Re: [R] Arcsine Tranformation.

Dear Samsad, The usual use of the arcsine transformation for proportions is arcsine-squareroot. Thus, in R, for proportions in p, you can use asin(sqrt(p)). You could have found the asin() function yourself in several ways, including help.search("arcsin"), which turns up the help page for

Re: [R] Has R recently made performance improvements in accumulation?

Thierry: thanks much for your feedback, and apologies for this tardy response. You pointed me in the right direction. I did not appreciate how even if the algorithm ultimately has O(n^2) behavior, it can take a big n to overcome large coefficents on lower order terms (e.g. the O(1) and O(n)

Re: [R] Help in plotting

> On Jul 31, 2016, at 8:07 AM, Bhaskar Mitra wrote: > > Hello Everyone, > > > I have a data frame with 2 columns as shown at the end of this mail. I want > to plot the data in column A; > however I want the data-points in column A to be of different color based >

Re: [R] Arcsine Tranformation.

On Sun, 31 Jul 2016, Samsad Afrin Himi wrote: Dear R-Team, How can I do arcsine tzransformation in R? My data is proportional score. ?asin Could you please help me out? This is such a simple task that it is difficult to tell what very basic aspects of R you need help with. If you don't

[R] Help in plotting

Hello Everyone, I have a data frame with 2 columns as shown at the end of this mail. I want to plot the data in column A; however I want the data-points in column A to be of different color based on conditions in column B. i.e all data in column A corresponding to value 0 in column B should be

[R] Arcsine Tranformation.

Dear R-Team, How can I do arcsine tzransformation in R? My data is proportional score. Could you please help me out? Best, Samsad [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see

Re: [R] lapply

> On Jul 30, 2016, at 7:53 PM, roslinazairimah zakaria > wrote: > > Dear r-users, > > I would like to use lapply for the following task: > > ## Kolmogorov-Smirnov > ks.test(stn_all[,1][stn_all[,1] > 0],stn_all_gen[,1][stn_all_gen[,1] > 0]) >

Re: [R] cpquery problem

Hi Marco Thanks for your prompt reply. First, I have been using the parse(eval()) convention because I saw it used in some example code for running cpquery, but am happy to drop this practice. I have tried running the cpquery in the debug mode, and found that it typically returns the following

Re: [R] Aggregate matrix in a 2 by 2 manor

Hi Jeff, many thanks, that one is the Speedy Gonzalles out of all. Can also do some FUN stuff. aggregate.nx.ny.array.aperm <- function( dta, nx = 2, ny = 2, FUN=colMeans, ... ) { # number of rows in result nnr <- nrow( dta ) %/% ny # number of columns in result nnc <- ncol( dta ) %/% nx #

Re: [R] Replace any values in a data frame based on another data frame

Your use of HTML email corrupted your example slightly, but I was able to fix it. Please follow the Posting Guide and set your emails to Plain Text mode when posting to this mailing list in the future. Here is one way: # you have to be careful about mucking with factors # convert columns to

Re: [R] Replace any values in a data frame based on another data frame

Marine: Thanks for the reproducible example. I would not have fooled with this otherwise! 1. First note that your specification that you wish to replace only those values in col3 and col4 of df1 that don't match with those of df2 is irrelevant: if you replace those that do match you don't change

Re: [R] Aggregate matrix in a 2 by 2 manor

If you don't need all that FUN flexibility, you can get this done way faster with the aperm and colMeans functions: tst <- matrix( seq.int( 1440 * 360 ) , ncol = 1440 , nrow = 360 ) tst.small <- matrix( seq.int( 8 * 4 ) , ncol = 8