On Fri, Dec 12, 2008 at 11:18 AM, Duncan Murdoch murd...@stats.uwo.ca wrote:
On 12/12/2008 11:38 AM, hadley wickham wrote:
On Fri, Dec 12, 2008 at 8:41 AM, Duncan Murdoch murd...@stats.uwo.ca
wrote:
On 12/12/2008 8:25 AM, hadley wickham wrote:
From which you might conclude that I don't
On Fri, Dec 12, 2008 at 11:11 AM, Vitalie Spinu vitosm...@rambler.ru wrote:
On Fri, 12 Dec 2008 17:38:13 +0100, hadley wickham h.wick...@gmail.com
wrote:
You could also imagine similar iterators for random sampling, like
samp(0.2) to choose 20% of the indices, or boot(0.8) to choose 80
Oh yes, that's a good point. But wouldn't the following do the job?
.selector - function(a, b) {
function(n) a(n) b(n)
}
or
.selector - function(a, b) {
function(n) intersect(a(n), b(n))
}
depending on whether selectors return logical or numeric vectors.
Writing functions for |
My end would be the output of your end(). If there are no args and no local
context, I don't see the need for it to be a function call. It would just
be defined as something like
end - structure( function(n) c(rep(FALSE, n-1), TRUE), class=selector)
Oh, I see what you mean.
I'm not sure
On Fri, Dec 12, 2008 at 3:08 PM, Vitalie Spinu vitosm...@rambler.ru wrote:
On Fri, 12 Dec 2008 18:27:02 +0100, hadley wickham h.wick...@gmail.com
wrote:
or may be just
mtcars[cyl3last(20)]
or this is already too far?
This would be a considerable extension because then the selector would
You (as many before you) have overlooked the ave() function, which can
replace the ordering as well the do.call(c,tapply())
Majority of questions on this list concern data manipulation. Many are
repetitive. Overlooking like that will always happen unless some
comprehensive data
On Wed, Dec 10, 2008 at 4:33 AM, Todor Kondic [EMAIL PROTECTED] wrote:
Thanks Bert for the answer! I'll try to find an appropriate package.
In the end, i have fiddling.
But, can anyone tell me, were I to create an underlying implementation
of cooridnate transforms, perhaps controlled by user
On Wed, Dec 10, 2008 at 11:02 AM, baptiste auguie [EMAIL PROTECTED] wrote:
Dear list,
I have a data.frame with x, y values and a 3-level factor group, say. I
want to create a new column in this data.frame with the values of y scaled
to 1 by group. Perhaps the example below describes it best:
Hi Michael,
In general, I think you should be able to do:
gimage - read.jpeg(url(gimageloc))
or alternatively use the EBImage from bioconductor which will read
from a url automatically (it also opens a much wider range of file
types)
library(EBImage)
img - readImage(gimageloc, TrueColor)
On Wed, Dec 10, 2008 at 1:54 PM, Viktor Nagy [EMAIL PROTECTED] wrote:
2008/12/10 Stefan Grosse [EMAIL PROTECTED]
I have two datasets stored in tab-separated format in the following way
file1:
country year1year2
Germanyvar1 var1
Hungary var1
On Wed, Dec 10, 2008 at 4:09 PM, Patrizio Frederic
[EMAIL PROTECTED] wrote:
hi all,
I have a data frame such as:
1 blue 0.3
1 NA0.4
1 red NA
2 blue NA
2 green NA
2 blue NA
3 red 0.5
3 blue NA
3 NA1.1
I wish to find the last non-missing value in every 3ple: ie I want a
graphics,statistical analysis etc. as well as programming. There are just
too many possible data structures to expect logical consistency in their
handling throughout (if one can even define what that means in specific
instances!).
I disagree with this claim: I think it is possible to create
Perhaps... But plyr works only on **basic** data structures, and I referred
to all **possible** data strucures (deliberately); so I stand by my
statement and note that you did not contradict it.
