I would go with unlist on x,single bracket subsetted on f
x <- list(`1` = c(7, 13, 1, 4, 10),
`2` = c(2, 5, 14, 8, 11),
`3` = c(6, 9, 15, 12, 3))
f <- factor(rep(1:3,5))
unlist(x[f])
Yes, unsplit() it is. I was messing around with ave() (which can be hammered
into submiss
;>
On 2024-08-15 2:39 p.m., Izmirlian, Grant (NIH/NCI) [E] via R-help wrote:
> \n<>\n\n \n<<
> This is very weird. I was running a swarm job on the cluster and it bombed
> only for n.per.grp=108, not for the other values. Even though
> n.per.grp*n.tt is 540, so that the leng
ch=n.per.grp*n.tt)
length(arm.i)
____
From: Rui Barradas
Sent: Thursday, August 15, 2024 2:51 PM
To: Izmirlian, Grant (NIH/NCI) [E] ;
r-help@r-project.org
Subject: [EXTERNAL] Re: [R] Very strange behavior of 'rep'
�s 19:39 de 15/08/2024, Izmirlian, Grant (NIH/NCI
\n<>\n\n \n<<
This is very weird. I was running a swarm job on the cluster and it bombed
only for n.per.grp=108, not for the other values. Even though
n.per.grp*n.tt is 540, so that the length of the call to 'rep'
should be 1080, I'm getting a vector of length 1078.
n.per.grp <- 108
n.tt <-
It looks like a homework assignment. It also looks like you didn't read the
documentation carefully enough. The 'len.out' argument in seq is solely for
specifying the length of a sequence. The 'quantile' function omputes the
empirical quantile of raw data in the vector 'x' at cumulative
probab
"and",
"a new line" ~
bar(x) == sum(frac(x[i], n), i==1, n)
)
)
p <- ggplot(data=DAT, aes(x=X)) + geom_point(aes(y=Y)) +
geom_line(aes(y=Y.p))
p <- p + labs(caption = e)
p <- p + theme(plot.caption = element_text(hjust = 0))
p
Hope this helps,
Rui B
7; (row)" ~ "and",
"a new line" ~
bar(x) == sum(frac(x[i], n), i==1, n)
)
)
p <- ggplot(data=DAT, aes(x=X)) + geom_point(aes(y=Y)) +
geom_line(aes(y=Y.p))
p <- p + labs(caption = e)
p <- p + theme(plot.caption = element_text(hjust = 0))
p
Hope this helps,
Ru
people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Feb 18, 2021 at 9:37 AM Izmirlian, Grant (NIH/NCI) [E] via R-help
mailto:r-help@r-project.org>> wrote:
## I am using ggplot and trying to pr
## I am using ggplot and trying to produce a caption containing math symbols. I
need to
## add a second line. I did a fair amount of googling for answers. This one
seemed like
## it would answer my question as it is nearly exactly my problem, except there
is only
## one argument to the paste fun
Hi -- there are lots of replies --I have not read them all, if someone else
suggested this, sorry for duplication. This is similar to the suggestion using
mapply, but not specific to matrices. In fact it's a kludge that applies to
many settings. You 'sapply' over the index 1:2, and pass a, b as
Statements like c(rbind(x, xx+yy), max(t)) and rep(0,length(df$b[1])) don't
make any sense. You're example will be easier to understand if you show us the
nrow(df) ==3
case. Thanks
Grant Izmirlian, Ph.D.
Mathematical Statistician
izmir...@mail.nih.gov
Delivery Address:
9609 Medical Center Dr,
logical indexing requires the logical index to be of the same length as the
vector being indexed. If it is not, then the index
is wrapped to be of sufficient length. The result on line 3 is
y[c(TRUE, TRUE, FALSE, TRUE)] where the last TRUE was
originally the first component of !is.na(y[1:3])
Gra
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