Probably better posted to the r-sig-geo list, where you are more
likely to find the relevant expertise.
Perhaps see also https://cran.r-project.org/web/views/Spatial.html,
depending on what you plan to do with your maps.
Bert Gunter
"The trouble with having an open mind is that people keep
Hello George!
Do you mean to have a map of the world with these countries filled in, or
to have just those countries on the map, please?
Thanks,
Erin
Erin Hodgess, PhD
mailto: erinm.hodg...@gmail.com
On Mon, Mar 30, 2020 at 7:38 PM george brida wrote:
> Dear R users,
>
> i would like to
HI Jim,
thank you so much for getting back to me, I think the issue is with
reading that csv file
> marker_info<-read.csv("marker-info",header=F,stringsAsFactors=FALSE)
> head(marker_info)
V1
1
#Column Description:
2
#Column is separated by '
Hi Ana,
This seems to work. It shouldn't be too hard to do the renaming and
reordering of columns.
output11.frq<-read.table(text="CHR SNP A1 A2 MAF NCHROBS
1 1:775852:T:CTC 0.1707 3444
1 1:1120590:A:CCA 0.08753 3496
1 1:1145994:T:CCT
Dear R users,
i would like to plot the maps of the Gulf Cooperation Council (GCC)
countries (KSA, Qatar, Bahrain, Kuwait, UAE and Oman) with these
constraints: i/ KSA , Qatar and Bahrain have the same face color , ii/
Kuweit and UAE with the same face color and iii/Oman with another face
color.
I have a file like this: (has 308545 lines)
head output11.frq
CHR SNP A1 A2 MAF NCHROBS
1 1:775852:T:CTC 0.1707 3444
1 1:1120590:A:CCA 0.08753 3496
1 1:1145994:T:CCT 0.1765
On 2020-03-30 13:21 +, SIMON Nicolas wrote:
| Apparently the condition " if ( var1 > tt ) "
| cannot be evaluated correcty.
|
| Could you please give me an advice to write it
| properly?
Hi! To understand what you wanted to do, I tried
to recreate your example in classic R indexing of
a
On 2020-03-30 13:21 +, SIMON Nicolas wrote:
> Could you please give me an advice to write it
> properly?
Hi! To understand what you wanted to do, I tried
to recreate your example in classic R indexing of
a data.frame, then converting it to a tibble:
var1 <- seq(0, 20, 1)
var2 <-
On 30/03/20 7:55 am, David wrote:
I’m trying to write a function that will add items to two vectors, and
then to create a third vector that is of the form 1, 2, 3, …, length of
one of the newly modified vectors. My problem is that what I’ve written
doesn’t seem to return any of those
Hi Bert,
Many thanks for your response.
Yes, my toy example is not representative of the reality. You are right without
colinearity my R code works.
As you say, it may be overfitting and there must be colinearity, even if for me
colinearity is not really a problem it is more a nuisance. It
I know nothing about the packages in question, but do you know what
"collinear" means and how/why it can mess up model fitting? If no,
that may be the problem. See also "overfitting."
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
Hi,
A google search does not give me any hint :=(
Maybe somebody can help me to fix the error message I get : Error in
robdist.hbrfit(x) : x is probably collinear
# # # # # # # # # # # # # # # # # # # ## # # # # # # # # # # # # # #
Harold,
I have dealt with this problem over the years and after much experimenting, I
can say that I *think* what you want is impossible. For RODBC, you need a
stored proc that uses SET NOCOUNT ON and that only returns a single result set.
You may want to try experimenting with the odbc
Muchas gracias Javier.
Voy a ver la información.
Manuel
El lun., 30 mar. 2020 a las 9:43, Javier Marcuzzi (<
javier.ruben.marcu...@gmail.com>) escribió:
> Estimado Manuel Spíndola
>
> No es justo R, pido disculpas por eso, hoy veo en una publicación española
> algo que puede servir para dar
Also see the 'rms' package.
If you use validate with bw=TRUE you can see often a given predictor will
be retained.
On Mon, Mar 30, 2020 at 11:57 AM stephen sefick wrote:
> Please search archives and Google. There are many resources. I think that
> the MASS package has stepwise regression, but
Please search archives and Google. There are many resources. I think that
the MASS package has stepwise regression, but please confirm yourself.