To me the basic structures are vectors, matrices and arrays; lists;
and data frames (that these are
On Tue, Dec 9, 2008 at 10:39 AM, Dennis Fisher [EMAIL PROTECTED] wrote:
Colleagues,
Platform: OS X (but issue applies to all platforms)
Version: 2.8.0
I have a mixture of text and data that I am outputting via R to a pdf
document (using a fixed-width font). The text contains tabs that
On Tue, Dec 9, 2008 at 5:36 PM, Renny Li [EMAIL PROTECTED] wrote:
Hi,
I am trying to compare two values using == operand, please take a look of
the following example (I copied ALL what I did here without deleting any line)
bb-1
cc-50
cc==abs(bb+52)
[1] FALSE
C-53
C-53
c-53
On Sun, Dec 7, 2008 at 10:10 AM, Daren Tan [EMAIL PROTECTED] wrote:
How to use the na.rm function outside aggregate ? I tried
na.rm - function(f) {
function(x, ...) f(x[!is.na(x)], ...)
}
na.rm(sum(c(NA,1,2)))
function(x, ...) f(x[!is.na(x)], ...)
na.rm(sum, c(NA,1,2))
Error in
I'm trying to omit NA:s in this DF and produce a reduced DF. The
problem is that I cannot completely omit NA rows.
I tried
library(reshape)
g - melt(DF, id=c(idvar1, idvar2))
g - na.omit(g)
You're missing an id variable:
DF$idvar3 - 1:2
g - melt(DF, id=c(idvar1, idvar2, idvar3), na.rm =
On Fri, Dec 5, 2008 at 6:50 AM, Antje [EMAIL PROTECTED] wrote:
Hello,
I hope this question is not too stupid. I would like to know how to update
levels after subsetting data from a data.frame.
df - data.frame(factor(c(a,a,c,b,b)), c(4,5,6,7,8), c(9,1,2,3,4))
names(df) - c(X1,X2,X3)
my.sub
Hi David,
facet_wrap and facet_grid function are both very usefull. But they are
perhaps a bit redundant.
I disagree ;) Conceptually they are rather different: facet_wrap is
essentially a 1d layout, while facet_grid is a 2d layout. This has
implications for how you specify the faceting, how
bericht-
Van: stephen sefick [mailto:[EMAIL PROTECTED]
Verzonden: woensdag 3 december 2008 1:09
Aan: ONKELINX, Thierry
CC: hadley wickham; R-help
Onderwerp: Re: [R] ggplot2 facet_wrap problem
If you look at the TSS graph in the faceted example and then look at
the plot of just the GPP vs
Hi Daren,
Unfortunately, the current version of reshape isn't very efficient.
I'm working on a new version which should be 10-20x times faster for
the operation that you're performing, but this won't be ready for a
while and in the meantime you might want to try an alternative
approach, like the
They are obviously growing desperate - I have now been asked to write
5 articles!
Hadley
--
http://had.co.nz/
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On Tue, Dec 2, 2008 at 9:48 AM, Antje [EMAIL PROTECTED] wrote:
Hi Gabor,
it works! Thank you very much! But I still don't understand the difference
between [0-9] and [:digit:]...
You might find this site helpful:
http://regexp.resource.googlepages.com/analyzer.html
Copy in your attempt and
Hi Stephen,
Have a look at the polishing your plot for publication chapter of
the ggplot2 book.
Regards,
Hadley
On Tue, Dec 2, 2008 at 5:31 PM, stephen sefick [EMAIL PROTECTED] wrote:
I would like to rotate the axis labels 45 deg.
--
Stephen Sefick
Let's not spend our time and resources
On Tue, Dec 2, 2008 at 6:21 PM, Avram Aelony [EMAIL PROTECTED] wrote:
A few questions about maps...
(1) How can I find a listing of the internal data sets that map() from the
maps library contains?
