Bill pointed out some errors in your code but you keep making the claim that
-MM-DD is not recognized and I just want to make it completely clear that
that is the default format for dates in R as it is an ISO standard. So focus on
other issues until you get it working... this format is defin
Please disregard my previous post. My understanding is correct, and the
behavior is **AS DOCUMENTED**.
I failed to read the docs carefully. Mea Culpa.
Best,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley
I would appreciate any help in correcting my misunderstanding of the
following:
> substitute(quote(x+a), env = list(a=5))
quote(x + 5) ## as expected
> substitute(quote(x+a), env = list2env(list(a=5)))
quote(x + 5) ## as expected
> ### BUT
> .GlobalEnv$a
[1] 5
> substitute(quote(x+a), env = .Gl
Hi Gregory,
On Mon, Dec 14, 2020 at 12:34 PM Gregory Coats wrote:
>...
> Is there a convenient way to tell R to interpret “2020-12-13” as a date?
>
Notice the as.Date command in the code I sent to you. this converts a
string to a date with a resolution of one day. If you want a higher
time resolu
You left out some calls to c(). Note that
(2,3,5)
is not valid syntax for making a vector of numbers; use
c(2,3,5)
You also left out a comma and gave different lengths for day and value.
You also left out plus signs between the various components of your ggplot
expression.
Try
data <- data
Hi Jim,
Thank you VERY much!
In what I tried, my values for the vertical Y were automatically understood by
R.
But it appears that the string -mm-dd was NOT recognized by R as a date for
the X axis, and gave a red error message.
My values for Year-Month-Day were NOT understood by R.
Is there
David,
Great suggestion!
Thanks,
Brian
On Dec 13, 2020, at 6:06 PM, David Winsemius
mailto:dwinsem...@comcast.net>> wrote:
On 12/13/20 12:49 PM, Brian Beckage wrote:
As an example to illustrate my question, if I used the following code to plot
the price of Apple stock using the tidyquan
On 12/13/2020 12:49 PM, Brian Beckage wrote:
As an example to illustrate my question, if I used the following code to plot
the price of Apple stock using the tidyquant package and ggplot2
AAPL<-tq_get(x="AAPL")
AAPL %>%
ggplot(aes(x = date, y = close)) +
geom_line() +
labs(title = "A
1. Please read and follow the posting guide linked below.
2. No html -- this is a plain text list.
3. Use ?dput to provide us your data so that we don't have to convert it
for you.
4. We expect you to first make an effort to do your own coding. See
?t.test, which you could also
have found yourself
By converting the character date data into a time-like type... e.g. ?as.Date
and plotting y-vs-x.
On December 12, 2020 11:18:46 AM PST, Gregory Coats via R-help
wrote:
>Starting with year-month-day, for the variable gallons, I can easily
>plot the variable gallons, while disregarding the date.
On 12/13/20 12:49 PM, Brian Beckage wrote:
As an example to illustrate my question, if I used the following code to plot
the price of Apple stock using the tidyquant package and ggplot2
AAPL<-tq_get(x="AAPL")
AAPL %>%
ggplot(aes(x = date, y = close)) +
geom_line() +
labs(title = "A
Hi Gregory,
Here's a start:
gcdf<-read.table(text="2020-01-05 15.973
2020-02-15 18.832
2020-03-10 17.392
2020-05-04 14.774
2020-06-21 19.248
2020-08-01 14.913
2020-08-27 15.226
2020-09-28 14.338
2020-11-09 18.777
2020-12-11 19.652",
header=TRUE,stringsAsFactors=FALSE,
col.names=c("date","gallons")
Dear R users,
I would like to ask for help with the code of multiple t-test. I have a
dataset as followed:
Species Treatment var1 var2 var2 var4 var5 var6
Blue D 0.022620093 0.125079631 0.04522571 0.010105835 0.013418019
1.455646741
Blue D 0.02117295 0.073544277 0.0311234 0.008742305 0.03261776 0.9
Starting with year-month-day, for the variable gallons, I can easily plot the
variable gallons, while disregarding the date.
gallons <- c (15.973, 18.832, 17.392, 14.774, 19.248, 14.913, 15.226, 14.338,
18.777, 19.652)
plot (gallons, type="l", xlab="X label", ylab="Y label", col="blue”)
How do
As an example to illustrate my question, if I used the following code to plot
the price of Apple stock using the tidyquant package and ggplot2
AAPL<-tq_get(x="AAPL")
AAPL %>%
ggplot(aes(x = date, y = close)) +
geom_line() +
labs(title = "AAPL", y = "Closing Price", x = "") +
coord_x_dat
15 matches
Mail list logo