On Oct 24, 2013, at 1:11 PM, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
On 24/10/2013 18:25, Marc Schwartz wrote:
On Oct 24, 2013, at 11:38 AM, David Winsemius dwinsem...@comcast.net wrote:
On Oct 23, 2013, at 7:53 PM, Long Vo wrote:
Hi R users,
Currently I want to fit a FIGARCH
://biostat.mc.vanderbilt.edu/wiki/Main/CatContinuous
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and provide commented, minimal
method:
Y - as.integer(Y = mean(Y))
Y
[1] 0 1 0 1 1 0 1 1 1 0
That being said, the original viewpoint stands, which is to not do this due to
loss of information.
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Marc Schwartz
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(min(bla, as.character(NA)))
chr bla
It would appear that in Magnus' example, that NA is passed as a logical in the
argument list may be relevant here.
BTW, I can reproduce Magnus' example on 3.0.2 on OSX (10.8.5).
Regards,
Marc Schwartz
On Sep 26, 2013, at 10:40 AM, arun smartpink
= TRUE) # depends upon 'R.oo'
require(R.utils)
?readWindowsShortcut
Regards,
Marc Schwartz
On Sep 26, 2013, at 5:05 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
Hi,
On Thu, Sep 26, 2013 at 4:54 PM, Santosh santosh2...@gmail.com wrote:
Dear Rxperts,
Through Windows OS, I created
do, but it's very hard to get it to do something
the designers didn't think of.
Duncan Murdoch
Fortune candidate, with cc: to Z.
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PLEASE do
the docs?
Thanks!
The latter. From ?strplit in the description of 'split':
If split has length greater than 1, it is re-cycled along x.
Thus, in the first example above, ',' is used for the first element of your
vector and ';' is used for the second and so on.
Regards,
Marc Schwartz
316.17
education 2 0.0022894 245 316.17 0.9989
Regards,
Marc Schwartz
On Sep 11, 2013, at 11:17 AM, Torvon tor...@gmail.com wrote:
José,
I get the following error message:
m1-clm(sym_bin ~ phq_index, data=data2)
m2-clm(sym_bin ~ 1, data=data2)
anova(m1,m2
is a description of the
various parameters for the plot.
Thus:
set.seed(1)
boxplot(rexp(50), outcol = red)
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Marc Schwartz
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).
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the Posting Guide:
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and provide
the '-' to ':', which can then be parsed as a sequence operator.
The paste() creates:
paste(c(, gsub(\\-, :, x), ))
[1] c( 2,5:7,10,12:15 )
which can then be evaluated as a single vector.
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Marc Schwartz
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row.names = TRUE. Picked up in the
course of fixing the above bug.
Source tarballs of the updated package are being mirrored and binaries for
Windows and OSX should appear in due course.
Regards,
Marc Schwartz
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this issue, and it has taken me a long time.
Frailty is an alternate label for random effects when all we have is a
random intercept. Multiple labels for the same idea adds confusion, but
nothing else.
Terry Therneau
On 07/25/2013 08:14 PM, Marc Schwartz wrote:
On Jul 25, 2013, at 4
to the Windows side in
the VM to see the files as the author intended.
Rich
On Wed, Jul 24, 2013 at 12:16 PM, Marc Schwartz
marc_schwa...@me.comwrote:
Hi Rich,
Seems to work for me using Powerpoint in MS Office 2011 for Mac.
I used the following code:
postscript(file
.
Thank you
Caveman
On Wed, Jul 24, 2013 at 2:27 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Jul 23, 2013, at 5:40 PM, cognizio ge...@uyleman.com wrote:
Great summary! It works great without the heavy PERL library. I am
running
the YAML package I thought I needed to support WRITEXLS
in windows PP 2010 and as an icon in PP 2013.
RPlot2.pptx https://www.dropbox.com/s/snm7cb9chrkcrff/RPlot2.pptx opens
as a graph in both windows PP and in Mac PP.
On Wed, Jul 24, 2013 at 2:39 PM, Marc Schwartz marc_schwa...@me.comwrote:
Rich,
I don't have direct access to Windows and I
went fine.
