On Linux, if I have a .so file that has a dependency on another .so, and I
`dyn.load(now=FALSE)` the first one, R seems to try to resolve the symbols
immediately, causing the load to fail.
For example, I have `libtorch` installed on my HPC. Note that it links to
various libs such as `libcudart.so`
Or directly to bugs.r-project.org . It definitely looks to me like a bug.
Instructions for bug reports are here:
https://www.r-project.org/bugs.html . David might need to set up a
Bugzilla account according to those instructions before reporting.
Duncan Murdoch
On 31/01/2023 1:40 p.m., Ber
This post should probably go to R-devel rather than here.
-- Bert
On Tue, Jan 31, 2023 at 9:47 AM David Engster wrote:
> I think I found a bug in the internal implementation of 'tar', but
> before bothering the R maintainers, I was advised to ask here to make
> sure I'm not missing something.
>
On Tue, 31 Jan 2023 13:12:46 +
Phil Smith via R-help wrote:
> Some of these install with no problem. However, most of them give an
> error messages that looks like:
>
> Warning in install.packages :
> installation of package ‘curl’ had non-zero exit status
I'm using my psychic debugging
Hello R-Help People!
I had to reinstall my operating system... and reinstall R.
I am having trouble with reinstalling packages:
install.packages(c( "curl"))
install.packages(c( "quantmod"))
install.packages(c( "TTR"))
install.packages(c( "xts"))
install.packages(c( "zoo"))
install.packages(c( "t
I think I found a bug in the internal implementation of 'tar', but
before bothering the R maintainers, I was advised to ask here to make
sure I'm not missing something.
Fortunately, it can be very easily reproduced on a Linux system. In an
empty temporary directory, execute the following code:
ca
Very true,
Carolyn J. Miller
M.S. Student, Ecology
SUNY-ESF, Environmental Biology
From: Bert Gunter
Sent: Tuesday, January 31, 2023 10:46 AM
To: Carolyn J Miller
Cc: Boris Steipe ; r-help@r-project.org
Subject: Re: [R] question
"The combination of some data
"The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of data."
John Tukey
Cheers,
Bert
On Tue, Jan 31, 2023 at 7:44 AM Carolyn J Miller via R-help <
r-help@r-project.org> wrote:
> Hi Boris,
>
> It's hair cor
Hi Boris,
It's hair cortisol so it shouldn't have an effect. My study species are
ungulates, which retain their coat through the winter into the spring shedding
out around April/May so in theory these two sampling periods should provide the
same results as hair cort provides an average of accum
Perhaps, rather than looking to compress your observations into a single
number, you could simply visualize what you observed: use a boxplot to show the
March and December observations, and overlay the three animals that were
recaptured as individual points, connected with a line.
Feel free to
Thank you!
Carolyn J. Miller
M.S. Student, Ecology
SUNY-ESF, Environmental Biology
From: Ebert,Timothy Aaron
Sent: Tuesday, January 31, 2023 9:50 AM
To: Carolyn J Miller ; PIKAL Petr ;
r-help@r-project.org
Subject: RE: question
As indicated here:
https://ww
As indicated here:
https://www.geeksforgeeks.org/compute-the-correlation-coefficient-value-between-two-vectors-in-r-programming-cor-function/
The cor() function needs two vectors. The only way that works is if you are
looking at the correlation between "Month" and "Cort."
If you interested in the
Hi Timothy,
Here's some example data that might help to demonstrate how the data currently
looks.
AnimalIDMonth Cort
1 12 0.00591
1 3 0.00583
2 3 0.005722
3 3 0.005838
4 3 0.005873
4 12 0.0059
5 3 0.00572
Thank you Petr!
On Tue, Jan 31, 2023 at 11:58 AM PIKAL Petr wrote:
> Hi Konstantinos
>
> Not exactly derivative but
> > diff(df[,2])
> [1] -0.01 -0.01 -0.01 -0.01 0.00 0.01 -0.02 -0.03 -0.02
>
> May be enaough for you.
>
> Cheers
> Petr
>
> >
> > -Original Message-
> > From: R-help On
Hi Ivan!
Thank you for your valuable insights! I look forward to learning more about
numerical differentiation and about this subject.
The pracma package and the fornberg() function is impressive. I got some
really good approximations on my derivatives.
Thank you!
Kostas
On Tue, Jan 31, 2023 at
Hi Andrew,
I applied your command in another dataset with known derivative values and
it gave me very satisfactory results!
Therefore, I will use it on my dataset. Thank you so much!
Kostas
On Tue, Jan 31, 2023 at 12:22 PM Andrew Robinson
wrote:
> Try something like
>
> with(df, predict(smoo
Try something like
with(df, predict(smooth.spline(x = altitude, y = atm_values), deriv = 1))
Cheers,
Andrew
--
Andrew Robinson
Chief Executive Officer, CEBRA and Professor of Biosecurity,
School/s of BioSciences and Mathematics & Statistics
University of Melbourne, VIC 3010 Australia
Tel: (+61)
В Tue, 31 Jan 2023 11:16:21 +0200
konstantinos christodoulou
пишет:
> How can I find the derivatives of the atmospheric measurements at each
> altitude?
Welcome to the world of finite difference methods! If you can find a
good textbook on them, it may be a good idea to skim it.
pracma::fornberg
Hi Konstantinos
Not exactly derivative but
> diff(df[,2])
[1] -0.01 -0.01 -0.01 -0.01 0.00 0.01 -0.02 -0.03 -0.02
May be enaough for you.
Cheers
Petr
>
> -Original Message-
> From: R-help On Behalf Of konstantinos
> christodoulou
> Sent: Tuesday, January 31, 2023 10:16 AM
> To: r-hel
Hi everyone,
I have a vector with atmospheric measurements (x-axis) that is
obtained/calculated at different altitudes (y-axis). The altitude is
uniformly distributed every 7 meters.
For example my dataframe is:
df <- dataframe(
*altitude* = c(1005, 1012, 1019, 1026, 1033, 1040, 1047, 1054, 1061,
Dear all,
my new R package LGDtoolkit is now on CRAN.
The goal of this package is to cover the most common steps in Loss Given
Default (LGD) rating model development. The main procedures available are
those that refer to bivariate and multivariate analysis.
In particular two statistical methods f
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