It was very statsy...I shoulda known better :)
stats.stackexchange answer, for posterity:
https://stats.stackexchange.com/questions/298506/bias-corrected-percentile-confidence-intervals
Joe
On Wed, Aug 16, 2017 at 1:30 PM, Joe Ceradini wrote:
> Hi folks,
>
> I'm trying to
Hi folks,
I'm trying to estimate bias-corrected percentile (BCP) confidence
intervals on a vector from a simple for loop used for resampling. I am
attempting to follow steps in Manly, B. 1998. Randomization, bootstrap
and monte carlo methods in biology. 2nd edition., p. 48. PDF of the
approach/ste
abels <- attr(terms(fmla), "term.labels")
> >> all(c("X1","X3") %in% term.labels)
> >> }
> >>
> >>> f("X3 + X2 + X1")
> >> [1] TRUE
> >>> f("- X3 + X2 + X1")
> >> [1] FALSE
>
ot;) %in% term.labels)
> }
>
>> f("X3 + X2 + X1")
> [1] TRUE
>> f("- X3 + X2 + X1")
> [1] FALSE
>> f("X3 + X2 + log(X1)")
> [1] FALSE
>> f("X3 + X2 + log(X1) + X1")
> [1] TRUE
> Bill Dunlap
> TIBCO Software
>
ep(FALSE,nbits)
>> for(i in 1:nbits) if(length(grep(xbits[i],x2))) xans[i]<-TRUE
>> return(all(xans))
>> }
>> multigrep("x1 + x3","x1 + x2 + x3")
>> [1] TRUE
>> multigrep("x1 + x4","x1 + x2 + x3")
>> [1] FALSE
>
Hi Folks,
Is there a way to find "x1 + x2 + x3" given "x1 + x3" as the pattern?
Or is that a ridiculous question, since I'm trying to find something
based on a pattern that doesn't exist?
test <- c("x1", "x2", "x3", "x1 + x2 + x3")
test
[1] "x1" "x2" "x3" "x1 + x2 +
0 39600
> >
> > as.numeric(hm("10:00"))
> [1] 36000
> >
>
> -Roy
>
>
> > On Jan 2, 2017, at 12:39 PM, Joe Ceradini wrote:
> >
> > Bingo! Thanks! I somehow couldn't find an example like that via google.
> >
> > Joe
> >
0S" "11H 0M 0S"
>
> -Roy
>
>
>> On Jan 2, 2017, at 12:27 PM, Joe Ceradini wrote:
>>
>> Thanks for the reply Roy!
>>
>> Perhaps you're showing me the way and I'm missing it - how would I
>> subset to only 1030 and 1100, exc
anks again.
On Mon, Jan 2, 2017 at 1:13 PM, Roy Mendelssohn - NOAA Federal
wrote:
> Hi Joe:
>
> See below.
>> On Jan 2, 2017, at 12:01 PM, Joe Ceradini wrote:
>>
>> Hi folks,
>>
>> I must be missing something obvious/painfully simple here
>>
>>
Hi folks,
I must be missing something obvious/painfully simple here
How do I subset a time vector based on hours AND minutes? So, in this
example, I want all time greater than 10:00, i.e., 10:30 and 11:00.
I'm working with lubridate which separates the hours and minutes into
separate slots.
ested in seeing those solutions as well.
Thanks,
Joe
On Mon, Oct 24, 2016 at 3:42 PM, David Wolfskill wrote:
>
> On Mon, Oct 24, 2016 at 03:33:20PM -0600, Joe Ceradini wrote:
> > R Helpers,
> >
> > I would like to extract the entire word beginning with "BT" (
R Helpers,
I would like to extract the entire word beginning with "BT" (or "BT-")
and not any thing else in the string. Or, I would like to extract from
BT up until the next space.
test <- data.frame(x = c("abc", "Sample BT-1501-2E stuff", "Bt-1599-3E stuff"))
test
So, from test$x I would like t
at gives you more flexibility in specifying what to look
> for in the structure of the data, then extract only those pieces that
> you want.
>
>
> On Fri, Oct 14, 2016 at 5:16 PM, Joe Ceradini
> wrote:
> > Afternoon,
> >
> > I unfortunately inherited a dat
mercy :)
Joe Ceradini
University of Wyoming
~~~
On 10/14/16, David Wolfskill wrote:
> Happy Friday, indeed.
