On 24/07/2021 5:40 p.m., Rui Barradas wrote:
Hello,
No, it's not possible to work with a matrix in ggplot2.
Not even with an object of class "list".
If that's the main thing Jeff is doing, then he should convert to a
dataframe. But it *is* possible to work with the original matrix in
Thanks for the tips
-Original Message-
From: Rui Barradas
Sent: Saturday, July 24, 2021 11:40 AM
To: reichm...@sbcglobal.net; R-help@r-project.org
Subject: Re: [R] Converting a list to a data frame
Hello,
This should do it:
as.data.frame(weight_chains$mcmc)
The only list member
Hello,
No, it's not possible to work with a matrix in ggplot2.
Not even with an object of class "list".
l <- list(x=1:5, y=1:5)
d <- as.data.frame(l)
m <- as.matrix(d)
library(ggplot2)
ggplot(l, aes(x, y)) + geom_point() # Error
ggplot(d, aes(x, y)) + geom_point() # OK, as expected
Duncan
I need to plot the results (ggplot2) and I'm thinking I can only use a
data.frame object in ggplot2. It is a rath r large "list" over 1 million rows.
It is possible to work with a matrix in ggplot2?
Jeff
-Original Message-
From: Duncan Murdoch
Sent: Saturday, July 24, 2021
Hello,
You can use stat_function, it will take care of all the details, all you
have to do is to pass xlim.
library(ggplot2)
library(cowplot)
ggplot() +
stat_function(fun = sin, xlim = c(0, pi)) +
xlab("x") +
ylab("sin(x)") +
scale_x_continuous(breaks = seq(0, pi, pi/6), labels =
This is not excel-help, but to the best of my knowledge Excel interpolates with
splines when you select curved point interpolation.
R, being primarily a science tool rather than a business tool, assumes you want
to be precise about how new points are to be interpolated between original data
plot(sin, to=pi) # also works but with x labeled in radians.
# With x axis labeled in degrees
plot(sin, to=pi, axes=FALSE)
axis(2)
lbls <- seq(0, 180, 30)
axis(1, pi*lbls/180, lbls)
This can probably be done in ggplot2, but I don't know how off the
top of my head.
Hope this
Alternatively with base graphics
N <- 500 ## number of points (arbitrary)
degrees <- seq(from=0,to=180,length=N)
degreesToRadians <- function(d) { pi * d / 180.0} ## vectorIzed!
plot(x=degrees,y=sin(degreesToRadians(degrees)),type='l',
xlab="x",ylab="sin(x)",main="sin(x) vs x\nx is in
Try something like the following
copdat$degrees <- c(1:180)
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Professor of Medicine
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology and Geriatric
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Colleagues,
Here is my code which plots sin(x) vs x, for angles between 0 and 180
degrees.
library(ggplot2)
library(REdaS)
copdat$degrees <- c(0,45,90,135,180)
copdat$radians <- deg2rad(copdat$degrees)
copdat$sin_x <- sin(copdat$radians)
ggplot(copdat,aes(x=degrees,y=sin_x))+
geom_point(size
Others have shown you how to extract the matrix and convert it to a
dataframe. My only addition is to suggest that you don't do this:
matrix methods are often much more efficient than dataframe methods, so
if you can work with the matrix without conversion, you'll often find
things run a lot
Hello,
This should do it:
as.data.frame(weight_chains$mcmc)
The only list member already has a dim attribute of length 2 and
dimnames' 2nd member are the colnames, just coerce to df.
Hope this helps,
Rui Barradas
Às 14:18 de 24/07/21, Jeff Reichman escreveu:
How does one convert a list
On 24/07/2021 11:22 a.m., Andrew Simmons wrote:
Hello,
I was wondering if anyone has a way to test if a package is currently being
installed. My solution was to check if environment variable "R_INSTALL_PKG"
was unset, something like:
"R CMD INSTALL-ing" <- function ()
Does ?installed.packages help?
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sat, Jul 24, 2021 at 8:30 AM Andrew Simmons wrote:
> Hello,
>
>
> I was
On Sat, 24 Jul 2021 11:19:41 + (UTC)
Bintao Cui via R-help wrote:
> Makefile.in:87: *** missing separator. Stop.
Thanks for showing us the error message, but this isn't enough
information. In order to be able to help, we also need to know what
exactly you did to get the error message.
Hello,
I was wondering if anyone has a way to test if a package is currently being
installed. My solution was to check if environment variable "R_INSTALL_PKG"
was unset, something like:
"R CMD INSTALL-ing" <- function ()
!is.na(Sys.getenv("R_INSTALL_PKG", NA))
Unfortunately, I couldn't find
Makefile.in:87: *** missing separator. Stop.
I am trying to install R-4.1.0 version to fedora, and got the error above,
please help!
Thanks.
With regards,Bintao
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
Here is a reprex that does what I think you want:
ex <- list(mcmc = matrix(1:12, ncol = 3, byrow=TRUE),
NULL, c("a","b", "s"))
dex <- data.frame(ex$mcmc)
names(dex) <- ex[[3]]
> dex
a b s
1 1 2 3
2 4 5 6
3 7 8 9
4 10 11 12
If this is not correct, you should provide a
How does one convert a list into a data frame?
> str(weight_chains)
List of 1
$ : 'mcmc' num [1:10, 1:3] -105 -105 -105 -104 -103 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:3] "a" "b" "s"
..- attr(*, "mcpar")= num [1:3] 1001 101000 1
- attr(*,
Thanks a lot Sir, indeed it resolved my issue.
Warm regards
On Sat, Jul 24, 2021 at 1:51 PM Rui Barradas wrote:
> Hello,
>
> Simply by also passing a vector to the extraction function:
>
>
> rows= df[c(1,2,5,7,12) , ]
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 12:38 de 24/07/21, Neha gupta
Hello,
Simply by also passing a vector to the extraction function:
rows= df[c(1,2,5,7,12) , ]
Hope this helps,
Rui Barradas
Às 12:38 de 24/07/21, Neha gupta escreveu:
Hi
If I have to select specific rows and all columns of a dataframe, I use:
rows= df[1:12 , ]
However, how to select
Hi
If I have to select specific rows and all columns of a dataframe, I use:
rows= df[1:12 , ]
However, how to select rows if our required rows are not in sequence i.e.
if we need to select row numbers 1,2,5,7, and 12..
Warm regards
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