Hello,
Not sure but have you consider using :
expand.grid(E1, E2)
that will create a data.frame of all combinations of your two vectors
and then use it for your search.
Best,
François
Le 01/03/2017 à 08:27, Evan Kransdorf a écrit :
Hello,
I need some help with data.table. I am trying to
Hello,
I need some help with data.table. I am trying to use data.table to do a
binary search of a large table using 2 keys.
KEY1 KEY2 PARAM1
row1 1 2-0.031
row2 2 8 -0.456
row3 3 24-7.86
row4 5 2 2.89
I set the keys:
#DT<-setke
If you believe that a fit to simulated data should give you parameter
estimates identical to those used for the simulation, then I suggest
that you stop posting and consult a local statistical expert: you
don't know what you're doing.
If I have misunderstood your post, then just ignore the above a
Hi All:
In searching online, I have found examples of using plotly with ggplot2
graphics, say using geom_line, where there are multiple lines and by
selecting the "factor" in the legend makes the particular line disappear or
reappear (see https://plot.ly/ggplot2/). I am wondering if anyone
Hi Maria,
No problem. Taking the example I used before:
aa<-data.frame(var1=runif(180),
SDATE=paste(sample(1998:2012,180,TRUE),
sample(1:12,180,TRUE),sample(1:28,180,TRUE),sep="-"))
aa$sdate<-as.Date(aa$SDATE)
plot(aa$sdate,aa$var1,xaxt="n")
# set the tick marks at the middle of every other year
As Mark and Wray have indicated, you have not told us what you have actually
tried other than search the internet. If you spent 3 days learning R and don't
know how to import a .csv file from Excel, you should be emailing the
instructor of the course. Use Save As in Excel to save your spreadshee
On 28/02/2017 11:07 AM, Rytis Bagdziunas wrote:
Hello everyone,
I've been struggling with the usage of ellipsis argument for stats::nls
and similar functions. In particular, nls manual indicates this:
...: Additional optional arguments. None are used at present.
The documentation is incorrec
> On Feb 28, 2017, at 8:11 AM, Ashley Patton via R-help
> wrote:
>
>
> Hi, please forgive me but I am completely new to R and have no experience
> with it other than a 3 day training course but I need to use it for an urgent
> project and don't have time to learn a whole new language before
The first thing you need to do is to read your data in. Convert your excel file
to a csv file, say mydata.csv, and make sure that you know where it is eg folder
"Datafile" on C drive. Then use setwd("C:/Datafile") and then
read.csv("mydata.csv") That should upload it and you can trawl t'interne
Hello everyone,
I've been struggling with the usage of ellipsis argument for stats::nls
and similar functions. In particular, nls manual indicates this:
...: Additional optional arguments. None are used at present.
However, "none are used" seems to be slightly misleading. Here's an
example:
d
Hi, please forgive me but I am completely new to R and have no experience with
it other than a 3 day training course but I need to use it for an urgent
project and don't have time to learn a whole new language before the deadline,
although I hope to get there soon.
My question is this. I have
Dear Jen,
Vectorisation is the keyword here. 250k sample takes only 2.5 seconds on my
machine. 2.5 million takes 29 seconds.
n <- 250e3
# country code
cc <- "+212"
# prefixes
IAM <- c(610,611,613,615,616,
618,641,642,648,650,651,652,653,
Hi, I'm trying to generate 2.5 million phone numbers. The code below
generates a random sample of 250K MPNS for Morocco. It takes about 10
minutes.
I need to generate 2.5 million. I've run it through once and it took about
45 hours.
Is there a way to speed this up?
Thanks,
Jen
# generate ra
Thank you Bert for the references. I have found mix.vmf as a possible
alternative to movMF but am stuck with applying either to my application.
Does anyone know why mix.vmf requires to 2 columns for x?
For example when I use:
gWD <- c(0.1, 1, 0.9, 0.7,0.3)
> mix.vmf(gWD, 2)
I get the error:
‘Er
This is not a reproducible example. You did not even show us one of the scripts
that apparently did work. None of your if() statements contains a logical
expression. You should read "An Introduction to R" and probably other tutorials
on R.
https://cran.r-project.org/doc/manuals/r-release/R-intr
Hi Petr
I followed your suggestion and I have attached a saved txt file with the data
and the script using dput(). I hope this time will work.
But by the way your code worked as well.
Many thanks.
Kind regards,Maria
Στις 1:06 μ.μ. Τρίτη, 28 Φεβρουαρίου 2017, ο/η PIKAL Petr
έγραψε:
H
> On Feb 28, 2017, at 8:36 AM, Jeff Newmiller wrote:
>
> For tasks like this, you will probably want to make sure to import the data
> as character data rather than as a factor. E.g.
>
> dat <- read.csv( "myfile.csv", header=FALSE, as.is=TRUE )
>
> You can check what you have with the str()
For tasks like this, you will probably want to make sure to import the data as
character data rather than as a factor. E.g.
dat <- read.csv( "myfile.csv", header=FALSE, as.is=TRUE )
You can check what you have with the str() function.
--
Sent from my phone. Please excuse my brevity.
On Februa
Let me give an outline of how to answer Alfredo's question via an example.
I will split the data set "lung" into two peices. For these subjects with
advanced lung cancer the physician's assessment of ECOG performance status
(ph.ecog) is one of the most powerful indicators of outcome. Try to
pred
> On Feb 28, 2017, at 3:38 AM, Harshal Athawale
> wrote:
>
> I am new in R.
>
> I have a file. This file contains name of the companies.
> 'data.frame': 494 obs. of 1 variable:
> $ V1: Factor w/ 470 levels "3-d engineering corp",..: 293 134 339 359 143
> 399 122 447 398 384 ...
>
> Problem:
I am new in R.
I have a file. This file contains name of the companies.
'data.frame': 494 obs. of 1 variable:
$ V1: Factor w/ 470 levels "3-d engineering corp",..: 293 134 339 359 143
399 122 447 398 384 ...
Problem: I would like to remove "CO" (As it is the most frequent word). I
would like "C
Hi
better to send us your data by copying result of dput()
Based on Jims toy data, do you want something like that?
plot(aa$sdate,aa$var1,xaxt="n")
sel <- seq(1,15, 2)
axis(1, at=axis.dates[sel], labels=format(axis.dates, "%Y")[sel])
You can easily adopt it by managing the sequention.
Cheers
P
Very difficult to diagnose what is going on without actually seeing the data.
But as I said on CV: Depending on the data, the variance components may not be
estimated precisely, so negative values for those kinds of pseudo-R^2
statistics are quite possible. In fact, if a particular moderator is
Dear Jim
Many thanks for this. I tried and it somehow worked. I removed the nlines=3
from your script so I can have the years in one line, but still the problem is
that while trying to show all the years, there are years in the first line and
then other years in a second line.
I was wondering i
Dear all,
Sorry about that. My mistake. Here is an example of my data
> head(aa) SDATE var11 1998-01-29 0.7282 1998-02-17 1.0803 1998-03-20
> 0.6374 1998-05-07 1.1205 1998-05-26 0.9036 1998-06-05
> 1.210.178 2012-10-4 0.71179 2012-11-4 0.663180
> 2012-12-10 0.484
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