I am realizing as well that R is not the best option for an
interactive session. I changed the script to get the input from a
config file; it is less elegant because the procedure now requires
double the files than with CLI input, but at the end of the day is
more practical when most of the answer
The final goal is to make two lines and find the intersection point.
I don't want to argue more about the reason.
The tol suggestion is reasonable, and I'll take that.
2019/4/19 4:12, Jeff Newmiller:
The fact that you think x~y is interchangeable with y~x suggests to me that you
will have a di
Dear Dingyuan Wang,
But your question was answered clearly earlier in this thread (I forget by
whom), showing that lm() provides the solution to the regression of x on y if
the criterion for singularity is tightened:
> lm(x ~ y)
Call:
lm(formula = x ~ y)
Coefficients:
(Intercept)y
Generally you should do the power analysis before collecting any data.
Since you have results it looks like you already have the data
collected.
But if you want to compute the power for a future study, one option is
to use simulation.
1. decide what the data will look like
2. decide how you will
The fact that you think x~y is interchangeable with y~x suggests to me that you
will have a difficult time convincing R Core that this is a bug. I recommend
that you take at leastan upper division college course in linear regression
first.
On April 18, 2019 9:35:55 AM PDT, Dingyuan Wang wrote:
I just want to make a line out of timestamps vs some coordinates, so y~x
or x~y doesn't matter.
Yes, I know the answer. When trying R, I'm surprised that R can't solve
that either. I first noticed that PostgreSQL can't solve it, and found
that they fixed that in pg 12.
https://www.postgresql
Hello,
I am running a non parametric repeated measures experiment with
Friedman’s test:
Friedman rank sum test
data: glikozi and week and subject
Friedman chi-squared = 18.538, df = 3, p-value = 0.0003405
How could I run a power analysis for this test in R?
Thank you!
--
George Kara
When the goal of looping is to compute something and save each
iteration into a vector or list, then it is usually easier to use the
lapply/sapply/replicate functions and save the result into a single
list rather than a bunch of global variables.
Here is a quick example that does the same computat
I am not an expert on Rscript, but I don't think that an actual
terminal is ever used when using Rscript. And `interactive()` will
probably always be false.
So if you want the script to pause for input, you need to have some
form of user interface to work with.
One option is to use the tcltk pac
I make a general rule not to stick time values into numerical analysis
algorithms without first subtracting a reasonable epoch (to obtain difftime)
and then using as.numeric.POSIXt with the units argument set explicitly so the
analysis uses numeric values that I can interpret. While the explicit
To be clear, if you encounter problems with R using RStudio, try doing "the
same thing" using an interface provided in the R installed software directly...
under Windows that might be through RGui or on Mac using R.app or on any
platform via the terminal command line R program. If the problem go
Thank you PIKAL Petr.
From: PIKAL Petr
Sent: Thursday, April 18, 2019 8:54 AM
To: Bill Poling ; r-help (r-help@r-project.org)
Subject: RE: Help with a setting some values of a df vector to 0 but not all
values
Hi
seems to me simple
Sample data
> nozero <- c(1565, 1569, 1674, 415, 1564)
>
Dear Peter,
> -Original Message-
> From: peter dalgaard [mailto:pda...@gmail.com]
> Sent: Thursday, April 18, 2019 12:23 PM
> To: Fox, John
> Cc: Michael Dewey ; Dingyuan Wang
> ; r-help@r-project.org
> Subject: Re: [R] lm fails on some large input
>
> Um, you need to reverse y and x the
> On Apr 18, 2019, at 8:24 AM, Michael Dewey wrote:
>
> Perhaps subtract 1506705766 from y?
Good advice. Some further notes follow.
One can specify `tol` to have a smaller than default value
e.g.
m2 <- lm(x ~ y, tol=1e-12)
which is accurate:
plot(y,x)
abline(coef=coef(m2))
Users
This sort of data arises quite easily if you deal with time/dates around
now. E.g.,
> d <- data.frame(
+ when = seq(as.POSIXct("2017-09-29 18:22:01"), by="secs", len=10),
+ measurement = log2(1:10))
> coef(lm(data=d, measurement ~ when))
(Intercept) when
2.17910611147
Um, you need to reverse y and x there. The question was about lm(y ~ x)
> X <- cbind(1, y)
> solve(crossprod(X))
Error in solve.default(crossprod(X)) :
system is computationally singular: reciprocal condition number = 6.19587e-35
Actually, lm can QR perfectly OK, but it gets caught by its
Yes.
Have you gone through any R tutorials, yet? There are many good ones on the
web, some of which are listed here:
https://www.rstudio.com/online-learning/
See also the "Intro to R" tutorial that ships with R.
Spending a little time with these will help you understand R's capabilities
and, of c
Dear Michael and Dingyuan Wang,
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Michael
> Dewey
> Sent: Thursday, April 18, 2019 11:25 AM
> To: Dingyuan Wang ; r-help@r-project.org
> Subject: Re: [R] lm fails on some large input
>
> Perhaps subtract
Dear Stephen
Questions about RStudio ae best asked in their help forums but I would
definitely install the latest version of R and RStudio and do
update.packages before asking
Michael
On 18/04/2019 13:19, Stephen Muldoon wrote:
Hi,
I am new to R studio. If my R studio continually asks to r
Perhaps subtract 1506705766 from y?
Saying some other software does it well implies you know what the
_correct_ answer is here but I would question what that means with this
sort of data-set.
On 17/04/2019 07:26, Dingyuan Wang wrote:
Hi,
This input doesn't have any interesting properties ex
Hi,
I am new to R studio. If my R studio continually asks to restart for new
packages to run, should I remove R studio and reinstall this latest version?