On Mon, Mar 30, 2020, 09:45 Jastine bugayong wrote:
> Statistics newbie over here getting her feet wet into the research realm.
>
> I will be using
Hello,
David is right, the response is named 'crp', not 'fastMM'. And there is
no need to run the regression twice.
Try
# function to obtain MSE
MSE <- function(data, indices, formula, method) {
d <- data[indices, ] # allows boot to select sample
fit <- lmrob(formula, data = d, method =
Hi David,
Yes, you are right but it does not change anything to my problem. According to
the error message, what I understand is that there is/are NAs values in "t".
Using newdata <- na.omit(Dataset) I create new dataset without missing data, so
I don't understand what is going on with these
Estimado Manuel Spíndola
No es justo R, pido disculpas por eso, hoy veo en una publicación española
algo que puede servir para dar sus clases, no se más que eso.
Link:
https://www.genbeta.com/web/ensena-casa-google-unesco-lanzan-centro-recursos-educativos-para-profesores-alumnos
Javier Rubén
You are comparing a 21-element vector with a 1-element vector, which gives you
21 answers. Which one of those answers are you actually interested in?
I am not sure what you are trying to accomplish here, so cannot offer further
advice.
On March 30, 2020 6:21:45 AM PDT, SIMON Nicolas wrote:
There is also the possibility that the OP believes that the function calls
are passing by reference.
On Mon, Mar 30, 2020 at 5:55 PM Richard M. Heiberger wrote:
> You need one more line In your function.
>
> addday <- function(stp,mcp,stpos,mcpos){
> stpos<-c(stpos,stp)
> mcpos<-c(mcpos,mcp)
>
Another comment: if you are running your program in RStudio, it will create
the sequence
of plots but you need to "page back" to see them. Click the "Plots" tab and
notice there are
two arrows: back (pointing to the left) and forward (pointing to the right)
HTH,
Eric
On Mon, Mar 30, 2020 at
On 3/30/20 2:45 AM, varin sacha wrote:
Many thanks David,
But I am not sure the Dataset and newdata are the real problem. I have solved, at least I
think so, what you were asking. Here below my new R code but still the same error
message. IMHO the problem is with "boot.ci" function...
# #
You need one more line In your function.
addday <- function(stp,mcp,stpos,mcpos){
stpos<-c(stpos,stp)
mcpos<-c(mcpos,mcp)
days<-c(1:length(stpos))
list(mcpos=mcpos, days=days)
}
This and the other question I just answered together say that you need to
re-read an introduction to R.
On Mon,
you probably forgot the print() statement.
Both lattice and ggplot require a print() in this situation.
See the help files.
On Mon, Mar 30, 2020 at 10:04 Ashim Kapoor wrote:
> Dear David,
>
> Try this :-
> par(mfrow=c(1,2))
> hist(rnorm(100))
> hist(rnorm(100,100,1))
>
> Best Regards,
> Ashim
Dear David,
Try this :-
par(mfrow=c(1,2))
hist(rnorm(100))
hist(rnorm(100,100,1))
Best Regards,
Ashim
On Mon, Mar 30, 2020 at 7:16 PM David wrote:
> I wrote a little program that asked to produce two plots, but when I ran
> it, I saw only the second plot. Is there a way to write a program
I wrote a little program that asked to produce two plots, but when I ran
it, I saw only the second plot. Is there a way to write a program that
will produce multiple visible plots?
David
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and
Statistics newbie over here getting her feet wet into the research realm.
I will be using the R-project to analyze the predictability of some data
using a stepwise multiple regression analysis. I would also like to have a
forced entry method option to avoid any methodology flaws, if possible,
I’m trying to write a function that will add items to two vectors, and
then to create a third vector that is of the form 1, 2, 3, …, length of
one of the newly modified vectors. My problem is that what I’ve written
doesn’t seem to return any of those modifications. How can I get the
new
Hi,
I tried to use mutate from dplyr with a personal function to create a new
variable of a data.frame.
All examples I found are such as myfunction(x){...}.
In my script, the function calls:
- one variable coming from the data.frame
- variables coming from lists or constant outside the
Many thanks David,
But I am not sure the Dataset and newdata are the real problem. I have solved,
at least I think so, what you were asking. Here below my new R code but still
the same error message. IMHO the problem is with "boot.ci" function...
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