Sorry, forgot to include the list.
On Sat, Sep 14, 2019 at 10:27 AM Jim Lemon wrote:
>
> See inline
>
> On Fri, Sep 13, 2019 at 11:20 PM Subhamitra Patra
> wrote:
>>
>> Dear Sir,
>>
>> Yes, I understood the logic. But, still, I have a few queries that I
>> mentioned below your answers.
>>
>>>
Regular expressions are in much more widespread use than merely R... and there
are correspondingly more resources for learning than just R-help. Please do
make use of them. Here are a couple that googling "regex character set carat"
found:
https://www.regular-expressions.info/charclass.html
Dear PIKAL,
Thank you very much for your suggestion.
I tried your previous suggested code and getting the average value for each
month for both country A, and B. But in your recent email, you are
suggesting not to change the date column to real date. If I am going
through your recently suggested
Hi
I am almost 100% sure that you would spare yourself much trouble if you changed
your date column to real date
?as.Date
reshape your wide format to long one
library(reshape2)
?melt
to get 3 column data.frame with one date column, one country column and one
value column
use ?aggregate and
However, notice that cat doesn't protect you in the same way:
Peters-iMac:tst pd$ echo stuff > A
Peters-iMac:tst pd$ ln -s A B
Peters-iMac:tst pd$ ls -l
total 8
-rw-r--r-- 1 pd staff 6 Sep 13 15:20 A
lrwxr-xr-x 1 pd staff 1 Sep 13 15:20 B -> A
Peters-iMac:tst pd$ cp A B
cp: B and A are
Dear Sir,
Yes, I understood the logic. But, still, I have a few queries that I
mentioned below your answers.
"# if you only have to get the monthly averages, it can be done this way
> spdat$month<-sapply(strsplit(spdat$dates,"-"),"["*,2*)
> spdat$year<-sapply(strsplit(spdat$dates,"-"),"[",*3*)"
A quick question.
Could you please explain the -- [^}]* -- part in finding the pattern?
On Fri, Sep 13, 2019 at 12:19 AM Bert Gunter wrote:
>
>
> You can't use the same regex for str_extract_all as I used for sub (or gsub,
> which is what is required here)! If you do this sort of thing a lot,
Hi Subhamitra,
I'll try to write my answers adjacent to your questions below.
On Fri, Sep 13, 2019 at 6:08 PM Subhamitra Patra
wrote:
> Dear Sir,
>
> Thank you very much for your suggestion.
>
> Yes, your suggested code worked. But, actually, I have data from 3rd
> January 1994 to 3rd August
Hi
I may be completely wrong but reshape/aggregate should by what you want
spdat
dates returnA returnB
1 1-1-1994 16 13
2 2-1-1994 44 10
3 3-1-1994 24 32
.
> library(reshape2)
> spdat.m <- melt(spdat)
Using dates as id variables
> str(spdat.m)
Dear Duncan
Thank you for the code, I will test it or at least check what it does. I
finally found probably easier solution.
I stay with my original code
if (dev.cur()==1) plot(ecdf(velik[,"ecd"]), main = ufil[j], col=i) else
plot(ecdf(velik[,"ecd"]), add=T, col=i)
After plot is finished and
If file.copy() is used to replace a symlinked file, it erases the
original file and does not copy the file. The original file is lost.
> version
_
platform x86_64-apple-darwin15.6.0
arch x86_64
os darwin15.6.0
Gracias por el aviso, Carlos.
Como siempre, muy buenas iniciativas.
Un saludo,
Miguel.
De: R-help-es en nombre de Carlos Ortega
Enviado: viernes, 13 de septiembre de 2019 9:25
Para: Lista R
Asunto: [R-es] "Grupo de Usuarios de R de Madrid". Meetup
Dear Sir,
Thank you very much for your suggestion.
Yes, your suggested code worked. But, actually, I have data from 3rd
January 1994 to 3rd August 2017 for very large (i.e. for 84 countries)
sample. From this, I have given the example of the years up to 2000. Before
applying the same code for
Buenas a todos,
Aunque os puede llegar el aviso por otros medios, os anuncio por aquí el
Meetup que estamos organizando conjuntamente el "Grupo de R de Madrid" y
las "R-Ladies" para el miércoles de la semana que viene (18-Sep).
Los detalles del evento los podéis encontrar aquí:
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