stderr_int <- summary(lm(y ~ x))$coefficients[1,2]
stderr_slope <- summary(lm(y ~ x))$coefficients[2,2]
Jeff.
On Oct 3, 2007, at 3:01 AM, Alexander Moreno wrote:
> Hi,
>
> If I have two vectors x and y and I do lm(y~x) and now I want to
> define
> variables that are the standard errors of the
You were on the right track with the for loop, but often you can do
the same thing looplessly (I know, it's not really a word) in R:
If your data is like this:
data<-data.frame(ID=rep(letters[1:4], 5), size=runif(20))
then apply either
tapply(data$size, data$ID, mean)
or
aggregate(data$size
Hi Edna,
Can you send a small subset of the data as an example and the
function call you used to read the data in originally? It might be
helpful in understanding why you're losing the "time element".
Jeff.
On Oct 1, 2007, at 12:27 AM, Edna Bell wrote:
> Dear R gurus
>
> I would like to ta
I hope this will change by and by.
The more examples you see and play with, the more you'll understand.
> So I would be very pleased if you could help me once again.
>
> Greetings
>
> Birgit
Cheers,
Jeff.
>
> Am 28.09.2007 um 18:25 schrieb Jeffrey Robert Spies:
&
Not sure how you want to handle the NAs, but you could try the
following:
#start
MalVar29_37 <- read.table(textConnection("V1 V2 V3 V4 V5 V6 V7 V8 V9
0 0 0 0 0 1 0 0 0
0 0 0 0 0 1 0 0 0
0 0 0 0 0 1 0 0 0
NA NA NA NA NA NA NA NA NA
0 1 0 0 0 1 0 0 0"), header=TRUE)
How about this:
a <- matrix(cbind(rep(2, 500), rep(3, 500)), 500, 2)
b <- matrix(cbind(rep(5, 500), rep(6, 500), rep(7, 500)), 500, 3)
matrix(apply(a, c(2), "*", b), nrow=500, ncol=6)
We apply the multiplier (quoted as specified in the apply help) with
argument b to every column of a as specif
, this site is quite
useful: http://www.cs.utah.edu/dept/old/texinfo/regex/regex_toc.html.
Make sense?
Jeff.
On Sep 18, 2007, at 10:46 AM, Arun Kumar Saha wrote:
> Dear Jeffrey,
>
> Your syntax looks very extraordinary to me. I would be very happy
> if you can explain this notation.
&g
And one using regular expressions:
x <- "2005-09-01"
pattern <- '([[:digit:]]{4})-([[:digit:]]{2})-([[:digit:]]{2})'
y <- sub(pattern, '\\1', x)
m <- sub(pattern, '\\2', x)
d <- sub(pattern, '\\3', x)
-- Jeff.
On Sep 18, 2007, at 5:00 AM, Arun Kumar Saha wrote:
> Dear all,
>
> I have a variable
For the sake of absolute correctness:
> sub('[[:digit:]]{4}\.tif', '', test)
should be
sub('[[:digit:]]{4}\\.tif', '', test)
-- Jeff.
On Sep 17, 2007, at 11:59 AM, Jeffrey Robert Spies wrote:
> test <- c("060907_17_3_5_1_1_2909.tif&quo
I believe you're looking for:
dim(a)
dim(a)[1] # Number of observations, in your example, 12
dim(a)[2] # Number of variables per observation, in your example, 9
--Jeff.
On Sep 17, 2007, at 12:05 PM, Alfredo Alessandrini wrote:
> Hi everybody,
>
> If I've a data frame like this:
>
> datafram
test <- c("060907_17_3_5_1_1_2909.tif", "060907_17_3_5_2_1_2910.tif",
"060907_17_3_5_3_1_2911.tif")
sub('[[:digit:]][[:digit:]][[:digit:]][[:digit:]]\.tif', '', test)
or
test <- c("060907_17_3_5_1_1_2909.tif", "060907_17_3_5_2_1_2910.tif",
"060907_17_3_5_3_1_2911.tif")
sub('[[:digit:]]{4}\.ti
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