On Apr 10, 2012, at 1:08 PM, Steve Lavrenz wrote:
I definitely need a loop - the example I gave was only a simple
one. Say I
want to do more complex calculations in each step, such that the
numeric
difference between consecutive terms is not constant.
I will try out some of the methods th
http://lmdvr.r-forge.r-project.org/figures/figures.html
Look at Figure 10.24 and the code therein. You will likely want to
define your own strip function, and the code in strip.combined could
be your guide. If you have Deepayan's book, you can find more details
in the relevant section.
H
R-FAQ 7.10:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-convert-factors-
to-numeric_003f
On Oct 9, 2008, at 6:59 AM, joseph kambeitz wrote:
I am having some problems while trying to fit simple data.
I aggregated some data using:
data1 <- aggregate(data1$T2, list=(SOA=data1$SOA), mea
I think the problem is that what you describe is not what some
people, R folks included, refer to as "dotplot", though I suppose
wikipedia as well as some other top google links seem to agree with
you and minitab. What you describe I think can be obtained with
something like:
x<- c(6,6,4,
Actually the '\\textbf' specification would work just fine. If you
examine test[,1] you'll see it contains the correct thing. The
problem is when print.xtable is called. This is because it
automatically contains a function that "sanitizes" the character
entries to "fix" characters that have
So, am I correct that each datum is either of the form "mm/dd/yy" or
of the form "dd/mm/"? If that is correct, then the following
should work, and takes care of converting 99 to 1999 instead of 2099:
dates <- c("06/15/07","04/09/99","20/03/2008")
short <- grep("\\d\\d/\\d\\d/\\d\\d$", dat
As suggested in ?"[.data.frame", try:
dat[match('a1', rownames(dat)),]
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On Sep 9, 2008, at 2:41 AM, Xianming Wei wrote:
Hi all,
While dat['a1',] and dat['a10',] produce the same results in the
following example, I'd
Try: license()
On Sep 3, 2008, at 6:59 PM, Erin Hodgess wrote:
Dear R People:
I am trying to install R in a classroom here, but have been told that
there must be a license.
Is there such a thing with R, please? Since it is free, I "assumed"
that there would be no license.
Thanks for any hel
Try:
myStr <- "YD\\(001\\)"
In POSIX format, or in most such formats in fact, special characters
like parentheses have a particular meaning, and need to be escaped if
they are to have the "parenthesis" meaning. This is done typically by
putting a backslash in front of them. Since however a
On Aug 27, 2008, at 10:40 PM, Rolf Turner wrote:
On 28/08/2008, at 2:02 PM, James Milks wrote:
The title says it all. Does anyone know of a way to save your
packages when you upgrade to a new version of R? This may seem
petty, but I'm accumulating enough packages that having to
downloa
On Jul 29, 2008, at 5:24 AM, Edna Bell wrote:
Hi R Gurus!
When you build a package, you need to put in keywords in the Rd files.
Where would you find the list of keywords, please?
Simplest way is to google for "r keywords". First hit is:
http://www.stat.ucl.ac.be/ISdidactique/Rhelp/doc/keyw
On Jun 27, 2008, at 1:44 PM, baptiste Auguié wrote:
DeaR list,
Pardon the stupidity of this question but I've been trying this for
a while now without success.
I've followed the example given in the green book "programming with
data", and I now have a working example of a S4 class with a
One more advantage of TextMate is support for Sweave files. You can
have a Sweave file open, and the LaTeX parts of it are syntax colored
according to LaTeX and one can use all the facilities of the LaTeX
extension (bundle) in LaTeX (which probably has some things similar
to AucTeX, has a n
On Jun 17, 2008, at 8:06 AM, Chuck Cleland wrote:
On 6/17/2008 6:59 AM, Steve Murray wrote:
Dear all,
I have used 'read.table' to create a data frame of 720 columns and
360 rows (and assigned this to 'Jan'). The row and column names
are numeric:
columnnames <- sprintf("%.2f", seq(from = -17
On Jun 16, 2008, at 12:13 PM, Lord Yo wrote:
Hello everyone
I have dataset containing a monetary value (ABS) and two factors (Fct,
Group). I am able to create useful using:
bwplot(ABS~Group|Fct)
and
dotplot(ABS~Group|Fct)
Question: What do I have to do to overlay the dotplot with the
bwpl
ere?
