I stand corrected!
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Aug 8, 2019 at 7:11 PM Jeff Newmiller
wrote:
> Val 1
> Bert 0
>
> On August 8, 2019
Assuming your actual case is a file containing those characters, your example R
string has to quote them. However, it seems like you want to disable
interpreting quotes while you read this file.
vld<-read.table(text=
"name prof
A '4.5
B \"3.2
C 5.5 "
Val 1
Bert 0
On August 8, 2019 5:22:13 PM PDT, Bert Gunter wrote:
>read.table() does not have a "text" argument, so maybe you need to go
>back
>and go through a tutorial or two to learn R basics (e.g. about function
>calls and function arguments ?)
>See ?read.table (of course)
>
>Cheers,
>
I would remove the quotes using sub, something like
# Read the file as text lines
text = readLines(con = file(yourFileName))
# Remove the offending quotes
text = gsub("'|\"", "", text)
# Concatenate and turn into a data frame
concat = paste(text, collapse = "\n")
df = read.table(text = concat,
Thank you all, I can read the text file but the problem was there is
a single quote embedded in the first row of second column. This
quote causes the problem
vld<-read.table(text="name prof
A '4.5
B "3.2
C 5.5 ",header=TRUE)
On Thu, Aug 8, 2019 at 7:24 PM Anaanthan
read.table() does not have a "text" argument, so maybe you need to go back
and go through a tutorial or two to learn R basics (e.g. about function
calls and function arguments ?)
See ?read.table (of course)
Cheers,
Bert Gunter
"The trouble with having an open mind is that people keep coming
data <- read.table(header=TRUE, text='
name prof
A 4.5
B 3.2
C 5.5
')
> On 9 Aug 2019, at 8:11 AM, Val wrote:
>
> Hi all,
>
> I am trying to red data where single and double quotes are embedded
> in some of the fields and prevented to read the data. As an example
> please see
Hi you can save your data file in txt or csv file. Then you can use function "
vld <-read.table("C:/Users/ .txt",header=T)".
Regards
Mayooran
-Original Message-
From: R-help On Behalf Of Val
Sent: Friday, 9 August 2019 12:11 PM
To: r-help@R-project.org (r-help@r-project.org)
Hi all,
I am trying to red data where single and double quotes are embedded
in some of the fields and prevented to read the data. As an example
please see below.
vld<-read.table(text="name prof
A '4.5
B "3.2
C 5.5 ",header=TRUE)
Error in read.table(text = "name prof \n
The proper place for Ubuntu/Debian questions is r-sig-deb...@r-project.org
--
David
On 8/8/19 12:52 PM, k...@breadfinance.com wrote:
Sorry for unintentionally sending a rich text email.
I have confirmed that installation follows ubuntu guide lines in your link and
I reproduce the output of
Sorry for unintentionally sending a rich text email.
I have confirmed that installation follows ubuntu guide lines in your link and
I reproduce the output of git blame of the installation recipe showing that it
has always been using the right key. The change before we get these errors are
on
Hello,
Maybe I don't understand the question but isn't all you have to do is
to, well, reverse the colors
col = c("palevioletred1", "royalblue1")
in the boxplot call?
boxplot(flcn_M ~ subject, data = dx,
col = c("palevioletred1", "royalblue1"),
xlab="subjects",
I don't know a clean way of delivering that result but if you use
logical indexing you can get an empty matrix with three columns:
str( mdat["nope" %in% rownames(mdat), ] )
num[0 , 1:3]
- attr(*, "dimnames")=List of 2
..$ : NULL
..$ : chr [1:3] "C.1" "C.2" "C.3"
# it prints thus to the
I use R a great deal but the huge web crawling power of it isn't an area I've
used. I don't want to reinvent a cyberwheel and I suspect someone has done what
I want. That is a program that would run once a day (easy for me to set up as
a cron task) and would crawl a single root of a web site
Hello,
I made plot in attach using:
boxplot(flcn_M~subject,data=dx,col =
c("royalblue1","palevioletred1"),xlab="subjects",ylab="Expression
estimate in delta (log2)",boxwex = 0.2,frame.plot = FALSE)
stripchart(flcn_M~subject, vertical = TRUE, data = dx,method =
"jitter", add = TRUE,pch = 20,
Jeff:
Fair enough. As I have no data (no experience with crashes), I am happy to
defer to those who do.
Cheers,
Bert
On Thu, Aug 8, 2019 at 10:28 AM Jeff Newmiller
wrote:
> If R crashes, RStudio typically also crashes... so not necessarily news to
> them.
>
> I will say that reproducible
If R crashes, RStudio typically also crashes... so not necessarily news to them.
I will say that reproducible examples are nearly always necessary in cases like
this to obtain meaningful answers from anyone, and the output of sessionInfo()
is also usually needed.