For example, usa, county, state, nz all work. Are there any others?
help(package = maps)
The underlying issue is actually not in transform() but in data.frame():
aq - airquality[sample(1:153,6),]
data.frame(aq, list(a=1,b=2))
Error in data.frame(aq, list(a = 1, b = 2)) :
arguments imply differing number of rows: 6, 1
data.frame(aq, list(a=1))
Ozone Solar.R Wind Temp Month
On Mon, Dec 1, 2008 at 11:06 AM, Vitalie Spinu [EMAIL PROTECTED] wrote:
Hello Everyone,
May be a silly question.
How to pass programmatically variables which are not known in advance and
are quoted? Variables are quoted implicitly in functions like subset and
transform and explicitly in
On Mon, Dec 1, 2008 at 12:53 PM, Reitsma, Rene - COB
[EMAIL PROTECTED] wrote:
Dear All,
I'm hoping one of you can help me with the following R problem. I'm
trying to refer to a member of a list by variable. However, this seems
not to work:
foo=list(first=c(1:10),second=c(11:20))
foo$first
On Sun, Nov 30, 2008 at 11:38 AM, Carl Witthoft [EMAIL PROTECTED] wrote:
From: Yihui Xie xieyihui_at_gmail.com
Date: Sun, 30 Nov 2008 15:32:35 +0800
Wow, you are so lazy... But sometimes R is just designed for lazy guys...
Yeah, well, laziness is the mother of creativity :-) .
But
On Sun, Nov 30, 2008 at 12:21 PM, Salas, Andria Kay [EMAIL PROTECTED] wrote:
I am running a large for loop and at the end of each iteration a matrix is
produced. The program changes the columns in the matrix, and each time a
column is added the name of that column is y. All original columns
On Fri, Nov 28, 2008 at 9:00 AM, Rthoughts
[EMAIL PROTECTED] wrote:
Hi,
Is the number of lines that can be displayed in R GUI limited?
When I do a Fourier Tranform of 4000 data points, I can only see the last
300 or so of it. I need to see all of it. How is this possible?
Perhaps you could
On Thu, Nov 27, 2008 at 12:53 AM, Kinoko [EMAIL PROTECTED] wrote:
Hi,
I would like to convert my character sequences in my matrix/
data.frame into numeric where it is possible.
I would also like to retain my alphabetic character strings in their
original forms.
5.15.1
hm hm
On Wed, Nov 26, 2008 at 8:14 AM, jim holtman [EMAIL PROTECTED] wrote:
Your time is being taken up in cor.test because you are calling it
100,000 times. So grin and bear it with the amount of work you are
asking it to do.
Here I am only calling it 100 time:
m1 - matrix(rnorm(1),
Hi Jason,
The reason you are getting this error is that the latest version of
reshape uses fun.aggregate(numeric(0)) to figure out what missing
values should be filled in with. Unfortunately there was a brief
period in R versions when var(numeric(0)) returned an error rather
than a missing
Why not write it yourself?
days_in_year - function(year) {
365 + (year %% 4 == 0) - (year %% 100 == 0) + (year %% 400 == 0)
}
This should work for any year in the Gregorian calendar.
Hadley
On Mon, Nov 24, 2008 at 1:25 PM, Felipe Carrillo
[EMAIL PROTECTED] wrote:
Hi:
Is there a function
On Tue, Nov 25, 2008 at 9:18 AM, Jacques Wagnor
[EMAIL PROTECTED] wrote:
Dear List,
Does there exist a function that produces a heat map like this one
(image 3 of 4):
=mtcars) + facet_grid(cyl ~ vs) # works
qplot(mpg, wt, data=mtcars, geom = line) + facet_grid(cyl ~ vs)
Erreur dans grobs[[i, j]] - layer$make_grob(layerd[[i, j]], details, coord)
:
types (de NULL a list) incompatibles dans l'affectation [[
david
2008/11/23 hadley wickham [EMAIL PROTECTED
Hi Paul,
That's a bug - I'll look into it.
Regards,
Hadley
On Mon, Nov 24, 2008 at 10:46 AM, Paul Emberson [EMAIL PROTECTED] wrote:
Hi,
With ggplot2 v0.8, how do I position a legend on top of the plot. Things
like
p + opts(legend.position=top)
work ok. But
p +
Hi David,
That looks like a bug! I'll look into it.
