Hi,
The following is implemented with function named subsetAll. It calls the
function subset1. The input to subset1 is the matrix A and a vector
indicating the beginning and ending values for columns 1 and 2. Input to
subsetAll is the matrix A and a matrix that is row bind from those vectors
Hi,
Maybe I missed something. The following example works. It should not
cause any problem with the same parameter names since their scopes are
within the functions.
> function2 <- function(a,b,c,d){
+ a+b+c+d}
> function2(1:2,2:3,3:4,4:5)
[1] 10 14
> function1 <- function(a,b,c,d){
+ newb <-
Hi,
I define a function named starStop with three inputs: start, stop and
increment.
> startStop <- function(start, stop, increment) {
+ for (i in seq(start, stop, increment+1)) cat(i,"-",i+increment,"\n")}
> startStop(12, 35, 5)
12 - 17
18 - 23
24 - 29
30 - 35
> startStop(42, 83, 5)
42 -
Hi,
I think what you did is correct. The row name 'comp168081_c2_seq1' is not
in the filter data frame. Neither is the row as the following small example
shows. Actually the dim(datawithoutVF) 171417 12
is different from dim(data) 171471 12. Or 171417 is not the same as
171471 altho
Hi,
I think you need quotation around I like the following:
> status
2010 2011 2012
1 AAA
2 AII
3 AAA
4 UUU
5 AAA
6 III
7 UII
8 AUA
9 IAU
10III
> apply(start,2,function(x)
Hi,
Here is my implementation:
> combine <- function(x){
+ odd <- x[1:length(x) %% 2 == 1]
+ even <- x[1:length(x) %%2 == 0]
+ paste0(odd,even)}
> temp <- letters[1:24]
> temp
[1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j" "k" "l" "m" "n" "o" "p" "q" "r"
"s" "t" "u" "v" "w" "x"
> combine(temp)
Hi,
Not sure if the following is what you look for:
>x <- c(1:10, NA, 12:20)
>sum(x[!is.na(x)])
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