherwise, a solution would be to create your own function to compute the mean
of a vector without the smallest value:
First, your code has flaws in the assignment of NA and in passing na.rm=TRUE to
colMeans().
It should be:
test2 <- test
for (i in 1:ncol(test)) { test2[which.min(test[,i]),i]=NA}
print(test2)
samp1 samp2 samp3
16060NA
2506065
3NA9065
490NA90
The which.min() only gets the first minimum value. If two or more values are
tied for the minimum, it will delete only the first one. This would get them
all:
> apply(test, 2, function(x) mean(x[-which(x == min(x))]))
samp1samp2samp3
66.7 70.0 73.3
Hi all,
When trying to load the drc package. I got the following error. Any
suggestions?
Thanks.
Hanna
> install.packages("drc", dependencies=TRUE)
--- Please select a CRAN mirror for use in this session ---
trying URL 'https://cran.fhcrc.org/bin/windows/contrib/3.1/drc_2.5-12.zip'
On 09/12/15 08:32, li li wrote:
Hi all,
When trying to load the drc package. I got the following error. Any
suggestions?
Yes. Read the error message
cheers,
Rolf Turner
Thanks.
Hanna
install.packages("drc", dependencies=TRUE)
--- Please select a CRAN mirror for use in this
Thanks.
2015-12-08 15:20 GMT-05:00 Rolf Turner :
>
> Please keep communications on-list. Others may have relevant comments and
> suggestions to make.
>
>
> On 09/12/15 09:00, li li wrote:
>
>> Thanks for the reply. So a newer version of R can solve the problem? But
>> I
Please keep communications on-list. Others may have relevant comments
and suggestions to make.
On 09/12/15 09:00, li li wrote:
Thanks for the reply. So a newer version of R can solve the problem? But
I was able to successfully load the package yesterday.
Thanks.
I have no access to your
Sarah:
Note that (as I read them) aggregate() and by() work differently on
data frames. aggregate() computes FUN column by column while by()
feeds the whole (subset) data frame to FUN.
If I am wrong about this, I would greatly appreciate being corrected.
Cheers,
Bert
Bert Gunter
"Data is
by() calls FUN with a data.frame as the argument. summary(), sum(), etc.
have methods that work on data.frames but sd() and mean() do not.
aggregate() calls its FUN with each column of a data.frame as the argument.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Dec 8, 2015 at 3:08 PM,
hello all,
I intend transfer a big data.frame, more than 1e4 rows, more than 100
columns...
I found solutions (in internet and help pages) for small data.frame like
the showed bellow.
Big data.frames is very expensive in computation time in my approach
I would like to optimize this transfer
Are you sure this is the right way to go for your use case? Even if you got a
quick solution to display an 1e4 x 100 table in TkTable, what is the purpose of
it? Will the user browse the whole dataset that way? Even if the answer is yes,
you would probably need to implement sorting and
Got it - thank you, everybody!
by splits it into data frames.
Lesson: use aggregate.
On Tue, Dec 8, 2015 at 6:17 PM, William Dunlap wrote:
> by() calls FUN with a data.frame as the argument. summary(), sum(), etc.
> have methods that work on data.frames but sd() and mean() do
Hi Cleber,
have you tried:
edit(mtcars)
Jim
On Wed, Dec 9, 2015 at 1:04 PM, Cleber N.Borges wrote:
> my objective is to show data in screen inside a tktable...
> for that, the data must be in a TCL variable and not only in a R variable
> like that:
>
> library( tcltk )
Hello!
Could you please explain why the first 5 lines work but the last 2 lines don't?
Thank you!
by(data = iris[myvars], INDICES = iris["Species"], FUN = summary)
by(data = iris[myvars], INDICES = iris["Species"], FUN = sum)
by(data = iris[myvars], INDICES = iris["Species"], FUN = var)
by(data =
Define: "transfer"
( save/load should be efficient and fast within R, but you appear to
have something else in mind. What?)
Apologies if it's obvious and I just don't get it.
Cheers,
Bert
Bert Gunter
"Data is not information. Information is not knowledge. And knowledge
is certainly not
Hi Dimitri,
I changed this into a reproducible example (we don't know what myvars
is). Assuming length(myvars) > 1, I'm not convinced that your first
five lines "work" either: what do you expect?
I get:
> by(data = iris[, -5], INDICES = iris["Species"], FUN = min)
Species: setosa
[1] 0.1
Sorry, I omitted the first line:
myvars <- c("Sepal.Length", "Sepal.Width")
by(data = iris[myvars], INDICES = iris["Species"], FUN = summary)
by(data = iris[myvars], INDICES = iris["Species"], FUN = sum)
by(data = iris[myvars], INDICES = iris["Species"], FUN = var)
by(data = iris[myvars], INDICES
my objective is to show data in screen inside a tktable...
for that, the data must be in a TCL variable and not only in a R variable
like that:
library( tcltk )
mtcars_in_TCL <- tclArray()
for( i in 1:5 ) for( j in 1:5 ) mtcars_in_TCL[[ i,j ]] <-
as.matrix(mtcars)[ i,j ]
i thank by attention
Hi Freddy,
Have you tried rev() on the palette?
Jim
On Wed, Dec 9, 2015 at 7:32 AM, Freddy Eggleton
wrote:
> Hi,
>
> I am trying to plot Conservative Vote % per borough for London using tmap
> however the legend colours boroughs with a high Conservative % as light
Because you are using by() incorrectly.
"A data frame is split by row into **data frames** subsetted by the
values of one or more factors, and function FUN is applied to each
subset in turn."
So your FUN is applied to a subset of the data frame (which is also a
list). Note that sum, min, and
Hi all,
When plotting the dose response curve using plot function as in the
example codes below, the scale of the axis should really be on the log
scale of the dose given the shape of the graph. But as you can see, the
tickmarks of the returned graph represent the original scale. How can I
Thanks for the reply but that does not seem to work. With that the plot is
on log scale for both the response and the dose levels, but the tickmarks
are still on the original scale.
2015-12-08 22:22 GMT-05:00 Jim Lemon :
> Hi Hannah,
> Try this:
>
> plot(mod,
Hi Hannah,
Try this:
plot(mod, type="all",log="xy")
Jim
On Wed, Dec 9, 2015 at 1:57 PM, li li wrote:
> Hi all,
> When plotting the dose response curve using plot function as in the
> example codes below, the scale of the axis should really be on the log
> scale of the
Hi Partha,
Probably the first thing to be done is to see what:
object$tables
really is. The error message tells you that either "v" has become larger
than the number of elements in the list/data frame "tables" or that "nd"
has become larger than the number of columns in the element "v" (or
Hi,
I am trying to plot Conservative Vote % per borough for London using tmap
however the legend colours boroughs with a high Conservative % as light blue
and boroughs with a low % of conservative votes as dark blue. How do i reverse
this scale so that areas with the most Conservative votes
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