On August 8, 2019 8:35:49 AM
Hi
Many thanks for your very quick response. I should have spotted the error
in the data. I have corrected it but the error remains. Hopefully. the
package maintainer will be able to help.
Thank you very much for your reply.
Tom
On Thu, 8 Aug 2019 at 15:57, Jeff Newmiller
wrote:
> This is a
This is an excellent question.
The answer, in this particular case, mostly has to do with the outlier time
values. (I've
never been convinced that the death at time 999 isn't really a misplaced code
for
"missing", actually). If you change the knots used by the spline you can get
quite
Hi,
Let say I have below matrix
mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol = 3, byrow = TRUE,
dimnames = list(c("row1", "row2"),
c("C.1", "C.2", "C.3")))
Now I can extract a raw by rowname as
> mdat['row1', ]
C.1 C.2 C.3
1 2 3
That is a better path, I agree.
However, I suspect that RStudio would still like to know about the issue,
even *if* feather/R is what crashes. They probably do not want RStudio to
crash even so.
-- Bert
On Thu, Aug 8, 2019 at 8:29 AM peter dalgaard wrote:
> Alternatively, try running your
Alternatively, try running your example from plain R (in a terminal, R.app, or
Rgui, depending on your platform), and see if the problem occurs without
RStudio in the equation. If it does, then the feather package probably owns the
problem.
-pd
> On 8 Aug 2019, at 16:34 , Bert Gunter wrote:
Hola Francisco:
Muchas gracias por este refinamiento.
Tienes razón, el gráfico de Lexis representa mucho mejor los datos.
Y gracias por el código. Lo guardo también para el futuro.
Saludos
On Thu, 8 Aug 2019 09:42:50 +0200
Francisco Viciana wrote:
> Hola, aunque con un poco de retraso,
This is a rather specialized issue... you probably should be cc'ing the package
maintainer as added here.
I have never used this package.. but perhaps the fact that 701 is female yet
listed as a father of 801 and 802 could be causing problems. (If so, this may
raise issues of family structure
You may have to contact RStudio about this. RStudio is a separate IDE
independent of R -- i.e. developed and maintained by a separate
organization from the R project.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka
Chris,
Thanks a lot for the help and your investigation by simulations.
> Interacting a fixed effect with a strata variable is not uncommon. No
> main effect of the strata variable is > possible but the interaction term
> allows the fixed effect variable to have different values in different
Hi
I have just started to do some analysis of genealogies and seem to be doing
something wrong when using gen.genealogy. The following is the script and
output that I used. Any help greatfully apprciated
library(GENLIB)
> library(ggenealogy)
> library(igraph)
> #
> #
> ###Data input as data
Hello,
since I am encountering a lot of problems exporting dataframes from
julia to R (there is always something wrong with the formatting,
probably a missing quote) so I am trying to use Feather to do the job.
I have installed Feather in Julia with `pkg.add("Feather")` and
imported it with
Estimado Cleiver Yam
Pienso que usted está bien encaminado, pero habría una llave combinada
entre las dos primeras columnas, ¿El id en la base de datos está compuesto
por ambas?, o posiblemente no pero usted podría estar requiriendo esto, es
simple, intente creando una columna con una combinación
Dear Abby,
Many thanks for your response.
To answer your question. For me better all the x variables (collectively), to
have m% missing values.
When you tell me : "Modify your code so that a single function say sim.test()
computes your simulated statistics, for n sample size and m missing
Hola.
Como las dos tablas tienen la variable común definida, podés hacerlo simple
con
library(tidyverse)
datos <- inner_join(df1, df2)
Saludos.
El jue., 8 ago. 2019 a las 8:59, Clei Y ()
escribió:
>
> Hola a todos
>
> Tengo una duda, puede ser un poco básica pero no encuentro la respuesta,
>
Hola a todos
Tengo una duda, puede ser un poco básica pero no encuentro la respuesta, tengo
dos base de datos como la siguiente:
Data frame 1:
Id_1Id_2Dato
1 1 3
1 2 6
1 2 5
2 1 2
2 1 4
2 3 5
Data frame 2:
Id_1
Bert's answer is great, but since there is only two columns to be
used, why not simply
pt$pheno <- pmax( p$phenoQ ,p$phenoH )
Cheers,
Lei
On Wed, 7 Aug 2019 at 21:23, Bert Gunter wrote:
>
> The ifelse() construction is fast, but after a couple of nested iterations,
> it gets messy and
Hola, aunque con un poco de retraso, hago una aportación a este hilo:
Si tienes un problema con dos escalas de tiempo sobre las que
evolucionan las lineas de seguimiento, creo que es mejor que hacer un
solo gráfico en forma de diagrama de Lexis, que dos gráficos
independientes. Muestro
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