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
Charilaos Skiadas-3 wrote:
On Jun 14, 2008, at 1:25 AM, T.D.Rudolph wrote:
aggregate() is indeed a useful function in this case, but it only
returns the
columns by which it was grouped. Is there a way I
On Jun 14, 2008, at 1:25 AM, T.D.Rudolph wrote:
aggregate() is indeed a useful function in this case, but it only
returns the
columns by which it was grouped. Is there a way I can use this while
simultaneously retaining all the other column values in the dataframe?
e.g. add superfluous (y
?"%%"
On Jun 13, 2008, at 11:23 AM, Eric Ferreira wrote:
Dear useRs,
How do I ask for the rest of a division?
For instantce, in C is like:
4%2 = 0
Best regards,
--
Eric B Ferreira
Exact Sciences Department
Federal University of Lavras
Brasil
Haris Skiadas
Department of Mathematics and C
On Jun 12, 2008, at 6:34 PM, Hua Li wrote:
Thanks, Marc and Haris!
I didn't know the values of the numbers beforehand, so the scan
method won't work, but "[^+-\\d.]+" will do!
And Haris, I didn't intend to keep the information of which number
is B, which is C etc when asking the question,
On Jun 12, 2008, at 5:06 PM, Marc Schwartz wrote:
on 06/12/2008 03:46 PM Hua Li wrote:
Hi,
I'm looking for some way to pick up the numbers which are
contained and buried in a long character. For example,
outtree.new="(((B:1204.25,E:1204.25):7581.11,F:8785.36):8353.85,C:
17139.21);"
num.char
I believe this might do what you want a bit faster. I replaced the
while loop with something that is likely to be faster. I saw no
reason for the rounding you were doing, better to use as.integer at
the end.
test <- function(t){
x <- rexp(t,0.1)
while(sum(x) <= t) {
x <- c(x, rexp(
On Jun 12, 2008, at 10:48 AM, Julien Hunt wrote:
Do you
need more information on my specific program.
Thanks for your time and help,
Yes, as the posting guide says, we would probably need a reproducible
self-contained example. Emphasis on "reproducible" and "self-contained.
Best regards,
Seeing how there have been three wrong answers so far, I should point
out that:
1) This is an FAQ: http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-
do-I-convert-factors-to-numeric_003f
2) Most of the other methods suggested so far fail if the example x
used is not of the form 1:n. The only
On Jun 12, 2008, at 2:24 AM, Qman Fin wrote:
Hi all,
I have some data x, which are actualy consisted of numerical
enties. But the
class of this matrix is set to be "factor" by someone else. I used
"class(x)", it turns out to be "factor". So I can not calculate them.
The typical approach is
On Jun 11, 2008, at 12:17 PM, Neil Gupta wrote:
R Users,
I'm new to R and was wondering how I can show more decimal places
when I run
commands. If I'm simply running a correlation(ES,YM) how would I
increase
the number of decimal places R shows? When I run this it shows me .
9734044.
How
In addition to Gabor's suggestion, note the following warning from ?nls
Warning
Do not use nls on artificial "zero-residual" data.
The nls function uses a relative-offset convergence criterion that
compares the numerical imprecision at the current parameter estimates
to the residual sum-of-
I have to say it is not clear at all what you expected. risk.factors
[1] is the character vector "file$A". You ask it to do a paste of
that, so of course it will just return itself. Then you do a table,
and naturally it tells you that it found "file$A" exactly once.
So what you have forgotte
On Jun 7, 2008, at 8:13 AM, jonboym wrote:
I'm trying to do a linear regression between the columns of
matrices. In
example below I want to regress column 1 of matrix xdat with
column1 of ydat
and do a separate regression between the column 2s of each matrix.
