:
>
> > On Oct 6, 2015, at 7:58 AM, Lorenz, David wrote:
> >
> > Did you verify that the correct percentages were above/below the
> regression
> > lines? I did a quick check and for example did not consistently get 50%
> of
> > the observed response values gre
Did you verify that the correct percentages were above/below the regression
lines? I did a quick check and for example did not consistently get 50% of
the observed response values greater than the tau=.5 line. I did when I
included the nonzero intercept term.
> Date: Mon, 5 Oct 2015 21:14:04 +05
I think that the issue, at least with the online calculator that I looked
at, is that it does not adjust the standard deviation of the test
statistic for ties, so the standard deviation is larger and hence larger
p-value. I was able to reproduce the reported z-score using the equation
for the st
Merve,
I'm not 100 percent sure I understand everything that you want. But start
with the simulated likert scale data. The code that you have is not very
efficient and it has at least one typo. I do not know if columns or rows
represent the persons, so I'll set up as NROW and NCOL.
An efficient
Elisa,
Part of the issue is that there is no unique solution. You could increase
each of the 6 values by a fixed amount to make up the 0.242003 difference
in area, or you could increase them proportionally, among many other
schemes.
I'll outline an approach and you can decide how you want to pr
Pavlos,
There are several ways to evaluate how well new data fit an old
regression.Part of the answer depends on what you are concerned about. For
example, if you are concerned about bias, you can test whether the mean of
the new data is within the expected range of the mean of that many new
valu
Andrea,
The argument na.action controls how missings are treated. is this what
you wanted?
aggregate(cbind(IND, DUM)~.,data=net1,sum, na.action=na.pass)
Dave
>Date: Mon, 16 Sep 2013 11:42:07 -0400
>From: Andrea Goijman
>To: arun
>Cc: R help
>Subject: Re: [R] Aggregate rows with same fields,
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