Regards,
Hadley
On Sat, Nov 22, 2008 at 1:07 PM, David Hajage [EMAIL PROTECTED] wrote:
Hello R users (and Hadley)
I have another question about ggplot2 :-)
(version 0.8)
`dat` -
structure(list(D = c(a, b, c, d), G =
On Sat, Nov 22, 2008 at 12:00 PM, zerfetzen [EMAIL PROTECTED] wrote:
Goal:
Suppose you have a vector that is a discrete variable with values ranging
from 1 to 3, and length of 10. We'll use this as the example:
y - c(1,2,3,1,2,3,1,2,3,1)
...and suppose you want your new vector (y.new) to
ggplot2
ggplot2 is a plotting system for R, based on the grammar of graphics,
which tries to take the good parts of base and lattice graphics and
avoid bad parts. It takes care of many of the fiddly details
that make plotting a hassle
(SUBJECT_ID=sample(letters[1:5],100,TRUE),HR=rnorm(100))
sd.list = with(dat, tapply(HR, SUBJECT_ID, sd))
data.frame(SUBJECT_ID=rownames(sd.list),sd=sd.list)
I think Hadley Wickham tried to make life easier with the plyr package,
so I thought something like the below would work out of the box
On Thu, Nov 20, 2008 at 10:04 AM, Dieter Menne
[EMAIL PROTECTED] wrote:
hadley wickham h.wickham at gmail.com writes:
library(plyr)
dat = data.frame(SUBJECT_ID=sample(letters[1:5],100,TRUE),HR=rnorm(100))
daply(dat,.(SUBJECT_ID),sd)
ddply(dat,.(SUBJECT_ID),sd)
Well that calculates sd
Hi David,
I inadvertently introduced a bug in ggplot in the last release. I
uploaded a fix to CRAN this morning and it should be available in the
near future. Sorry for the inconvenience.
Regards,
Hadley
On Thu, Nov 20, 2008 at 2:49 PM, David Hajage [EMAIL PROTECTED] wrote:
Hello R users,
Reading in between the lines a little, maybe you want
lm(..., na.action = na.exclude)
That should return missing values for the influence statistics when
the predictor or responses is missing in the input.
Hadley
On Thu, Nov 20, 2008 at 4:19 PM, David Kaplan
[EMAIL PROTECTED] wrote:
Let me
On Wed, Nov 19, 2008 at 12:54 PM, Brigid Mooney [EMAIL PROTECTED] wrote:
Hi All,
I am iterating through dated materials, with variable start and end dates,
and would like to skip procedures everytime I encounter a weekend or
holiday. To do this, I thought the easiest way would be to create a
On Wed, Nov 19, 2008 at 5:34 PM, Juliet Hannah [EMAIL PROTECTED] wrote:
With this data
x - c(0,0,1,1,2,2)
y - c(5,6,4,3,2,6)
lwr - y-1
upr - y+1
xlab - c(Low,Low,Med,Med,High,High)
mydata - data.frame(x,xlab,y,lwr,upr)
I would like to make a dot plot and use lwr and upr as error bars.
Hi Dave,
On Mon, Nov 17, 2008 at 6:35 AM, Dave Murray-Rust
[EMAIL PROTECTED] wrote:
I'm trying to plot multiple lines using different colours/symbols to
distinguish them. If I try to plot more than 6 lines, I get an error:
ggplot( dat, aes(x=time,y=value,group=variable,shape=variable) ) +
On Sun, Nov 16, 2008 at 7:41 PM, Simon Blomberg [EMAIL PROTECTED] wrote:
It is better programming practice to use FALSE for false and TRUE for
true, and not F and T. This is because it is quite legal to do this:
T - FALSE
F - TRUE
It may be better programming practice, but is it better
On Mon, Nov 17, 2008 at 3:42 PM, steve [EMAIL PROTECTED] wrote:
Thank you. Here's my version, using melt instead of do.call(make.groups...
