Thanks, you are right that the file path is not correct. I just typed:
nc_open("file.nc"), and it gave the error above.
On Tue, Sep 18, 2018 at 1:33 PM, Jeff Newmiller
wrote:
> I really don't know how you expect an answer when you don't show what you
> did or pointed us to an example of a file t
Hello,
I am not completely sure but I think I installed Ubuntu 18.04 LTS first
and R 3.5 days later, so yes, if I'm right it is possible to run R 3.4
on 18.04.
(You ask whether we can *install* R 3.4 on Ubuntu 18.04.1, I'm saying it
can be *run* on Ubuntu 18.04.1.)
Hope this helps,
Rui Ba
Dear All,
I was reading this page --->
https://cran.r-project.org/bin/linux/ubuntu/README.html
It says: R 3.4 packages for Ubuntu on i386 and amd64 are available for all
stable Desktop releases of Ubuntu prior to Bionic Beaver (18.04) until
their official end of life date.
The page also shows ho
Dear Jeff,
Thank you please.
I did search before but could not get it resolved. But with your query now,
just typed ?xtable as key search word and the first document I opened gave
an indication of digits. Without knowing what it was saying, I tried it in
my data and it gave the result I have bee
I really don't know how you expect an answer when you don't show what you did
or pointed us to an example of a file that yields this error. My best blind
guess is that you have not given the name of an ncdf file to the function.
On September 17, 2018 9:44:45 PM PDT, lily li wrote:
>Hi R users,
Have you read
?xtable
On September 17, 2018 7:24:37 PM PDT, Ogbos Okike
wrote:
>Dear Volunteers,
>
>I have a table involving many decimal places:
>2005-01-04 -2.13339817688037
>2005-01-19 -6.86312349695117
>2005-01-22 -4.33662370554386
>2005-02-10 -1.40789214441639
>2005-02-13 -1.1334121785854
Hi R users,
I have installed ncdf4 package in R from the linux terminal, but have met
this problem when using nc_open to open a .nc file. What is the problem?
Any help would be appreciated.
Error in R_nc4_open: Is a directory
[[alternative HTML version deleted]]
Dear Volunteers,
I have a table involving many decimal places:
2005-01-04 -2.13339817688037
2005-01-19 -6.86312349695117
2005-01-22 -4.33662370554386
2005-02-10 -1.40789214441639
2005-02-13 -1.1334121785854
2005-02-19 -1.28411233010119
2005-05-09 -1.6895978161324
2005-05-16 -3.07664523496947
2005-
Hello,
I'm trying to use parallel computing in MuMIn package. It worked a couple
month ago, but now I'm getting the error. Here is a code:
#Data
x1 = rnorm(1000)
x2 = rnorm(1000)
x3 = rnorm(1000)
z = 1 + 0.5*x1 - x2
pr = 1/(1+exp(-z))
y = rbinom(1000, 1, pr)
dataD = cbind(y=y, x1=x1 ,x2=x2, x3=x3
Hi Henrik,
Thanks for the suggestions! I tried your approach, and obtained the
following output, which is pretty similar to the previous ones.
> cl <- future::makeClusterPSOCK(1, outfile = NULL, verbose = TRUE)
*Workers: [n = 1] ‘localhost’*
*Base port: 11214*
*Creating node 1 of 1 ...*
*- se
I didn't find an attached file, but I'm using Ubuntu 18.04 and have upgraded R
to version 3.5.
I don't recall exactly how I did the upgrade, but it must have been something
like:
https://www.digitalocean.com/community/tutorials/how-to-install-r-on-ubuntu-18-04-quickstart
-- Mike
$ cat /etc/os-r
" I did not pick up on by() doing the splitting for me when I read the
help..."
>From ?by:
"A data frame is split by row into data frames subsetted by the values of
one or more factors, and function FUN is applied to each subset in turn."
I do not understand how it could be more clearly stated t
On Mon, Sep 17, 2018 at 12:56 PM Zhihao Huang wrote:
>
> Hi Henrik,
>
> Thanks for the suggestions! I tried your approach, and obtained the following
> output, which is pretty similar to the previous ones.
>
> > cl <- future::makeClusterPSOCK(1, outfile = NULL, verbose = TRUE)
> Workers: [n = 1]
On Mon, 17 Sep 2018, Bert Gunter wrote:
I cannot think of a way of proving a sample of data; if a sample for a
Typo: s/proving/providing/
Rich
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/li
Inline.
Bert
On Mon, Sep 17, 2018 at 11:54 AM Rich Shepard
wrote:
>My dataframe has 113K rows split by a factor into 58 separate
> data.frames,
> with a different numbers of rows (see error output below).