Orvalho
On Thu, Jul 25, 2013 at 3:00 PM, Marc Schwartz marc_schwa...@me.com wrote:
Hi,
Perl is still required for WriteXLS. That dependency has not changed.
What did change is that I removed the requirement for Text::CSV_XS, which
contains C code in the Perl package
...@temple.edu
wrote:
file2.eps opens as a graph in windows PP 2010 and as an icon in PP
2013.
RPlot2.pptx https://www.dropbox.com/s/snm7cb9chrkcrff/RPlot2.pptx
opens
as a graph in both windows PP and in Mac PP.
On Wed, Jul 24, 2013 at 2:39 PM, Marc Schwartz marc_schwa...@me.com
wrote:
Rich
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On Jul 25, 2013, at 4:45 PM, David Winsemius dwinsem...@comcast.net wrote:
On Jul 25, 2013, at 12:27 PM, Marc Schwartz wrote:
On Jul 25, 2013, at 2:11 PM, John Sorkin jsor...@grecc.umaryland.edu wrote:
Colleagues,
Is there any R package that will allow one to perform a repeated
0.4 0.3 0.2 0.2 0.1 ...
..- attr(*, comment)= chr Width of the petals (cm)
$ Species : Factor w/ 3 levels setosa,versicolor,..: 1 1 1 1 1 1 1 1 1
1 ...
..- attr(*, comment)= chr Species of the flowers
Regards,
Marc Schwartz
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.
If you are operating on Windows, as opposed to Linux or OSX, typically EMF/WMF
files are the easiest way to go in terms of sticking R plots into an Office
file, as they are also vector based images, but are effectively Windows only.
Regards,
Marc Schwartz
On Jul 24, 2013, at 10:20 AM
. PP did not generate its
own png file.
Since my immediate goal is the projection screen for a PowerPoint
presentation, I will go
directly to the png file. For the proceedings and for paper I will continue
to use the pdf file.
Rich
On Wed, Jul 24, 2013 at 11:36 AM, Marc Schwartz
as the author intended.
Rich
On Wed, Jul 24, 2013 at 12:16 PM, Marc Schwartz marc_schwa...@me.comwrote:
Hi Rich,
Seems to work for me using Powerpoint in MS Office 2011 for Mac.
I used the following code:
postscript(file = file.eps, height = 4, width = 4
is
plot(1:10)
which is base.
did you try the windows side yet?
Rich
Sent from my iPhone
On Jul 24, 2013, at 13:22, Marc Schwartz marc_schwa...@me.com wrote:
Hi Rich,
That's curious.
I noted that you are using barchart() below which is lattice versus base
graphics
, providing descriptive
information on the content of the column in the Excel worksheet.
The package is openly maintained under GPL-2 at:
https://github.com/marcschwartz/WriteXLS
If anyone identifies any issues, please let me know.
Thanks and regards,
Marc Schwartz
counts
within groups.
On Wed, Jul 17, 2013 at 5:04 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Jul 17, 2013, at 4:43 PM, Witold E Wolski wewol...@gmail.com wrote:
I would like to cut a vector into groups of equal nr of elements.
looking for a function on the lines of cut but where I
of the CRAN package is restricted.
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Marc Schwartz
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the readPC() function therein.
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and provide commented, minimal, self
0.273 0.000 0.273
system.time(mat.left - t(big.mat)[nrow(big.mat):1], )
user system elapsed
0.094 0.000 0.099
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Marc Schwartz
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PLEASE do read
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
, install a binary using a package manager like yum or did you download
the source tarball, compile and install?
Need more information.
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Marc Schwartz
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PLEASE do read
./configure
make
make install
Thanks!
On Fri, Jul 12, 2013 at 12:12 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Jul 12, 2013, at 11:58 AM, Chirag Gupta cxg...@email.uark.edu wrote:
Hi
I am trying to upgrade R version 2.11 to 3.0.1 on Linux server.
I downloaded the latest version
volume list. 116 posts in 2010, 77 in 2011, 72 in 2012 and
25 so far in 2013. The trend would seem to be downward.