But the
output I get seem
I just managed to write things just fine, and then I recalled that I
had a similar problem when teaching our students SPSS (Yes, I know,
don't ask...), but the problem was effectively this: If a given file
was open in Excel, then that file was locked and no other program
could use it until
On Jun 5, 2008, at 9:13 PM, Duncan Murdoch wrote:
On 05/06/2008 8:23 PM, Rolf Turner wrote:
I just discovered what seems to me to be a slight funny in respect
of formal argument names. If I define a function
foo <- function(a,b){ ... whatever ...}
then ``inside'' foo() the exists() fu
On May 30, 2008, at 7:56 PM, ss wrote:
and I got an error message:
exprSet <- read.table('process_all4_GSA2.txt', row.names = 1,header
=FALSE)
Error in read.table("process_all4_GSA2.txt", row.names = 1, header
= FALSE)
:
duplicate 'row.names' are not allowed
I would say that's pretty e
On May 30, 2008, at 5:37 AM, baptiste Auguié wrote:
Thank you for the suggestions (off-list as well). I think the best
option may eventually be an explicit for loop to make things
clearer. To clarify a bit, I've used the plot function in the
example where in fact it is a numerical integrat
On May 29, 2008, at 11:54 PM, Redding, Matthew wrote:
Dear R Gurus,
I am having a little difficulty with nlm. I've searched the
archives and
found nothing that tells me why this is occuring -- though there are
some slightly similar issues.
A simple example:
lev2<-function(aaa,bbb,ccc,ddd,e
On May 29, 2008, at 11:02 PM, [EMAIL PROTECTED] wrote:
Suppose I have a plot
plot(1:10, pch = "")
And I want some text to indicate a Normal distrubition. I could do
this:
text(5, 6, substitute(XN(mu, sigma^2)), adj = 0)
text(5.35, 6, "~", adj = 0)
But that's clumsy, and depending on you
On May 29, 2008, at 9:56 PM, lek2k wrote:
PLEASE do read the posting guide http://www.R-project.org/posting-
guide.html
and provide commented, minimal, self-contained, reproducible code.
I (and certainly many others) have been using multiple points calls
for a while now with no problems at
A google search for "logistic regression with stepwise forward in r"
returns the following post:
https://stat.ethz.ch/pipermail/r-help/2003-December/043645.html
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On May 28, 2008, at 7:01 AM, Maria wrote:
Hello,
I am
On May 27, 2008, at 10:43 PM, Daniel Yang wrote:
Dear all,
I want to create a list that contains 0,1,2,3, ..., 1 as its
elements. I used the following code, which apparently doesn't work
very well.
a <- 0
for(i in 1:1) {
a <- list(a, i)
}
The result is not what I wanted. So ho
I think this comment for ?par, meant for both crt and srt, applies:
crt
A numerical value specifying (in degrees) how single characters
should be rotated. It is unwise to expect values other than multiples
of 90 to work. Compare with srt which does string rotation.
So I would say that even
?paste
paste('text',y,'.txt', sep="")
and you likely need data[[y]] instead of data$y.
On May 23, 2008, at 9:05 PM, Jason Lee wrote:
Hi,
I have a couple of text and would like to automate of reading these
multiple
files using
(namely; text1.txt, text2.txt)
for(y in 3:10){
data$y<-rea
Try results=verbatim instead of results=tex.
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On May 23, 2008, at 4:16 AM, [EMAIL PROTECTED] wrote:
Dear R users,
I'm working in a brief R-tutorial to a group of students. To make
that I'm
using Sweave but I've got
On May 22, 2008, at 9:14 PM, Edward Wijaya wrote:
Hi,
Below I have a function mlogl_k,
later it's called with "nlm" .
__BEGIN__
vsamples<- c(14.7, 18.8, 14, 15.9, 9.7, 12.8)
mlogl_k <- function( k_func, x_func, theta_func, samp) {
tot_mll <- 0
for (comp in 1:k_func) {
curr_ml
On May 22, 2008, at 3:04 PM, AlGates wrote:
Hello,
maybe someone can help me. I am looking for a possibility to plot a
3D area
diagram like in Excel:
http://www.microsoft.com/germany/mac/excel/images/chartbefore.jpg
Watch
this!
Would be nice if someone had any idea about that.
I don't
On May 22, 2008, at 8:56 AM, maiya wrote:
sorry, my mistake!
the data frame should read:
orig<-as.data.frame.table(orig)
orig
Var1 Var2 Freq
1AA 40
2BA5
3AB 30
4BB 25
but basicaly i would simply like a sample of the original matrix
( which is
a fre
Try:
mlogl_out <- nlm(mlogl, mean(vsamples), vsamples)
or
mlogl_out <- nlm(mlogl, mean(vsamples), x=vsamples)
The argument vsamples=vsamples is passed to mlogl, since nlm does not
recognize it. But mlogl doesn't have a vsamples argument, only alpha
and x arguments. So you have to either le
On May 20, 2008, at 5:59 PM, Deepayan Sarkar wrote:
On 5/20/08, Charilaos Skiadas <[EMAIL PROTECTED]> wrote:
Here is how I see it. Let me define a "visual y-unit" as the
height of a
unit of data in the y-direction, and similarly for a visual x-unit.
