On 27/10/14 19:42, Camilo Mora wrote:
> Hi Bart,
>
> Even after putting the variables in the apply function, the results come not
> right:
>
> library (alphahull)
> DT=data.frame(x=c(0.25,0.25,0.75,0.75),y=c(0.25,0.75,0.75,0.25))
> Hull <- ahull(DT, alpha = 0.5)
>
> TEST<- data.frame(x=c(0.25,0
On 27/10/14 06:05, Camilo Mora wrote:
> Hi everyone,
>
> I have a two column (x,y) database with say 20 million rows. I want to check
> the points that are inside of a hull created with the package alphahull. The
> function that does this is call �inahull�, and it runs well when I use it for
>
On 24/09/14 16:13, Sohail Khan wrote:
> Dear All,
>
> I have clustered a patient data set by agnes.
>
> I want to extract information for each cluster, I.E. all row ids
> belonging to each cluster.
Fascinating, thank you for sharing.
Best,
Bart
__
R-
On 22 Aug 2014, at 12:39, Duncan Murdoch wrote:
> On 22/08/2014, 6:02 AM, Bart Kastermans wrote:
>> I have a daily generated report in which I put a check using stopifnot.
>> Unfortunately
>> I didn’t check the effect very well, turns out that if the condition checked
&g
I have a daily generated report in which I put a check using stopifnot.
Unfortunately
I didn’t check the effect very well, turns out that if the condition checked
fails
this is not shown in the knitr output (I only get an error much later due to a
missing
object).
So my question is, what is th
Better:
b <- c(a[1]-1,a[-length(a)])
On 07 Aug 2014, at 17:28, Bart Kastermans wrote:
> For readability I like:
>
>> b <- c(0,a[-length(a)])
>> which(a != b & a == 0)
> [1] 4 12 18
>> which(a != b & a == 1)
> [1] 1 6 16 23
>
>
> On 0
For readability I like:
> b <- c(0,a[-length(a)])
> which(a != b & a == 0)
[1] 4 12 18
> which(a != b & a == 1)
[1] 1 6 16 23
On 07 Aug 2014, at 17:23, William Dunlap wrote:
> My solution may be a bit clearer if you define the function isFirstInRun
> isFirstInRun <- function(x) {
> if (le
On 19 Jun 2014, at 15:42, message wrote:
> Readers,
>
> For data set:
>
> a, 90, 10
> b, 60, 40
> c, ,
> d, , 50
>
> A plot was attempted:
Wonder who attempted this. :-)
>
> dataset<-as.matrix(read.csv("datafile.csv",header=FALSE))
Look at your dataset; I’d say it is clearly not what you w
he answer should have the elements of tm.1 with the following indexes
> 1,1 1,3
> 2,1 2,3
> 3,1 3,3
In that example:
> t(apply(tm.1, 1, function(x) x[x>0]))
[,1] [,2]
[1,]12
[2,]12
[3,]12
> class(t(apply(tm.1, 1, function(x) x[x>0])))
[1] "m
s a vector which is useless as I want a matrix.
>
>
> On Thursday, June 19, 2014 2:40 PM, Bart Kastermans
> wrote:
>
>
> > tm.1 <- matrix(c(11,22,33,-4), ncol=2)
> > which(tm.1 > 0, arr.ind=TRUE)
> row col
> [1,] 1 1
> [2,] 2 1
> [3,] 1 2
>
On 19 Jun 2014, at 13:19, carol white wrote:
> Hi,
> Is there a way to extract a subset of non-contiguous elements of a matrix
> elegantly and with 1 or very few scripts?
>
> Suppose I have a matrix of positive and negative numbers (m) and I want to
> retrieve only the positive number. This I
s" you'll learn more bad habits than good ones if
> you examine my packages…
>
> Max
>
> On Fri, Jun 6, 2014 at 2:42 PM, Duncan Murdoch
> wrote:
>> On 06/06/2014 10:26 AM, Bart Kastermans wrote:
>>>
>>> To improve my R skills I try to understand s
To improve my R skills I try to understand some R code written by others.
Mostly
I am looking at the code of packages I use. Today I looked at the code for the
caret package
http://cran.r-project.org/src/contrib/caret_6.0-30.tar.gz
in particular at the file R/adaptive.R
This file starts with:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA512
On 8/5/13 1:00 PM, Anindya Sankar Dey wrote:
> Hi All,
>
> I applied the naiveBayes function in e1071 package with the iris
> data, and here's the list that was created
>
> structure(list(apriori = structure(c(50L, 50L, 50L), .Dim = 3L,
> .Dimnam
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