>
>I cannot think of a way of proving a sample of data; if a sample for a
> MWE
On Mon, 17 Sep 2018, MacQueen, Don wrote:
I'm also going to guess that maybe your object rainfall_by_site has
already been split into separate data frames (because of its name). But
by() does the splitting internally, so you should be passing it the
original unsplit data frame.
Don,
I did n
I'm also going to guess that maybe your object
rainfall_by_site
has already been split into separate data frames (because of its name).
But by() does the splitting internally, so you should be passing it the
original unsplit data frame.
You could supply example data by providing the first few
Try changing it to
by(rainfall_by_site, rainfall_by_site[, 'name'],
function(x) {mean.rain <- mean(x[, 'prcp'])
})
Inside the function, so to speak, the function sees an object named "x",
because that's how the function is defined: function(x).
So you have to operate on x inside
>
> by(rainfall_by_site, rainfall_by_site[, 'name'], function(x) {
>
+ mean.rain <- mean(rainfall_by_site[, 'prcp'])
+ })
Note that you define a function of x which does not use x in it.
Hence, even if the function gave a value, it would give the same
value for each group. To see what the 'x' in
My dataframe has 113K rows split by a factor into 58 separate data.frames,
with a different numbers of rows (see error output below).
I cannot think of a way of proving a sample of data; if a sample for a MWE
is desired advice on produing one using dput() is needed.
To summarize each group
Dear Hamed,
> -Original Message-
> From: Hamed Ha [mailto:hamedhas...@gmail.com]
> Sent: Monday, September 17, 2018 3:56 AM
> To: Fox, John
> Cc: r-help@r-project.org
> Subject: Re: [R] Problem with lm.resid() when weights are provided
>
> H i John,
>
>
> Thank you for your reply.
>
>
Dear All,
I am using R to carry out RNA-Seq workflow in my standalone machine which
needs the latest R version >=3.5. I was trying to update firstly removing
the R 3.4 and reinstalling from scratch again the latest version. Can
anybody just guide me how to carry out the process as I am getting only
Thanks for the help. My friend helped me and here is the solution:
boot.cluster <- function(x, id){
boot.id <- sample(unique(id), replace=T)
out <- lapply(1:length(boot.id),
function(newid){cbind(x[id%in%boot.id[newid],],newid)})
return( do.call("rbind",out) )
}
Lei
-Original Message-
Yes, it does. Thank you.
Aimin
On Sun, Sep 16, 2018 at 11:00 PM Paul Murrell
wrote:
> Hi
>
> The 'x' component of the 't' grob that you get back from grid.get() is a
> unit object, which you can subset and assign to a subset, for example
> this code nudges the fourth label up and to the right 1
Hi!
I'm solving a quadratic programming problem with some constraints. The
problem is the second set of Amat conditions, which seem to be
inconsistent, but I cannot see why. Do you have any idea, what could be the
problem?
Thanks in advance for your help!
Maija
for(j in 1:J){
hs[j] <-(-(gEst$
On Sun, 16 Sep 2018 21:18:45 +0200
Kim Titcombe wrote:
> I have Windows 10. English version.
Do you have any other problems, besides the warning message at startup?
According to MSDN[1], the combination of English language
and Swiss cultural rules should be supported in Windows 10 >=
v1607 with
Dear Jeff,
Yours is like reciting A, B,C or 1, 2, 3 ...
I am greatly relieved.
Many thanks.
Ogbos
On Mon, Sep 17, 2018 at 9:07 AM Jeff Newmiller
wrote:
> There are many ways to combine data frames, but the method you have chosen
> is extremely rare because you do not appear to be creating sen
There are many ways to combine data frames, but the method you have chosen is
extremely rare because you do not appear to be creating sensible relationships
in the rows of the data frame, so your final result seems unlikely to be
understandable by normal interpretation of tabular data. See ?merg
H i John,
Thank you for your reply.
I see your point, thanks. I checked lm.wfit() and realised that there is a
tol parameter that is already set to 10^-7. This is not even the half
decimal to the machine precision. Furthermore, plying with tol parameter
does not solve the problem, as far as I che
You are telling us that the ID values in your data set indicate clusters.
However you went about making that determination in the first place might be an
obvious(?) way to do it again with your bootstrapped sample, ignoring the
cluster assignments you have in place. This is the wrong place to ha
Dear Contributors,
I have two data frame of different column lengths. I am trying to have them
in one data frame.
Using
A<-d1$date
B<-d2$date
a<-data.table(A )[ , I := .I][data.table(B )[ , I := .I], on = "I"]
I got
1: 2005-01-04 1 2005-01-04
2: 2005-01-19 2 2005-01-19
3: 2005-01-22 3 2005-01
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