>Well, use the manual setup as indicated in the readme cinatined in the
package. No idea what went wrong in this case.
OK, thanks.
John Se
**
**
2011/3/2 Uwe Ligges
>
>
> On 01.03.2011 11:01, John Seers wrote:
&
Thanks Robert. I will have a look at it.
John Seers
**
**
On Wed, Mar 2, 2011 at 3
-C="R-WinEdt"
-E="C:\Program Files (x86)\WinEdt Team\WinEdt 6\R.ini""' execution failed
with error code 1
>
Does it matter if you are using 64 bit R and the 32 bit WinEdt? (I have
tried 32 bit R).
Does RWin
Dallazuanna [mailto:www...@gmail.com]
Sent: 19 January 2009 12:30
To: john seers (IFR)
Cc: r-help@r-project.org
Subject: Re: [R] How to assign names in a list
If I understand correctly:
names(list2) <- paste("name", 1:3, sep = "")
On Mon, Jan 19, 2009 at 10:23 AM, john seers
Hi All
How can you associate names with a list when names have not been
assigned? For example if you have a list like this:
list2<-list(1,2,3)
list2
[[1]]
[1] 1
[[2]]
[1] 2
[[3]]
[1] 3
How do you make it look like this with names? :
f1<-1
f2<-2
f3<-3
list1<-list(name1=f1, name2=f2, name3
Hi
qqline does not do the plot. It adds a line to an existing plot.
So you have to do something else first, like:
qqnorm(x)
qqline(x)
JS
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Scotty Nelson
Sent: 05 August 2008 09:58
To: r-help@r-pro
Is this what you want:
paste("Mystring", frequency, sep="")
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Alfredo Alessandrini
Sent: 31 July 2008 10:11
To: r-help@r-project.org
Subject: [R] add string
Hi,
How can I join two string?
frequency
Q1:
Have a look at:
?save
?save.image
?load
Q2:
I am not sure this is right:
model<-lm(data$admissions~data$maxitemp)
Try and code a line that looks more like this with the variables the
names of the columns in your data:
model<-lm(admissions ~ maxitemp + minitemp, data=data)
Have a read
Something like this might do what you want:
dates<-paste(c("2008"), c("Jan", "Feb", "Sep", "Sep", "Dec"), 1:3,
sep="")
temp<-rnorm(length(dates))*30
data1<-data.frame(Dates=dates, Temp=temp)
data.s1<-data1[grep("Sep", data1[["Dates"]]),]
> data.s1
Dates Temp
3 2008Sep3 22.263627
4 2
This is definitely the best way:
c(lapply(1:length(x), function(i, x, y) c(x[i], y[i]), x, y),
recursive=TRUE)
JS
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Shubha Vishwanath Karanth
Sent: 23 July 2008 13:55
To: [EMAIL PROTECTED]
Sub
Hi Fabio
Have you used the name "c" for something else? Try typing in "c" at the
command line, you should see something like:
> c
function (..., recursive = FALSE) .Primitive("c")
Regards
John
---
for example;
> par(mfrow=c(2,2))
Error in c(2, 2) : unused argument(s) (2)
> par$mfr
Hi Fabio
Works OK for me.
> par(mfrow=c(2,2))
> par("mfrow")
[1] 2 2
>
But then I am using Windows ...
> sessionInfo()
R version 2.7.1 (2008-06-23)
i386-pc-mingw32
locale:
LC_COLLATE=English_United Kingdom.1252;LC_CTYPE=English_United
Kingdom.1252;LC_MONETARY=English_United
Kingdom.1252
nal Message-
From: A Ezhil [mailto:[EMAIL PROTECTED]
Sent: 10 July 2008 16:23
To: r-help@r-project.org; john seers (IFR)
Subject: RE: [R] false discovery rate !
Dear John,
My P values are not same and the smallest P value = 0.0002. My P value
distribution is not that great (see the attached f
Hi
Are all your input p values the same? If so your output FDR values would
be the same.
Or are all your p-values relatively large? Then (nearly) all your FDR
values might be 1.
