On 16/10/16 12:10, Rich Shepard wrote:
On Sat, 15 Oct 2016, David Winsemius wrote:
I am not the one to answer the windoze question but my Mac (being less
sensible than Rolf) also pops up a help window when queried with
?xyplot()
David,
Well, on my Slackware system writing in emacs with ESS
I would like to print a barchart without labels for categorical variables.
What change should be made to below command?
Thanks,
Naresh
boy.age <- data.frame(name = c("alpha", "beta", "charlie", "gerald"), age =
c(7, 9, 6, 5))
boy.age$name <- with(boy.age, reorder(name, age))
# draws with nam
On Sat, 15 Oct 2016, David Winsemius wrote:
I am not the one to answer the windoze question but my Mac (being less
sensible than Rolf) also pops up a help window when queried with ?xyplot()
David,
Well, on my Slackware system writing in emacs with ESS ?read.csv()
produces the error message
On Sun, 16 Oct 2016, Rolf Turner wrote:
Presumably you are running (yeuccch) Windoze,
Rolf,
Not since mid-1997. Slackware-14.1 on this host.
Rich
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> On Oct 15, 2016, at 3:48 PM, Rolf Turner wrote:
>
> On 16/10/16 11:28, Rich Shepard wrote:
>> On Fri, 14 Oct 2016, Rich Shepard wrote:
>>
So typing ?xyplot at the console doesn't bring up a help page? That
would
imply that you need to reinstall R.
>>
>>> Will rebuild and re-in
On 16/10/16 11:28, Rich Shepard wrote:
On Fri, 14 Oct 2016, Rich Shepard wrote:
So typing ?xyplot at the console doesn't bring up a help page? That
would
imply that you need to reinstall R.
Will rebuild and re-install tomorrow morning.
Sigh. User error. I entered the string as a functio
On Fri, 14 Oct 2016, Rich Shepard wrote:
So typing ?xyplot at the console doesn't bring up a help page? That would
imply that you need to reinstall R.
Will rebuild and re-install tomorrow morning.
Sigh. User error. I entered the string as a function, e.g., ?xyplot()
rather than by its na
> On Oct 15, 2016, at 3:37 AM, Ahmad Nursalim wrote:
>
> I have the problem use R
>
> Error in solve.default(object$hessian)
>
> system is computationally singular: reciprocal condition number = 1.42892e-30
>
>
> what is the problem ?and what it means
> help me
You should learn to help your
No, you need to specify the inputs corresponding to the next value in order to
obtain a production for that point. Read ?predict.lm or whatever function is
appropriate for your model about the newdata argument.
--
Sent from my phone. Please excuse my brevity.
On October 15, 2016 8:24:35 AM PDT
On 16/10/16 04:24, mviljamaa wrote:
My conception of prediction intervals is the following:
"a prediction interval gives an interval within which we expect next y_i
to lie with a specified probability"
So when using predict() for my model:
predict(fit4, interval="prediction")[1:20,]
I get:
Thank you David Wolfskill, David Winsemius, and Gabor! All very
helpful and interesting fixes for the problem (compiled below)! Now I
will see which one works best on the 944 rows that each have a cell of
smooshed attributes...the attribute names should be the same in all
the rows, if there is any
I forgot to add that if you have less than 16GB of memory, then you
were probably paging memory to disk and that would have take a much,
much, longer time. When you are trying to do something BIG, do it in
some smaller steps and look at the resources that it takes (memory,
cpu, ...).
Jim Holtman
Do you realize you are trying to create a vector with 1 billion
entries, so this will take some time. How much memory do you have on
your computer?