library(reshape)
fgl2 = melt(fgl[,-10])
fgl2$type = fgl$type
bwplot(value ~ type | variable, data = fgl2)
Or even more succintly:
fgl2 - melt(fgl, id =
On Mon, Nov 17, 2008 at 3:49 PM, Etches Jacob [EMAIL PROTECTED] wrote:
In lattice
#toy data
library(ggplot2)
library(lattice)
x - rnorm(100)
y - rnorm(100)
k - sample(c(Weak,Strong),100,replace=T)
j - sample(c(Tall,Short),100,replace=T)
w - data.frame(x,y,j,k)
Hi Stavros,
I think we're talking past each other on the question of the semantics
of formula operators, and it's probably not productive to continue. I
would guess that the underlying issue is that we come from different
communities, and so have different background assumptions. Perhaps
On Sun, Nov 16, 2008 at 9:56 PM, Christian Arnold [EMAIL PROTECTED] wrote:
Hello R-Community,
I am pretty new to R and I am fascinated what R can do! I am doing
phylogenetic analysis in R, and my current project includes two problems
that I am unable to solve, unfortunately. I am hoping that
On Thu, Nov 13, 2008 at 9:10 PM, J Dougherty [EMAIL PROTECTED] wrote:
On Monday 10 November 2008 01:23:30 pm Prof Brian Ripley wrote:
See ?Sys.timezone, which help.search(timezone) points you to.
On Mon, 10 Nov 2008, stephen sefick wrote:
I have looked at
?as.POSIXct
That also links to
Along similar lines, someone recently posted a script to generate
a .bib file for all packages installed. It would be useful if someone
were to implement that script for CRAN and make the resulting
R-packages.bib file available on the CRAN site.
It would also be useful if citation() added a
I think your analysis is correct, that the goals of casual use and
programming are inconsistent. But in general I think there's always going
to be support for providing alternative ways that are programmer-safe.
For instance, library( foo, character.only=TRUE) says that foo is a
character
?dir
Hadley
On Tue, Nov 11, 2008 at 11:06 AM, [EMAIL PROTECTED] wrote:
Dear all,
I am trying to read a bunch of csv files using read.table() that are named
test_xx.csv where xx has no particular pattern. Is there a way
of reading all the files by specifying a truncated file name
On Mon, Nov 10, 2008 at 1:04 PM, Wacek Kusnierczyk
[EMAIL PROTECTED] wrote:
pardon me, but does this address in any way the legitimate complaint of
the rightfully confused user?
consider the following:
d = data.frame(a=1, b=2)
a = c(a, b)
z = a
# that is, both a and z are c(a, b)
Which can be simplified to:
paths - dir(path = filePath, pattern = ^test_, full = T)
lapply(paths, read.csv)
Hadley
On Tue, Nov 11, 2008 at 2:01 PM, [EMAIL PROTECTED] wrote:
Hi all,
Thanks everyone for your advice. They have been helpful.
Just for the record, I am using ...
And without wanting to be rude or anything, your opinion carries very
little weight in a project like R. You've arrived on the list and been
very critical of the work of others. Now there is nothing wrong with
being critical if it is constructive, and additionally with something
like R you
That's why (I think) it should be an *** optional argument
with default set to FALSE *** ... it's clear from the past traffic
on the list (I won't take the time to dig up the thread
references right now) that there is at the very least
a significant minority of users who expect the opposite,
On Tue, Nov 11, 2008 at 8:30 PM, Kinoko [EMAIL PROTECTED] wrote:
Dear list,
Is there a way to do something like the following pseudo-code -
without for loop?
There isn't a for loop in your code!
Hadley
complexFn - function(a,b){
...
return(c)
}
x[i] = complexFn(x[i-1], x[i-2])
I
On Mon, Nov 10, 2008 at 4:42 PM, [EMAIL PROTECTED] wrote:
Dear list
Can anyone suggest a simple way to abort execution like stop(...) does, but
without issuing an Error: ... message?