Then the aspect ratio
On May 20, 2008, at 2:34 PM, Deepayan Sarkar wrote:
On 5/20/08, Joshua Hertlein <[EMAIL PROTECTED]> wrote:
Hello,
I am very interested in "banking to 45 degrees" as defined by
William S. Cleveland
in "Visualizing Data." I like to do it in R as well as Excel,
etc. With R I have come
On May 20, 2008, at 11:49 AM, David Afshartous wrote:
All,
Very basic question I can't seem to find the answer to:
plot(0:10, 0:10)
The axes intersection is not aligned at (0,0) in the lower left.
This is on purpose, so that data points are not obscured by the axes.
The axis range is alwa
Hi Andre,
On May 19, 2008, at 4:28 PM, Andre Nathan wrote:
Hello
I'd like to plot a histogram of some data composed of real numbers.
The
bin width I'm using is ~ 0.01, which results in high values in the y
axis, so that the area under each bar corresponds to the
probability of
the data i
On May 18, 2008, at 10:41 AM, BXC (Bendix Carstensen) wrote:
Tha handy thinb about the fig=TRUE option in Sweave is that you do not
have to bother about filenames and starting and stpping the device.
I want the the resulting LaTeX to look as:
\begin{Schunk}
\begin{Sinput}
x <- seq(-2 * pi, 2
On May 15, 2008, at 5:37 PM, e-letter wrote:
Below is direct copy from command terminals of both pcs (mandrake 92
with r 171; mandriva 2008 with r 251, respectively).
R : Copyright 2003, The R Development Core Team
Version 1.7.1 (2003-06-16)
R is free software and comes with ABSOLUTELY NO WAR
On May 15, 2008, at 1:24 PM, David Katz wrote:
Trying to learn Proto. This threw me:
#startup r...
library(proto)
a <- proto(x=10)
a$x
[1] 10
x <- proto(x=100)
x$x
Error in get("x", env = x, inherits = TRUE) : invalid 'envir' argument
Do I simply need to be careful to name proto obje
Two comments. First of all, I don't see how you can be sure that if
you specify 365 bins, then each bin will contain exactly one day. In
order to do that, you need to know that each bin has width exactly 1,
and you don't tell lattice to use such a width, so it is likely
choosing something e
On May 15, 2008, at 2:07 PM, lamack lamack wrote:
Dear all, someone could explain why the following example is not a
valid
randomization scheme?
Consider an experiment in which the
six experimental units to be used are permanently fixed in a row and
two treat-
ments are to be randomly ass
ligned)
###
Anywag, thanks again for having taken the time thinking about my
question;
Heinrich.
-Ursprüngliche Nachricht-
Von: Charilaos Skiadas [mailto:[EMAIL PROTECTED]
Gesendet: Mittwoch, 14. Mai 2008 13:30
An: RINNER Heinrich
Cc: [EMAIL PROTECTED]
Betreff: Re: [R] lattice: left-
On May 14, 2008, at 9:28 PM, [EMAIL PROTECTED] wrote:
Dear List,
I'm currently trying to produce a number of pairs() plots with special
text labels in the diagonal panels giving the units for the various
quantities.
These labels stretch across multiple lines, with the names of the
quantities
a
Deepayan's new book to the rescue again:
http://lmdvr.r-forge.r-project.org/figures/figures.html?
chapter=01;figure=01_04
Look at the code for this figure, especially the last two lines. Not
sure that the fact that it's a win.graph device has much to do with
this.
Haris Skiadas
Departmen
On May 14, 2008, at 3:47 AM, RINNER Heinrich wrote:
[adapted repost of question
http://tolstoy.newcastle.edu.au/R/e4/help/08/03/6260.html]
Dear R community,
by default, text in the strips of a trellis plot is centered in the
strip.
Is there a way to have the text left-aligned?
For example:
l
On May 13, 2008, at 5:52 AM, Esmail Bonakdarian wrote:
Tony Plate wrote:
You probably should check this section in your R-help subscription
options (via https://stat.ethz.ch/mailman/options/r-help/, I think):
Receive your own posts to the list?
