use sapply.
>
> R can assign names through vectors:
>
> names(y) <- names(x)
>
> Or:
>
> names(y) <- c("NameA","NameB")
>
> Regards,
>
> Wu
>
>
>
>
> From: Carlos Petti [carlos.p
Or rather :
n <- sapply(x, function(i) names(i))
tapply(x, n, names)
2010/8/11 Carlos Petti :
> A beginning of solution...
>
> n <- sapply(x, function(i) names(i))
> tapply(x, n, c)
>
> 2010/8/11 Carlos Petti :
>> Thanks.
>>
>> On the other hand,
>&g
A beginning of solution...
n <- sapply(x, function(i) names(i))
tapply(x, n, c)
2010/8/11 Carlos Petti :
> Thanks.
>
> On the other hand,
> I try to obtain the same result but from this list :
>
> x <- list()
> x$i <- 5
> x$j <- 9
> x$k <- 15
> name
>
> I give a handmade code, hope it helps.
>
> y <- list()
> y$a <- a
> y$b <- c(b,c)
> names(y$a) <- "i"
> names(y$b) <- c("j","k")
>
>
> Carlos Petti wrote:
>>
>> a <- 5
>> names(a) <- "a&q
Dear list,
I have a list, as follows :
a <- 5
names(a) <- "a"
b <- 9
names(b) <- "b"
c <- 15
names(c) <- "c"
x <- list("i" = a, "j" = b, "j" = c)
I want to invert the list, like this :
$a
i
5
$b
j k
9 15
I do not find a clean solution.
Could anyone give me elegant ideas ?
Thanks in advance
-- Forwarded message --
From: Carlos Petti
Date: 2010/8/10
Subject: Re: [R] List of lists ?
To: David Winsemius
Perhaps a solution :
x <- list()
x[[2]] <- list()
x[[2]][[1]] <- c(1, 2, 3)
x[[2]][[2]] <- c(3, 2, 1)
2010/8/10 Carlos Petti :
> Thanks for answer.
-- Forwarded message --
From: Carlos Petti
Date: 2010/8/10
Subject: Re: [R] List of lists ?
To: David Winsemius
Thanks for answer.
I read the error messages but I did not find the solution :-(
Your solution works.
But, a new problem remains because I want
to use the list of
Dear list,
I have to use a list of lists containing vectors.
For instance :
[[1]]
[[1]][[1]]
[1] 1 2 3
[[1]][[2]]
[1] 3 2 1
I want to attribute vectors to the main list
without use of an intermediate list,
but it does not work :
x <- list()
x[[1]][[1]] <- c(1, 2, 3)
x[[1]][[2]] <- c(3, 2, 1
Dear list,
I have a list of matrices :
i1 <- matrix(1:10, nrow = 2, ncol = 5)
i2 <- matrix(11:20, nrow = 2, ncol = 5)
j <- list(i1 = i1, i2 = i2)
I would like to attribute names to each dimension, for each matrix,
as follows :
$i1
B1 B2 B3 B4 B5
A1 1 3 5 7 9
A2 2 4 6 8 10
$i2
B1 B2 B3 B4 B5
A1
Dear list,
Thank you for your answers.
Petr, your solution works great :-)
Peter's solution too.
Carlos
2010/3/17 Ivan Calandra
> Now I get it, I was still thinking you wanted two columns. I was confused
> by the "print" example.
> Petr's suggestion works well then
> Ivan
>
> Le 3/17/2010 11
Dear list,
Sorry, I did not explain myself very well.
I want to obtain a data.frame like this :
Freq
a1
b1
c1
This data.frame contains just one column (Freq) and each row is named.
But when I use this code :
df <- as.data.frame(t)
or this code :
df <- as.data.frame(t, row.names(
Dear list,
I have a contingency table :
a <- letters[1:3]
t <- table(a)
I'm looking for a way to transform this table into data frame, as follows :
Freq
a1
b1
c1
I used :
df <- as.data.frame(t, row.names = names(t))
But, this function do not remove the duplicated column. Do you
Dear list,
I have a list of three matrices :
i = list(matrix(1:4,2,2), matrix(3:6,2,2), matrix(9:12,2,2))
I would like to sum the matrices, as follows :
[,1] [,2]
[1,] 13 19
[2,] 16 22
I used this code :
k <- i[[1]]
for (j in (2:length(i))) {
k <- k + i[[j]]}
But, is it possible to sum witho
r2<-f2(iBig,jBig))
user system elapsed
0.084 0.004 0.088
2010/3/5 William Dunlap
> > -Original Message-
> > From: r-help-boun...@r-project.org
> > [mailto:r-help-boun...@r-project.org] On Behalf Of Carlos Petti
> > Sent: Friday, March 05, 2010 9:43 AM
> >
Dear list,
I have a vector of characters and a list of two named elements :
i <- c("a","a","b","b","b","c","c","d")
j <- list(j1 = c("a","c"), j2 = c("b","d"))
I'm looking for a fast way to obtain a vector with names, as follows :
[1] "j1" "j1" "j2" "j2" "j2" "j1" "j1" "j2"
I used :
match <-
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