Why don't you put a small example up of what you did? Then we could see
what method you used etc.
Regards
JS
the same thing?
Regards
JS
---
-Original Message-
From: Prof Brian Ripley [mailto:[EMAIL PROTECTED]
Sent: 27 June 2008 11:10
To: john seers (IFR)
Cc: jim holtman; juli pausas; R-help
Subject: Re: [R] removing blanks from a string
There are well-informed answers given as examples o
There is also the "trim" command in the gdata package. Removes blanks
from the front of the string as well which may not be what you want.
Regards
JS
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of jim holtman
Sent: 27 June 2008 10:27
To: jul
Something like this may be close to what you want:
subset(input, field1=="blah1" & !is.na(charmatch("blah3",input$field3)))
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Albert Vilella
Sent: 29 May 2008 11:38
To: r-help@r-project.org
Subject: [
Try:
mat <- mat[order(rownames(mat)), ]
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Paul Geeleher
Sent: 19 May 2008 12:07
To: r-help@r-project.org
Subject: [R] Sort matrix with duplicate row names alphabetically by
rowname
Hi,
I've a matri
ributed package.
Sorry if it is off topic. I was not sure, so I took the middle road of
posting to R-help and the package owner.
Regards
John Seers
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read th
(rtest.java) and get the results below. I do
not think the notes about a deprecated API are a problem. But I do not
know what causes the unsupported conversion messages.
Versions used etc below.
Any ideas please? Thanks for any help.
Regards
John Seers
Hi Chib
>>whether there is a way of handling the error you get in the
download.file() function
I think the function "try" will do this for you. That is, handle the
error.
Have a look at ?try.
Regards
John Seers
---
-Original Message-
From: [EMAIL PROTECTED
Thank you very much for your help - that fixed it. Sorry I did not see
it in the manual.
Regards
JS
---
-Original Message-
From: Prof Brian Ripley [mailto:[EMAIL PROTECTED]
Sent: 19 February 2008 14:14
To: john seers (IFR)
Cc: r-help@r-project.org
Subject: Re: [R] Building a
Hi
A simple example of a linear model:
x<-1:10
y<-3*x+1
m1<-lm(y~x)
y
# [1] 4 7 10 13 16 19 22 25 28 31
fitted(m1)
# 1 2 3 4 5 6 7 8 9 10
# 4 7 10 13 16 19 22 25 28 31
The fitted and calculated values look identical to me.
Can you give an example of how your calculated values
r how to alter it. Can
anybody point me to some documentation?
Thanks very much for any help.
Regards
John Seers
> sessionInfo()
R version 2.6.2 (2008-02-08)
i386-pc-mingw32
locale:
LC_COLLATE=English_United Kingdom.1252;LC_CTYPE=English_United
Kingdom.1252;LC_MONETARY=English
Hi Corinna
The p.adjusted value is the the p-value adjusted for Multiple
Comparisons.
Enter ?p.adjust to get more of an explanation.
Regards
JS
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Schmitt, Corinna
Sent: 11 February 2008 16:02
To: r
OK, that looks a good suggestion. Though it is a bit of a step towards loops
and counting ...
Thanks a lot.
Regards
JS
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Tue 2/5/2008 4:51 PM
To: john seers (IFR)
Cc: R Help
Subject: Re: [R] Using lapply
plot the
data (or whatever) and be able to slap a label on it so I can keep track
of what I am doing.
Regards
John Seers
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: 05 February 2008 16:17
To: john seers (IFR)
Cc: R Help
Subject: Re: [R] Using lapply and
Hi KB
I am not sure exactly what you want to do but perhaps this is this
closer to what you need:
addition<-function(X, a){Xnew<-X + a}
X<-array(1,dim=c(2,2))
a<-2
Xa<-addition(X,a)
Xa
Regards
JS
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf O
t, names(people))
dev.off()
#
Thank you for any suggestions.
John Seers
---
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.h
Hi
I think this is a good suggestion.
