Anindya Sankar Dey wrote/hat geschrieben on/am 30.12.2015 07:35:
Hi All,
The fmsb package has a function called Variance Inflation Factor and it
states the definition of the function as follows:-
"To evaluate multicolinearity of multiple regression model, calculating the
variance inflation
Shivi,
It looks like you have copied and pasted with errors. When you use dput() on a
dataframe, it will output a list (see example that follows). I think you have
cut off the beginning of the output and have manually added the assignment
“ab<-“. Also it is clear that the read.csv is
Dear All:
I need helps with creating histograms for data that include left censored
observations.
Here is an example of left censored data
*Sulfate.Concentration*
I am trying to generate a confidence interval for the statistic arpt (at
risk of poverty threshold generated with the package leaken) using the
package boot.
This is my temptative script (where XH090 and DB030 and w are variables
of an attached dataframe):
> arpt.boot <- function(data,i){
> d
Try
d= data[ ,i]
instead of d= data[i]
in your function. If that doesn't help, I think we would have to know
more about the structure of your data.
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley
Hi Duncan,
Please find the dput from the data.
ab<-read.csv("collection_last.csv",header=TRUE)
y<-ab[1:10,]
ab<- "2,458", "2,461", "2,462", "2,463", "2,464", "2,465", "2,468",
"2,469", "2,470", "2,473", "2,474", "2,475", "2,476", "2,477",
"2,478", "2,479", "2,480", "2,483", "2,484,267",
Hi all,
In help(unname), for the "force" argument, it states that
"if true, the dimnames (names and row names) are removed even from
data.frames."
However, when I use unname() to remove all the names from mtcars, it fails.
> unname(mtcars, force = TRUE)
Error in
> On Dec 30, 2015, at 11:26 PM, SHIVI BHATIA
> wrote:
>
> Hi Duncan,
> Please find the dput from the data.
>
> ab<-read.csv("collection_last.csv",header=TRUE)
> y<-ab[1:10,]
>
This is (possibly) partial output from a dput call. Unable to repair at any
rate.
>
> On Dec 31, 2015, at 1:12 PM, David Winsemius wrote:
>
>>
>> On Dec 31, 2015, at 11:16 AM, Abram Wooten via R-help
>> wrote:
>>
>> Hello,
>>
>> I am new to R and I am having trouble adding an exponent to my problem. For
>> instance,
>>> mat5
A <- matrix(c(1,2,3,4),2,2)
B <- matrix(A, nrow=14, ncol=14)
> B
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14]
[1,]131313131 3 1 3 1 3
[2,]242424242 4 2 4
Hello,
I am new to R and I am having trouble adding an exponent to my problem. For
instance,
> mat5 <-matrix(c(0.5,0.5,0.25,0.75),2,byrow=T)
> mat6 <-matrix(c(0.5,0.5,0.25,0.75),2,byrow=T)
> mat5%^%2
Error: could not find function "%^%"
I unsure on weather I should square mat5 or use the two
> On Dec 31, 2015, at 12:28 PM, Kathryn Lord wrote:
>
> Dear R users,
>
> Suppose that I have a matrix A
>
> A <- matrix(c(1,2,3,4),2,2)
>> A
> [,1] [,2]
> [1,]13
> [2,]24
>
> With this matrix A, I'd like to create bigger one, for example,
>
>
On 31/12/15 23:20, Steven Stoline wrote:
Dear All:
I need helps with creating histograms for data that include left
censored observations.
Here is an example of left censored data
*Sulfate.Concentration*
<-matrix(c(1450,1800,1840,1820,1860,1780,1760,1800,1900,1770,1790,
Well, all of the solutions proposed are a bit tricky in that the
matrix must be "constructed" by hand. They are also reinventing
wheels. What I think you really want is the kronecker product, which
is the matrix operation that does exactly what you want. e.g.
A <- matrix(1:4, nr=2)
to create a
Hi Steve,
Maybe something like this:
Sconc<-matrix(c(1450,1800,1840,1820,1860,1780,1760,1800,1900,
1770,1790,1780,1850,1760,1450,1710,1575,1475,1780,1790,
1780,1450,1790,1800,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,1,0,0),
24,2)
hist(Sconc[,1],breaks=c(1450,1550,1650,1750,1900))
Dear group
I have a script that prints data frames and plot using ggplot 2 while running,
how can I do this
thanks in advance
Ragia
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
Does what? You said you already have a script.
**If** you want to program it as a function, then I suggest that you
do some homework and go through an R tutorial, e.g. the "Intro to R"
that ships with R or one of the many available on the web.
If that is not what you mean, then clarify.
Cheers,
> On Dec 31, 2015, at 11:16 AM, Abram Wooten via R-help
> wrote:
>
> Hello,
>
> I am new to R and I am having trouble adding an exponent to my problem. For
> instance,
>> mat5 <-matrix(c(0.5,0.5,0.25,0.75),2,byrow=T)
>> mat6 <-matrix(c(0.5,0.5,0.25,0.75),2,byrow=T)
>>
Dear R users,
Suppose that I have a matrix A
A <- matrix(c(1,2,3,4),2,2)
> A
[,1] [,2]
[1,]13
[2,]24
With this matrix A, I'd like to create bigger one, for example,
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13]
[,14]
[1,]1313
Something like:
A <- matrix(c(1,2,3,4),2,2)
A
B <- matrix(rep(A, 4), nrow=2)
B
C <- do.call(rbind, lapply(1:8, function(x) B))
C
On Thu, Dec 31, 2015 at 12:28 PM, Kathryn Lord
wrote:
> Dear R users,
>
> Suppose that I have a matrix A
>
> A <-
Hi Ragia,
I may be missing your point, but try the "htmlize" function in the prettyR
package. This creates an HTML file containing both the text output and
images from an R script.
Jim
On Fri, Jan 1, 2016 at 11:46 AM, Ragia Ibrahim wrote:
> Dear group
> I have a script
Cordial orario aún no han Saludo a todos y un feliz próximo año para quienes
por horario aún no han cambiado de año.
una pregúntica, alguien me puede informar si existe un modo de colocar espacio
entre dos columnas en un data.frame?
gracias de antemano.
un abrazo
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