Here are some times to generate increasing sample sizes. I have 16GB
on my computer and it took only 30 seconds to generate the data and
used almost
Here is a solution using 'dplyr'
> require(dplyr)
> lag<-read.table(text=" ID, y1, y2
+ 1,0,12/25/2014
+ 1,125,9/15/2015
+ 1,350,1/30/2016
+ 2,0,12/25/2012
+ 2,450,9/15/2014
+ 2,750,1/30/2016
+ 2, 656, 11/30/2016
+ ",sep=",",header=TRUE)
>
> new_lag <- lag %>%
+ mutate(y2 = as.Date(y2
I forgot about the sorting part and assumed the data.frame was already
sorted. If not, after converting y2 to class Date, you can do
lag <- lag[order(lag$ID, lag$y2), ]
Rui Barradas
Em 15-10-2016 19:45, Rui Barradas escreveu:
Hello,
Try the following.
lag<-read.table(text=" ID, y1, y2
1,0,
Hello,
Try the following.
lag<-read.table(text=" ID, y1, y2
1,0,12/25/2014
1,125,9/15/2015
1,350,1/30/2016
2,0,12/25/2012
2,450,9/15/2014
2,750,1/30/2016
2, 656, 11/30/2016
",sep=",",header=TRUE)
str(lag)
lag$y2 <- as.Date(lag$y2, format = "%m/%d/%Y")
str(lag)
# 1)
flag <- ave(lag$ID, lag$ID
I have the problem use R
Error in solve.default(object$hessian)
system is computationally singular: reciprocal condition number = 1.42892e-30
what is the problem ?and what it means
help me
--
[[alternative HTML version deleted]]
__
R-help@r-
When I ran this code:
"
x<-sample(1:5,10,TRUE,c(0.1,0.2,0.4,0.2,0.1))
print(table(x)/10)
plot(table(x)/10,type="h",xlab="x",ylab="P(x)")
"
My laptop was frozen and didn't respond. Although I used ctrl+alt+del to
terminate r program, my laptop still did nothing. And I must re
Hi all,
I want sort the data by ID and Y2 then count the number of rows within
IDs. Assign a "flag" variable to reach row starting from first to
the last row.
For instance, in the following data ID "1" has three rows and each
row is assigned flag sequentially 1, 2,3.
2. In the second step, wi
My conception of prediction intervals is the following:
"a prediction interval gives an interval within which we expect next y_i
to lie with a specified probability"
So when using predict() for my model:
predict(fit4, interval="prediction")[1:20,]
I get:
fit lwr upr
1 491
Until now I was using plot() and I check the possibility to shift to
ggplot2.
All is OK until now except to write text out of the plotting region
[equivalent of par(xpd=TRUE); text(x, y, labels)].
I have found using google recommendation to use annotation_custom() but
I still failed to print
Hi Jim,
no, I calculated the return series in Excel and imported the data into R. Then
I transformed the data into a vector as I need a vector object of asset returns
and did the calculation.
Kind regards,
T.
From: Jim Lemon
Sent: 15 October 2016 11:06
Replace newlines and colons with a space since they seem to be junk,
generate a pattern to replace the attributes with a comma and do the
replacement and finally read in what is left into a data frame using
the attributes as column names.
(I have indented each line of code below by 2 spaces so if
On 14/10/2016 2:52 PM, Anže Dejak wrote:
Greetings,
Firstly, I'd hope this is the correct e-mail address to ask about specific
problems refering to problems with R. If it isn't, I kindly ask of you to
re-direct me to the correct contact person.
So, the thing with my version of R (I'm using RStu
Hi Anze,
I'm not sure that this will work on Windows, but you can create a
function named ".First" (note the leading period) with something like
this:
.First<-function() setwd("C:/Users/anze")
To do this, start a session, enter the above line and then quit the
session, saving the current workspac
Hi T,
Have you tried converting "clearntest" or "data" into a time series?
Jim
On Sat, Oct 15, 2016 at 4:47 AM, T.Riedle wrote:
> Dear all,
>
> I am trying to clean return data using the Return.clean() function in the
> PerformanceAnalytics package. Hence, my code looks as follows but I get an
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