Re: [R] Rotation Forest Error Message

Just re-read your question and realized I misread the error message. The argument is of zero length. But the conclusion is the same, either a bug in the package, or a problem with your input. On Fri, Aug 21, 2020 at 4:16 PM Abby Spurdle wrote: > > Note that I'm not familiar with this package

Re: [R] Rotation Forest Error Message

Note that I'm not familiar with this package or the method. Also note that you haven't told anyone what function you're using, or what your call was. I'm assuming that you're using the rotationForest() function. According to its help page, the default is: K = round(ncol(x)/3, 0) There's no

[R] Rotation Forest Error Message

Hi R Helpers, I wanted to try the rotationForest package. I pointed it at my data set and got the error message "Error in if (K >= ncol(x)) stop("K should not be greater than or equal to the number of columns in x") : argument is of length zero'. My dataset has 3688 obs. of 111 variables.

Re: [R] & and |

The single grep regex solutions offered to Ivan's problem were fine, but do not readily generalize to the conjunction of multiple (>2, say) regex patterns that can appear anywhere in a string and in any order. However, note that this can easily be done using the Perl zero width lookahead

Re: [R] combine filter() and select()

On Wed, Aug 19, 2020 at 10:03 AM Ivan Calandra wrote: > > Dear useRs, > > I'm new to the tidyverse world and I need some help on basic things. > > I have the following tibble: > mytbl <- structure(list(files = c("a", "b", "c", "d", "e", "f"), prop = > 1:6), row.names = c(NA, -6L), class =

[R-es] Puntos de corte de dos curvas de densidad

Buenas tardes, tengo una variable bimodal (*var)*, de presencias y ausencias (1s y 0s) y otra variable, *prob*, con las probabilidades (entre 0 y 1) que le asigna un modelo. Con: *ggplot(Preds, aes(x=prob, fill= var )) + geom_density(alpha=.3)* obtengo la distribución de las presencias y de las

[R] [R-pkgs] skedastic: Heteroskedasticity Diagnostics for Linear Regression Models

Dear All, Allow me to re-introduce the skedastic package (version 1.0.0) which now implements more than 20 different heteroskedasticity tests for the linear regression model, as well as a graphical diagnostic tool and some helper functions with broader applications (e.g., computing probability

Re: [R] select() columns using their positions

Hello, It is also possible to select by vectors of indices (as opposed to a vector): top_n is just to not clutter the display. library(dplyr) data(iris) iris %>% select(1, 3, 4) %>% top_n(5) iris %>% select(c(1, 3), 4) %>% top_n(5) Hope this helps, Rui Barradas Às 10:05 de 20/08/20,

Re: [R] how to prove sum of probabilities to be one in R?

On 20/08/2020 3:42 a.m., Shaami wrote: > Hi Dear > > I am facing a floating-point problem related to the sum of probabilities. > It is really difficult to prove that sum of probabilities is 1 because of > some minor differences. The MWE is as follows. > >> p1=0. >> p2=0.003>

Re: [R] combine filter() and select()

A kind of hybrid answer is to use base::subset(), which supports non-standard evaluation (it searches for unquoted symbols like 'files' in the code line below in the object that is its first argument; %>% puts 'mytbl' in that first position) and row (filter) and column (select) subsets > mytbl

[R] how to prove sum of probabilities to be one in R?

Hi Dear I am facing a floating-point problem related to the sum of probabilities. It is really difficult to prove that sum of probabilities is 1 because of some minor differences. The MWE is as follows. > p1=0. > p2=0.003> p1+p2==1[1] FALSE The sum of probabilities is

Re: [R] select() columns using their positions

OK, my bad... I'm sure I had tried it and it didn't work, but I guess the error was somewhere else... Thank you! Ivan -- Dr. Ivan Calandra TraCEr, laboratory for Traceology and Controlled Experiments MONREPOS Archaeological Research Centre and Museum for Human Behavioural Evolution Schloss

Re: [R] select() columns using their positions

Did you try it? mydata %>%   select( c( 1, 2, 4 ) ) On August 20, 2020 1:41:13 AM PDT, Ivan Calandra wrote: >Dear useRs, > >I'm still trying to learn tidyverse syntax. > >I would like to select() columns based on their positions/indices, but >I >cannot find a way to do that (I've seen a lot

[R] select() columns using their positions

Dear useRs, I'm still trying to learn tidyverse syntax. I would like to select() columns based on their positions/indices, but I cannot find a way to do that (I've seen a lot about doing that for rows, but I could not find anything for columns). I thought it would be obvious, but I cannot find

Re: [R] combine filter() and select()

Hi Jeff, The code you show is exactly what I usually do, in base R; but I wanted to play with tidyverse to learn it (and also understand when it makes sense and when it doesn't). And yes, of course, in the example I gave, I end up with a 1-cell tibble, which could be better extracted as a

Re: [R] combine filter() and select()

Dear Chris, I didn't think about having the assignment at the end as you showed; it indeed fits the pipe workflow better. By "easy", I actually meant shorter. As you said, in base R, I usually do that in 1 line, so I was hoping to do the same in tidyverse. But I'm glad to hear that I'm using

Re: [R] & and |

Thank you all for all the very helpful answers! Best, Ivan -- Dr. Ivan Calandra TraCEr, laboratory for Traceology and Controlled Experiments MONREPOS Archaeological Research Centre and Museum for Human Behavioural Evolution Schloss Monrepos 56567 Neuwied, Germany +49 (0) 2631 9772-243