>
> It seems to me that the data need a bit of cleamup before attempting to
> parse -- for example, that "F" looks to b
should be strsplit(ugly, attributes) not strplit(ugly, attributes)
On Fri, Oct 14, 2016 at 7:53 PM, Joe Ceradini wrote:
> Hopefully this looks better. I did not realize gmail default was html.
>
> I have a dataframe with a column that has many field smashed together.
> I need
Hopefully this looks better. I did not realize gmail default was html.
I have a dataframe with a column that has many field smashed together.
I need to split the strings in the column into separate columns based
on patterns.
Example of a string that needs to be split:
ugly <- c("Water temp:14: F
Afternoon,
I unfortunately inherited a dataframe with a column that has many fields
smashed together. My goal is to split the strings in the column into
separate columns based on patterns.
Example of what I'm working with:
ugly <- c("Water temp:14: F Waterbody type:Permanent Lake/Pond: Water
pH:
read.csv("your_data.csv", stringsAsFactors=FALSE)
(I'm just reiterating Jianling said...)
Joe
On Tue, Sep 20, 2016 at 4:56 PM, lily li wrote:
> Is there a function in read.csv that I can use to avoid converting numeric
> to factor? Thanks a lot.
>
>
>
> On Tue, Sep 20, 2016 at 4:42 PM, lily li
Guru
>
> What is the problem that you are trying to solve?
> Tell me what you want to do, not how you want to do it.
>
> On Wed, Sep 14, 2016 at 12:25 PM, Joe Ceradini
> wrote:
>
>> Hi all,
>>
>> There are many R help posts out there dealing with slash
> [1] 9 9 9 9
> > write.csv(test2)
> "","x"
> "1","8/24/2016"
> "2","8/24/2016"
> "3","6/16/2016"
> "4","6/16/2016"
>
> -----
> David L Carlson
> Departm
Hi all,
There are many R help posts out there dealing with slashes in gsub. I
understand slashes are "escape characters" and thus need to be treated
differently, and display differently in R. However, I'm still stuck on
find-replace problem, and would appreciate any tips. Thanks!
GOAL: replace al
Also, this starting happening for me with R studio 0.99.893, so if you have
a different version, maybe it is a different issue (or maybe it is a
different issue regardless...).
Joe
On Thu, May 19, 2016 at 7:27 AM, Joe Ceradini wrote:
> I had this problem as well, a lot, and it was frustrat
I had this problem as well, a lot, and it was frustrating and I did not
find much reference to it online. I believe it occurs after you run a plot
and then make the plotting window too small for R studio to redraw the
plot. Then when run a line of code, it never runs or appears to be running
indefi
Hi Folks,
Hopefully this question has enough R and not too much stats to be
appropriate for this list. Based on,* Hosmer et al. 2013. Logistic
regression for matched case-control studies. Applied Logistic
Regression *(eqtn.
7.8)*, *I am assessing GOF of conditional (or matched) logistic regression
Does this do what you want?
aggregate(Nuclei ~ Slide, example, sum)
On Fri, Jan 22, 2016 at 12:20 PM, Ed Siefker wrote:
> Aggregate does the right thing with column names when passing it
> numerical coordinates.
> Given a dataframe like this:
>
> Nuclei Positive Nuclei Slide
> 1133
Thanks Terry!
I thought that since I was providing survConcordance with the model object
that the same formula would be applied. But I was obviously wrong. I just
ran survConcordance with the addition of the strata argument, as you
suggested, and got the same answer as summary(fit)with the sam
r(site), method ="efron",
> data = dat) # warning
> fit <- clogit(resp ~ x1 + x2 + strata(ID) + cluster(site), method
> ="efron", data = dat) # no warning
> summary(fit)
>
> Chris
>
> -Original Message-
> From: Joe Ceradini [mailto:j
Hi,
I'm running conditional logistic regression with survival::clogit. I have
"1-1 case-control" data, i.e., there is 1 case and 1 control in each strata.
Model:
fit <- clogit(resp ~ x1 + x2, strata(ID), cluster(site), method ="efron",
data = dat)
Where resp is 1's and 0's, and x1 and x2 are both
Caroline - the phidot forum is an *excellent* spot to post this question.
There is an entire RMark subforum.
www.phidot.org/forum/index.php
Even just searching this forum will probably give you some answers.
Also, this book has a whole section on individual covariates and approaches
for dealing wi
R-helpers,
I am trying to make a panel of ggplots with universal Y and X axes. There
are many examples that show how to do this with grid.arrange. However, my x
axis label looks like it is (maybe) overwritten by the margin of the lower
left plot and I cannot figure out how to fix it. I realize thi
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