I don't want to set 'options( show.error.messages=TRUE)' because I want
normal behaviour to resume after
I should have been clearer, sorry-- I'm trying to exit from an inner
function which might be several levels deep, returning straight to the R
prompt. To be specific, I'm trying to clean up the No Error in... message
in my 'debug' package-- the No prefix being my original workaround to
On Fri, Nov 7, 2008 at 7:53 AM, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 11/7/2008 8:31 AM, roger koenker wrote:
Those of you with an interest in the US election and/or
statistical graphics may find the maps at:
http://www-personal.umich.edu/~mejn/election/2008/
interesting.
Hi all,
I'm trying to write up some recommendations for what graphics formats
are most useful for inclusion into ms office and openoffice. There
have been a few discussions on the list in the past, but I haven't
seen a summary. These are the options I've seen so far, along with
there costs and
On Thu, Nov 6, 2008 at 10:05 AM, Max Kuhn [EMAIL PROTECTED] wrote:
* svg: R output devices still experimental
I've been using the svg device in the Cairo package for a while now.
I've never had any issues with it and wouldn't characterize it as
experimental (of course, others may have had
..°}))
) ) ) ) )
( ( ( ( (Prof. Philippe Grosjean
) ) ) ) )
( ( ( ( (Numerical Ecology of Aquatic Systems
) ) ) ) ) Mons-Hainaut University, Belgium
( ( ( ( (
..
hadley wickham wrote:
Hi all,
I'm trying to write up
On Wed, Nov 5, 2008 at 5:42 AM, Fredrik Karlsson [EMAIL PROTECTED] wrote:
Dear list,
Sorry to ask you this, but I just ran a TukeyHSD on an model with a
two thee level factors as independent variables and a numeric score
dependent variable.
The aov gives a significant interaction effect, and
On Wed, Nov 5, 2008 at 11:12 AM, pilar schneider
[EMAIL PROTECTED] wrote:
Dear all
I need some help with R.
How can I save the estimates of a regression model in a file?
here is what I did:
1) this is my regression model:
fit1 - lm(logmilk ~ logdays + days, data=data2)
2) however, I want
Hi Stephen,
Thanks for the bug report (and apologies for the delay getting back to
you). I'm working on a fix today and will hopefully release a new
version in the very near future.
Hadley
On Fri, Oct 31, 2008 at 12:51 PM, stephen sefick [EMAIL PROTECTED] wrote:
Hadley et al.,
I was using
plotmatrix(d[,3:6])
I would like to either have a colour or more preferably a shape to
correspond to Site
this is what I have tried (along with many other combinations)
plotmatrix(nmds.bug[,3:6])+scale_shape(nmds.bug, shape=Site, pch=1:12)
There's not really any easy way to do this in the
, hadley wickham [EMAIL PROTECTED] wrote:
Hi Stephen,
Thanks for the bug report (and apologies for the delay getting back to
you). I'm working on a fix today and will hopefully release a new
version in the very near future.
Hadley
On Fri, Oct 31, 2008 at 12:51 PM, stephen sefick [EMAIL
Hi Simeon,
Could you publish vixarchive.csv too please? Do you have a start on
the version in ggplot2? It would be useful to see that code too.
Hadley
On Tue, Nov 4, 2008 at 8:49 AM, simeon duckworth
[EMAIL PROTECTED] wrote:
Dear R-listers
I've been trying to figure out how to annotate
Is your variable actually a date? R doesn't recognise dates
automatically - you need to create them with as.Date or similar.
Hadley
On Tue, Nov 4, 2008 at 3:22 AM, [EMAIL PROTECTED] wrote:
Dear all,
In the x-axis of a xyplot I define dates ,for example 01-10-2007 instead of
numbers, in a
On Mon, Nov 3, 2008 at 9:02 AM, Jorge Ivan Velez
[EMAIL PROTECTED] wrote:
Dear zerftezen,
Try this:
# Data
set.seed(123)
X=as.data.frame(matrix(rnorm(100),ncol=10))
# Percentiles 10 and 90 using apply
t(apply(X,2,quantile,probs=c(0.1,0.9)))
# The same using sapply
Hi Carlos,
I'd strongly urge to reconsider your colour choices - 7-10% of males
are red-green colour blind and it will be difficult for them to tell
the difference between the high and low values.