Tony,
Like jt I too have it set to receive
On May 12, 2008, at 5:22 PM, Anh Tran wrote:
Hi,
What's one way to convert an integer to a string with preceding 0's?
such that
'13' becomes '013'
to be put into a string
I've tried formatC, but they removes all the zeros and replace it with
blanks
formatC(13, width=10, format="d", fl
On May 10, 2008, at 7:30 AM, Hans W Borchers wrote:
For learning purposes mainly I attempted to implement hashes/maps/
dictionaries
(Python lingua) as S4 classes, see the coding below. I came across
some rough S4
edges, but in the end it worked (for one dictionary).
When testing ones sees th
On May 9, 2008, at 5:39 AM, Dieter Menne wrote:
Dr. Ottorino-Luca Pantani unifi.it>
writes:
Imagine that for a particular cuvette (I have 112 different
cuvettes !!)
you have to mix the following volumes of solution A, B, and C
respectively.
c(1803.02, 193.51, 3.47)
Each solution is to
On May 8, 2008, at 9:11 PM, Sean Carmody wrote:
Does anyone have any ideas about how you could use R to produce a
fancy area
plot like this one in the NY Times? http://tinyurl.com/6rr22g
I certainly hope not, I wouldn't want my favorite statistics program
to produce an area graph where the
This is exactly the problem: apps launched through the Finder do not
go through the usual shell initialization process, where the PATH is
typically set up. The two solutions would be to either use the full
path to the command, or else start R.app from the Terminal, via the
command:
open -
On May 6, 2008, at 10:43 PM, Alexy Khrabrov wrote:
I've used to have a script with a barplot command it in, preceded
by a png:
png(graph.file,height=H,width=W)
barplot(t,names.arg=breaks[2:(length(t)+1)],tck=gridlines)
-- worked before R 2.6.2. When I tried it in R 2.6.2, which I have
for
I would actually go with this:
bits=c(1, 0, 1, 1, 0)
paste("X", which(bits==1), sep=".",collapse="+")
No need for the vars variable. Though admittedly it breaks down if
bits is identically 0.
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On May 6, 2008, at 3:1
On May 5, 2008, at 7:03 AM, pecardoso wrote:
Maybe a very, very basic question but how can I get a vector of
values with the specific format:
001,002,010,100
instead of:
1,2,10,100
Not perfect, but might get you started:
sprintf("%03d",c(8:10,101))
or
formatC(c(8:10,101), width=3, flag="
Actually it's been out for a couple of weeks now at least. I just
finished my first reading of it, and I must say it was spectacular.
Congratulations Deepayan, the book gave me exactly the kind of
lattice knowledge I needed, and then some. The graphics are really
impressive and good illustr
On Apr 15, 2008, at 9:53 PM, Ng Stanley wrote:
> Hi,
>
>> t <- list("cat"=1)
>> exists("t")
> [1] TRUE
>> exists("t[["cat"]]")
> Error: unexpected symbol in "exists("t[["cat"
>> exists("t[[\"cat\"]]")
> [1] FALSE
Perhaps what you want is:
"cat" %in% names(t)
> Thanks
> Stanley
Haris Skiadas
De
I think you want to look into ?stack. For example:
x<-data.frame(a=1:5,b=6:10)
y<- stack(x)
Then x$values are the values, and x$ind is the factor.
On Apr 15, 2008, at 9:36 PM, Paul Lynch wrote:
> Hi,
>I'm trying to do a linear regression style one-way ANOVA using some
> data in a data frame
Did you try Richie's suggestion? The x[,1] part will pick out the
first column of the data frame. Seems to do exactly what you asked for.
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On Apr 11, 2008, at 7:57 AM, Antje wrote:
> Of course, I know, but I cannot app
On Apr 9, 2008, at 1:27 PM, Hans-Jörg Bibiko wrote:
>
> On 09.04.2008, at 17:46, Shubha Vishwanath Karanth wrote:
>> To put it simple,
>>
>> C=c("My Dog", "Its really good", "Beautiful")
>>
>> Now,
>> SOMEFUNCTION(C) should give: c("My", "Its really", "")
>
> SOMEFUNCTION <- function(x) gsub(" *\
On Apr 6, 2008, at 10:35 AM, Ben Bolker wrote:
> csiro.au> writes:
>
>>
>> I've noticed an increasing tendency for people to use '=' rather than
>> the older '<-' symbol. When '=' became available as an assignment
>> operator in S-PLUS in the late '90s my first reaction was to
>> switch to
>>
On Mar 30, 2008, at 2:51 PM, Bryan Hanson wrote:
> I think I more or less understand what a “wrapper” is, but I’d like
> to hear
> how more experienced R users define it, and especially I'd like to
> know if
> there is a formal definition. In my reading, it seems like there
> are a
> fairly
Try adding strip.white=false on the code chunks:
<>=
hline()
hline()
@
Read ?RweaveLatex for more settings.
or if you want this to happen in all code chunks add this early on in
the rnw file:
\SweaveOpts{strip.white=false}
Haris Skiadas
Department of Mathematics and Computer Science
Hanover
raphics?