And I would like to add the associated problem of deciding between
packages that do the same function which one is "better". Or similarly
packages are often superceded. I find I have to spend a lot of time
learning how to use packages to decide which one
When you start R you get this information:
R is a collaborative project with many contributors.
Type 'contributors()' for more information and
'citation()' on how to cite R or R packages in publications.
That should help answer your question.
Regards
JS
---
-Original Message-
From
Thanks for the help.
Regards
John Seers
---
-Original Message-
From: Peter Dalgaard [mailto:[EMAIL PROTECTED]
Sent: 01 February 2008 10:04
To: [EMAIL PROTECTED]
Cc: john seers (IFR); [EMAIL PROTECTED]
Subject: Re: [R] Building a formula using paste
[EMAIL PROTECTED] wrote
Thank you very much. That problem has been niggling me for some time.
I slotted in your code and it worked. I just need to spend a bit of time
understanding it ...
Thanks again.
John Seers
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: 01
o the formula appears in the model summary?
Regards
John Seers
> sessionInfo()
R version 2.6.1 (2007-11-26)
i386-pc-mingw32
locale:
LC_COLLATE=English_United Kingdom.1252;LC_CTYPE=English_United
Kingdom.1252;LC_MONETARY=English_United
Kingdom.1252;LC_NUMERIC=C;LC_TIME=English_United Kingd
Hi
Are you sure this is an R problem? The "Choose" dialog can be very slow
if you have networked directories that cannot be connected to. Windows
tries to connect repeatedly and each time waits for a timeout. Suggest
you check your mapped network drives.
Regards
JS
---
Dear R users
sinc
Hi
I am running under Windows XP using R2.6.1.
I pasted your code in my Rprofile.site in the etc directory and it
worked for me.
All I can suugest is:
1. Check you really put it in the etc directory. (Do you have an old
version of R somewhere ...?)
2. Is it really called Rprofile.site. (Not .
Hello
Works fine for me:
> data
<-scan(file='http://en.wikipedia.org/wiki/Special:Recentchanges',what='c
haracter')
Read 3581 items
>
So I don't think it is the Wikipedia end.
Regards
John Seers
---
-Original Message-
From: [EMAIL PROTE
100
csvalues<-NULL
for (i in 1:(length(testdata)/25)) {
st<-(i-1) * 25 + 1
sel<-st:(st+24)
selvals<-testdata[sel]
csvalues<-c(csvalues, scale(selvals, scale=sd(selvals)))
}
Thanks for any help.
John Seers
---
John Seers
Institute of Food Research
Norwich Re
Ah, that is neat.
Thanks.
JS
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: 16 November 2007 15:12
To: john seers (IFR)
Cc: r-help@r-project.org
Subject: Re: [R] Scaling a column in groups
Try this:
c(apply(matrix(testdata, 25), 2, scale))
On Nov 16
[1] grid_2.6.0
>
---
John Seers
Institute of Food Research
Norwich Research Park
Colney
Norwich
NR4 7UA
tel +44 (0)1603 251497
fax +44 (0)1603 507723
e-mail [EMAIL PROTECTED]
e-disclaimer at http://www.ifr.ac.uk/edisclaimer/
Web sites:
www.ifr
.
Regards
John Seers
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hi Peter
Perhaps "get" is what you need?
foo.bar <- list( "a"= "a", "b"=1 )
save( file="foo.bar.RData", foo.bar )
rm( foo.bar )
my.fn <- function( fname ) {
load( fname )
attach( get(ls( pat="foo" )) ) # works
#attach( foo.bar ) # works
}
Regards
tup from the environment
variable R_LIBS (which should be a semicolon-separated list of
directories at which R library trees are rooted) followed by those in
environment variable R_LIBS_USER.
john seers (IFR) wrote:
>
> I use the following method which works well for me.
>
> I create
Hi
I use the following method which works well for me.
I create a directory to hold the installed packages e.g. C:\Program
Files\R\mylibrary
Then in my C:\Program Files\R\R-2.5.1\.Renviron file I have a line as
follows:
R_LIBS=C:/PROGRA~1/R/mylibrary
(I think you have to use Windows short
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