Hadley
On Sat, Nov 1, 2008 at 11:58 PM, Carlos Morales
[EMAIL PROTECTED] wrote:
Hello everyone,
On Sat, Nov 1, 2008 at 5:13 AM, baptiste auguie [EMAIL PROTECTED] wrote:
Hi,
I believe you can apply the same procedure as described in Paul Murrell's R
graphics book for arranging lattice plots.
Yup, and see also http://had.co.nz/ggplot2/book/grid.pdf
Hadley
--
http://had.co.nz/
On Fri, Oct 31, 2008 at 11:25 AM, Philip Twumasi-Ankrah
[EMAIL PROTECTED] wrote:
Hi friends,
I need suggestions/directions on how to producing a waterfall plot for
present extend of change in tumour size for a set of respondents in a study.
Example of use of waterfall plot is in the
On Thu, Oct 30, 2008 at 3:49 AM, ONKELINX, Thierry
[EMAIL PROTECTED] wrote:
Dear Bernd,
AFAIK you can only get counts, densitys, counts scale to a maximum of 1
and likewise densitys. But you can alter the labels on the scales
manually.
Well, a proportion is just the count divided by the
For this example:
library(ggplot2)
p - ggplot(mtcars, aes(x = wt, y=mpg)) + geom_point()
p - p + scale_x_continuous(expression(beta))
p
How can I include text with the expression. For example, level of
\beta. Also, how can I increase
Have a look at ?plotmath - you want something like
?split.
Hadley
On Wed, Oct 29, 2008 at 3:22 PM, t c [EMAIL PROTECTED] wrote:
I need some help with sub-setting my data. I am trying to divide a data
frame into multiple data frames based on the year collected, and stored in a
list with each new data frame labeled with year X where X is the
On Fri, Oct 24, 2008 at 5:18 PM, Elena Schulz [EMAIL PROTECTED] wrote:
Hi Hadley,
thanks a lot for your quick answer.
You should be able to replicate any dodging layout with facetting
You mean instead of facetting by years, facetting by months? I will try this
an see how the plot looks.
I'd
'plot' though. Is this a normal behaviour?
\documentclass[9pt]{article}
\title{ggplot2 example}
\begin{document}
\maketitle
\section*{Examples of using ggplot2}
The goal is to be able to import ggplot2 graphics into the annual report.
Hadley Wickham has done a great job by creating
You might want to have a look at the plyr package -
http://had.co.nz/plyr. The intro pdf describes a couple of problems
that are similar to yours.
Hadley
On Sun, Oct 26, 2008 at 3:10 PM, Wade Wall [EMAIL PROTECTED] wrote:
Hi all,
I have roughly fifty dataframes and a dataframe with the names
On Wed, Oct 22, 2008 at 9:34 AM, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 10/22/2008 10:02 AM, francois Guilhaumon wrote:
Hello,
I'm looking for a way to get the name of an object when it is used
within an sapply.
More precisely, with a simple example :
I have a named list of objects :
On Tue, Oct 21, 2008 at 1:58 AM, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi group!
Suppose I have 2 matrices A and B of equal dimensions.
I want to apply a function f to all corresponding pairs of rows from A
and B in an efficient manner.
Basically, I want
mapply(f, data.frame(A),
Here's two quick thoughts:
qplot(1, mpg, data=mtcars, geom=boxplot) + facet_grid(. ~ cyl, margins =T)
qplot(factor(cyl), mpg, data=mtcars, geom=boxplot) +
geom_boxplot(aes(x = all), width = 0.9)
Hadley
On Tue, Oct 21, 2008 at 12:41 PM, SalishSea [EMAIL PROTECTED] wrote:
I'd like to generate a
On Sun, Oct 19, 2008 at 10:49 AM, stephen sefick [EMAIL PROTECTED] wrote:
updn.gg - (structure(list(date = structure(c(11808, 11869, 11961, 11992,
12084, 12173, 12265, 12418, 12600, 12631, 12753, 12996, 13057,
13149), class = Date), unrestored = c(1.13789418691602, 0.704948049842955,
Why don't you want to do this?
timesDefineInside - function(foo, bar...) {
foo * bar
}
It seems like the obvious solution to your problem.