I found Paul Murrell's book useful.
> Agus
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
> Charilaos Skiadas escribió:
>> On Mar 27, 2008, at 1:47 PM, Agustin Lobo wrote:
>>> Thanks, it was a matter of reshaping the data matrix a
On Mar 27, 2008, at 1:47 PM, Agustin Lobo wrote:
> Thanks, it was a matter of reshaping the data matrix as I usually have
> it, ie:
> datos <-
> data.frame(x=abs(round(rnorm(100,10,5))),y=abs(round(rnorm
> (100,2,1))),f=factor(round(runif(100,1,3
>
> to become:
>
> datos2 <-
> data.frame(V1=
As you have not given us a reproducible example (namely we don't
really know what "test" is), there are likely better ways to do this
than what I am about to suggest, and you can find examples in the
relevant plot functions likely, but I think what you want can be
achieved using ifelse:
On Mar 23, 2008, at 1:37 PM, Charilaos Skiadas wrote:
> panel.points(mean(x), y, col="red", ...)
Correction, this should have probably been:
panel.points(tapply(x, y, mean), y, col="red", ...)
All this assuming you want horizontal boxplots.
Haris Skiadas
De
On Mar 23, 2008, at 11:31 AM, Plantky wrote:
> Hi everyone,
>
> Is there a way to include both mean and median in a bwplot? And what
> should I do to convert the median dots into lines?
Did you look at the documentation for bwplot and panel.bwplot?
This should do it , adjust at will:
ex <- data
On Mar 16, 2008, at 8:12 PM, Christophe Genolini wrote:
> Hi the list
>
> I am fighting with the twins setAs and setIs...
>
> Here are some questions and comments (comments to myself but that
> migth
> be wrong, it is why I am posting them)
> 1. Very surprising : using setIs define 'is', 'as<-'
On Mar 13, 2008, at 5:04 AM, Christophe Genolini wrote:
> Hi the list
>
> When two setGeneric occurs on the same function, the second erage the
> first and erase all the function previously define.
> Is it possible to prevent that ? Is it possible to declare a
> setGeneric
> that can not be eras
On Mar 10, 2008, at 7:49 AM, Elena Wilson wrote:
>
> linmod=lm(Y~X1+X2+X3+X4W, subset=(X5==1 & X6==7), weights==WEIGHT)
That should likely be weights=WEIGHT, with one equal sign.
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
___
If you have an original file in excel, the way I get such files is to
save them as csv (comma-separated), and then to use read.csv. Then
these empty spots are more easily handled, since they correspond to
too successive commas.
Haris Skiadas
Department of Mathematics and Computer Science
Han
On Mar 10, 2008, at 5:15 AM, Petr PIKAL wrote:
> Hi
> [EMAIL PROTECTED] napsal dne 10.03.2008 08:12:28:
>
>> hello
>>
>> I want to compare the values of two columns of a dataset on a graph.
>> Which graphic do you recommend ?
>
> It depends on what values you have and what you want to compare.
>
>
as to allow the
use of variables from the data frame in the specification of graphics
parameters like col, lty etc?
Your suggestion does indeed work very nicely in my case. I could
probably do away from the formula interface altogether, but it is a
convenient way of specifying the axis label
On Mar 9, 2008, at 12:12 PM, Keizer_71 wrote:
>
> Hi Everyone,
>
> I am having trouble using R. I am not sure what happen but when i
> start R, i
> am getting error message
>
> "Fatal Error: Unable to restore saved data in .RData.
Just google for "unable to restore saved data in .RData. ", and
I ran into a weird, to me at least, problem, and hoping someone can
shed some light into it. In a nutshell, there seems to be some
problem when one calls plot with a formula, from within another
function, using ... to pass arguments, and one of those arguments
being xlim (and only xlim show
On Mar 7, 2008, at 10:50 AM, zhihuali wrote:
>
> Hi, netters,
>
> This is probably a rookie question but I couldn't find the answer
> after hours of searching and trying.