Thanks,
Stephen
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.
Dear R community,
I'm trying to create a looping to see the effect of number of samples from
one dataset.
Lets say I have 10 values in a single data frame and I want to see the mean
of each sampling let say from 2-9 number of sampling. But I want to do the
repetition let say up to 100 for each num
Hello
Is it possible to calculate in r the number of days and count of b in var r
from the following table:
id r s t u
1 a 100 1 27-06-2017
1 a 200 0 29-06-2017
1 b 300 0 01-07-2017
2 a 500 1 12-06-2017
3 b 100 0 02-07-2017
3 a 600 1 02-07-2017
4 a 200 0 12-06-2017
4 a 300 1 15-06-2017
4 b 200 0
Hi,
This input doesn't have any interesting properties except y is unix
time. Spreadsheets can do this well.
Is this a bug that lm can't do x ~ y?
R version 3.5.2 (2018-12-20) -- "Eggshell Igloo"
Copyright (C) 2018 The R Foundation for Statistical Computing
Platform: x86_64-pc-linux-gnu (64-bi
Dear all,
I am trying to write an interactive script where the user type some
input from the terminal. I used readline() but when I launch the file
with Rscript, the function is overwritten directly, there is no
waiting for the user's input. For instance, this example:
VAR1 = as.numeric(readline(p
Hi
seems to me simple
Sample data
> nozero <- c(1565, 1569, 1674, 415, 1564)
> test <- sample(c(1:10, nozero), 250, replace=T)
> test
[1] 10264 41559 1565 15692 10 1569 415 15693
[16]49 10115 1013 109 15644 108
Dear R users,
I want to compute a nlm for each plot an species and after that to save the
regression coef for each species and plot.
Thanks for your help!
I tried something like this
s<-data.frame(unique(ah$sp))
pl<-data.frame(unique(ah$plot))
z<-data.frame(matrix(nrow=0, ncol=5))
for(i in 1:nr
Yes, thank you Eric, that's got it, sheesh, I knew it was simple.
Many thanks.
WHP
From: Eric Berger
Sent: Thursday, April 18, 2019 8:47 AM
To: Bill Poling
Cc: r-help (r-help@r-project.org)
Subject: Re: [R] Help with a setting some values of a df vector to 0 but not
all values
df$ClaimManag
df$ClaimManagerID[ !(df$ClaimManagerID %in% c(1565,1569,1674,415,1564))] <-
0
On Thu, Apr 18, 2019 at 3:39 PM Bill Poling wrote:
> Good morning.
>
> #RStudio Version 1.1.456
> sessionInfo()
> #R version 3.5.3 (2019-03-11)
> #Platform: x86_64-w64-mingw32/x64 (64-bit)
> #Running under: Windows >=
Good morning.
#RStudio Version 1.1.456
sessionInfo()
#R version 3.5.3 (2019-03-11)
#Platform: x86_64-w64-mingw32/x64 (64-bit)
#Running under: Windows >= 8 x64 (build 9200)
I have a df column that looks like the below.
#68 ID's including the 0 value
I want to set all the values to 0 with the exc
Dear Patrick,
This is not easy to debug without a reprex
I would check the content of zzz and wide.i in the loop
str(wide.i)
zzz <- rbind(zzz, wide.i)
str(zzz)
Note that the Rmd always runs in a clean environment. This might explain
the difference
Best regards,
ir. Thierry Onkelinx
Statistic
On Thu, 18 Apr 2019 10:36:10 +
akshay kulkarni wrote:
> fx <- (x1 <= -2)*(x1^2) + (x1 > -2 && x1 < 2)*(x1^3) + (x1 > =
> 2)*(x1^4)
>
> Can I include fx in an nls call to create something like this:
>
> NLS1 <- nls(y ~ a*(sin(x2) + fx), start = list(a = 2)) ?
For now, you can, since fx
I have a function that works in ESS, but it fails if I include it in
an .Rmd file that I tried to knit using Rstudio. I found advice at:
https://www.rstudio.com/products/rstudio/release-notes/debugging-with-rstudio/
It seems to be not referring to markdown files. Somewhere else
suggested calling
Hi Drake,
Petr's suggestion to use the merge() function is good.
Another (possibly overkill) approach is to use functions from the dplyr
package, which is a fantastic package to get familiar with.
For example, the last alternative that Petr suggests is an example of what
is called a "left join" (me
Hi
I wonder why such combination is so complicated in your text book.
Having data frames fr1 and fr2
> dput(fr1)
structure(list(Fruit = structure(c(1L, 3L, 2L), .Label = c("banana",
"mango", "pear"), class = "factor"), Calories = c(100L, 100L,
200L)), class = "data.frame", row.names = c("1", "2"
The whole thing is a merge operation, i.e.
> FruitNutr <- read.table(text="
+ Fruit Calories
+ 1 banana 100
+ 2 pear 100
+ 3 mango 200
+ ")
> FruitData <- read.table(text="
+ Fruit Color Shape Juice
+ 1 apple red round 1
+ 2 banana yellow oblong 0
+ 3 pear green pear 0.5
+ 4 orange orange round 1
Dear Drake
See in-line comments
On 18/04/2019 00:24, Drake Gossi wrote:
Hello everyone,
I'm working through this book, *Humanities Data in R* (Arnold & Tilton),
and I'm just having trouble understanding this maneuver.
In sum, I'm trying to combine data in two different data.frames.
This data
Dear All,
I have in field and collect some data and i need your help for the appropriate
test to analyze the data.
Indeed, i collected data from 200 farmers. From cluster analysis, i found four
type or clusters of farmers. During the survey, i asked all the farmers to rank
the different constrai
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