Hadley
On Sun, Oct 19, 2008 at 8:34 PM, Sietse Brouwer
[EMAIL PROTECTED] wrote:
Dear R-helpers,
I've got two functions; callTimes() calls times(),
On Fri, Oct 17, 2008 at 4:31 AM, Ted Harding
[EMAIL PROTECTED] wrote:
On 17-Oct-08 09:01:08, Benoit Boulinguiez wrote:
Hi,
Personally I always use xlim and ylim with the plot or points
function like that:
plot( X,Y,pch=16,col=2,cex.axis=1.5,cex.lab=1.5,
.
thanks agian
On Fri, Oct 17, 2008 at 4:19 PM, hadley wickham [EMAIL PROTECTED] wrote:
Hi Stephen,
Thanks for the kind words about ggplot2 :)
The next version of ggplot2 will implement the equivalent of scale
relation free - I've just finished writing the bulk of the code and
now I'm getting
On Fri, Oct 17, 2008 at 3:50 PM, [EMAIL PROTECTED] wrote:
Thanks for the gracious assistance in advance
I'm working on a non-metric scaling problem and am calculating the distance
for input to isoMDS
Here is the code
library(MASS)
vegdata - tapply(Percent, list(PRIMARY_VE, MASTERID),
On Thu, Oct 16, 2008 at 8:05 AM, kdebusk [EMAIL PROTECTED] wrote:
What test do I use to determine if there is a correlation between a
discrete variable and a continuous variable?
For example - I have water quality ratings for streams (excellent,
good, fair, poor) and a corresponding nitrogen
On Thu, Oct 16, 2008 at 11:42 AM, x0rr0x [EMAIL PROTECTED] wrote:
Hi all,
I'm trying to create a histogram which shows the frequency of variables
within a certain timeframe.
I've been using SPSS before, but I didn't quite like it...
To describe my problem further here are some example
An alternative approach would be to store 0 x 0 matrices instead of
NULLs. This way every object in your list is a consistent type.
Hadley
On Wed, Oct 15, 2008 at 5:23 AM, Muhammad Azam [EMAIL PROTECTED] wrote:
Dear friends
There is a list of arrays comprising different no of rows and columns
On Wed, Oct 15, 2008 at 5:59 AM, Michael Pearmain [EMAIL PROTECTED] wrote:
Hi All,
I've been trying to compare if the previous value in a variable is equal to
a binary value..(i.e i want to check if the last event was a yes or no)
i've been trying to write some code for this, but it seems
Hi Dylan,
You might want to have a look at the plyr package which is designed to
make these sorts of tasks easier - http://had.co.nz/plyr. The site
includes a ~20 page introductory pdf.
Hadley
On Wed, Oct 15, 2008 at 3:45 PM, dylan boyd [EMAIL PROTECTED] wrote:
Another request for help
On Tue, Oct 14, 2008 at 6:46 AM, stephen sefick [EMAIL PROTECTED] wrote:
r -(structure(list(TSS = c(2.8, 8.4, 11, 1.3, 4.2, 2, 3.4, 14, 8.2,
3.1, 1.4, 0.9, 0.5, 6.1, 9.2, 0.6, 1, 11, 2.4, 1.2, 1.3, 1.3,
0, 1.8, 8, 11, 11, 8.5, 8.5, 1.8, 13, 4.4, 1.4, 2.1, 0.5, 25,
25, 9.3, 6.1, 1.6, 1.5, 19,
Why not use a scatterplot? That will be far far better for your
purpose than a heatmap.
Hadley
On Tue, Oct 14, 2008 at 4:45 PM, feishi [EMAIL PROTECTED] wrote:
Hi, I have a question about heatmap. I have a data with row as microRNA and
two columns are two cell expression values for these
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