>
> Suppose there'a a dataframe M:
>
> x y
> 10 A
> 13 B
> 8 A
> 11 A
>
> I want to locate the rows where x >=
On Mar 7, 2008, at 8:41 AM, Rainer M Krug wrote:
>>
>> I'm not sure I understand it, why don't you want to just number the
>> subfigures in the order in which you will draw them?
>
> Because i thought it would be easier the other way round? Thanks
> anyway
Yes, I agree it should not be as har
On Mar 7, 2008, at 8:02 AM, Rainer M Krug wrote:
> On 07/03/2008, Charilaos Skiadas <[EMAIL PROTECTED]> wrote:
>> On Mar 7, 2008, at 7:18 AM, Rainer M Krug wrote:
>>
>>> Hi
>>>
>>> I created a complex layout with using layout() and it looks
&
On Mar 7, 2008, at 2:17 AM, Oldrich Kruza wrote:
> Hello Soumyadeep,
>
> if you store the data in a tabular file, then I suggest using standard
> text-editing tools like cut (say your file is called data.csv, fields
> are separated with commas and you want to get rid of the third and
> sixth colum
On Mar 7, 2008, at 7:18 AM, Rainer M Krug wrote:
> Hi
>
> I created a complex layout with using layout() and it looks exactly as
> I need it. But I don't want to print in the order in which the
> subfigure are numbered, but in a different order.
>
> How can I navigate in the layout so that I can s
On Mar 6, 2008, at 9:05 PM, John Taffe wrote:
> Dear R-help list,
>
> I'm new to R. I tried to get R to read a Stata data file using the
> read.dta function in the package "foreign", which I downloaded and
> extracted to "C:\Program Files\R\R-2.6.2\library" on my pc.
>
> I tried
>
>> nora <- rea
On Mar 6, 2008, at 1:49 PM, Mag. Ferri Leberl wrote:
> Dear everybody!
> Is there a command in \LaTeX to display the R-Logo or has anybody
> made it up?
> Thank you in advance.
Isn't it just an image? Hence you would include it like one usually
includes images. Or do you mean something else?
On Mar 5, 2008, at 2:56 PM, [EMAIL PROTECTED] wrote:
> Hello,
>
> I am an advanced user of R. Recently I found out that apparently I do
> not fully understand vectors and lists fully
> Take this code snippet:
>
>
> T = c("02.03.2008 12:23", "03.03.2008 05:54")
> Times = strptime(T, "%d.%m.%Y %H:%M
Sorry, I meant to send this to the whole list.
On Mar 5, 2008, at 8:46 AM, Charilaos Skiadas wrote:
> The problem doesn't necessarily have to do with the range of data.
> At first level, it has to do with the simple fact that dfdb has
> rank 6 at most, (7 at most in general,
On Mar 5, 2008, at 1:39 AM, Mark W Kimpel wrote:
> I am getting some unexpected results from some functions of igraph and
> it is possible that I am misinterpreting the vertex numbers. Eg., the
> max betweenness measure seems to be from a vertex that is not
> connected
> to a single other vertex
On Mar 5, 2008, at 12:03 AM, Will Holcomb wrote:
> I have been trying to figure out how to run a simple simulation of
> the ANOVA
> and I'm coming up just a bit short. The code I've got is:
>
> cohen.f = .25
> groups = 4
> between.var = 19
> within.var = between.var / cohen.f ^ 2
> n = 500
> s
Mark,
if I understand what you are asking, then you likely want either the
Floyd-Warshall algorithm:
http://en.wikipedia.org/wiki/Floyd-Warshall_algorithm
or Djikstra's algorithm
http://en.wikipedia.org/wiki/Dijkstra%27s_algorithm
The package igraph seems to have some useful methods,
On Mar 3, 2008, at 11:12 AM, stephen sefick wrote:
> x<-read.zoo("SC2.csv", sep="," , format="%m%m/%d%d/%y%y%y%y %h%h:%m%
> m")
>
> #Error in read.zoo("SC2.csv", sep = ",", format =
> "%m%m/%d%d/%y%y%y%y %h%h:%m%m") :
> index contains NAs Error message
You need header=TRUE in th
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