Would this work?
xxxz$Average20 <- (xxxz$Low20 + xxxz$High20)/2
I tried this earlier but it does not appear to have gone through.
Tim
-Original Message-
From: R-help On Behalf Of avi.e.gr...@gmail.com
Sent: Saturday, June 8, 2024 2:16 PM
To: 'Sorkin, John' ; r-help@r-project.org
Can this problem be made more direct?
xxxz$Average.20 <- (xxxz$Low20 + xxxz$High20)/2
That is literally the mean of two columns. Functions can be useful if there
will be more columns, but with just two this seems easier.
I will point out that the average daily temperature based on the midpoint
John,
Maybe you can clarify what you want the output to look like. It took me a
while to realize what you may want as it is NOT properly described as
wanting rowsums.
There is a standard function called rowMeans() that probably does what you
want if you want the mean of all rows as in:
>
Incidentally, FWIW, for means, rowMeans() is a lot faster:
xxxz$av20 <- rowMeans(xxxz[,c("Low20","High20")])
Bert
On Sat, Jun 8, 2024 at 10:47 AM Bert Gunter wrote:
> Use apply(), not by().
>
> xxxz$av20 <- apply(xxxz[,c("Low20","High20")],1, mean)
>
> -- Bert
>
> On Sat, Jun 8, 2024 at
Use apply(), not by().
xxxz$av20 <- apply(xxxz[,c("Low20","High20")],1, mean)
-- Bert
On Sat, Jun 8, 2024 at 10:38 AM Sorkin, John
wrote:
> I have a data frame with three columns, TotalInches, Low20, High20. For
> each row of the dataset, I am trying to compute the mean of Low20 and
> High20.
I have a data frame with three columns, TotalInches, Low20, High20. For each
row of the dataset, I am trying to compute the mean of Low20 and High20.
xxxz <- structure(list(TotalInches =
c(58, 59, 60, 61, 62, 63, 64, 65,
66, 67, 68, 69, 70, 71, 72, 73, 74,
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