Regards,
Marc Schwartz
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required package: parallel
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on subscribing is here:
https://stat.ethz.ch/mailman/listinfo/r-sig-fedora
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Marc Schwartz
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, I would
envision that the effective number of your factor levels is reduced as a
consequence, allowing the model to be fit.
You likely need to consider collapsing some of the low count factor levels into
an Other category, if it makes contextual sense to do so for your data.
Regards,
Marc
for the target OS's, which obviates the need for the user to have C related
development tools installed locally.
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Marc Schwartz
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# missing the preceding code where 'a' was
# defined globally
f - function(x) { a-5; g(x) }
g - function(y) y + a
# Now it works, showing that 'a - 5' within f() is not part of the
# value returned by g(), which is the goal of John's example code :-)
f(2)
[1] 12
Regards,
Marc Schwartz
, x3, x4) == 1)
[1] 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0
which gets you the same result as:
ifelse(x1 == 1 | x2 == 1 | x3 == 1 | x4 == 1, 1, 0)
[1] 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0
Regards,
Marc Schwartz
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) == 1)
[1] 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0
which gets you the same result as:
ifelse(x1 == 1 | x2 == 1 | x3 == 1 | x4 == 1, 1, 0)
[1] 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0
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Marc Schwartz
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On Jun 19, 2013, at 1:23 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Jun 19, 2013, at 8:24 AM, Brian Perron beper...@umich.edu wrote:
Greetings:
I am looking for a way to avoid using the ifelse function for
constructing a new variable. More specifically, assume I have a set
On Jun 19, 2013, at 1:23 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Jun 19, 2013, at 8:24 AM, Brian Perron beper...@umich.edu wrote:
Greetings:
I am looking for a way to avoid using the ifelse function for
constructing a new variable. More specifically, assume I have a set
to legend().
Regards,
Marc Schwartz
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and provide commented, minimal, self-contained
str(y) and str(group)
You should also be sure to note in your posts when you are using a function
from a non-base package, in this case MASS, which is not indicated in your
sessionInfo() above, so something is amiss there as well.
Regards,
Marc Schwartz
' is:
group
[1] 1 1 1 1 0 0 0 0
glm.nb(y ~ group)
Error in while ((it - it + 1) limit abs(del) eps) { :
missing value where TRUE/FALSE needed
Think about it... :-)
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Marc Schwartz
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is with the two relevant CRAN Task Views:
http://cran.r-project.org/web/views/ClinicalTrials.html
and
http://cran.r-project.org/web/views/Pharmacokinetics.html
There is also another package not listed above that might be relevant:
http://cran.r-project.org/web/packages/scaRabee/
Regards,
Marc
In addition to the manner in which the PDF files are generated, you might want
to consider the possibility that the lines are artifacts created by your PDF
viewer.
See:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-are-there-unwanted-borders
Regards,
Marc Schwartz
On Jun 3, 2013
.
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}
\toprule
V1 \\
\midrule
a9 \\
b8 \\
c 17 \\
d9 \\
e7 \\
f 16 \\
g 13 \\
h 10 \\
i 11 \\
\bottomrule
\end{tabular}
\end{table}
Regards,
Marc Schwartz
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success with JDBC and there is the ODB package on CRAN
(http://cran.r-project.org/web/packages/ODB/).
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Marc Schwartz
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PLEASE do read the posting guide http://www.R
-project.org/doc/manuals/r-release/R-intro.html#Missing-values
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Marc Schwartz
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and provide
sample(Vec)
[1] 1 0 1 1 1 1 1 1 0 1
sample(Vec)
[1] 1 0 1 0 1 1 1 1 1 1
sample(Vec)
[1] 1 1 1 0 1 1 1 0 1 1
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Marc Schwartz
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On Apr 22, 2013, at 6:28 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Apr 22, 2013, at 6:21 PM, Ayyappa ayyapp...@gmail.com wrote:
Dear group,
I want to generate a vector of 10 elements that always has 20% zeroes, but
with a random ordering of zeroes and ones. Can you please suggest
error: 2.717 on 21 degrees of freedom
Multiple R-squared: 0.8623,Adjusted R-squared: 0.7967
F-statistic: 13.15 on 10 and 21 DF, p-value: 6.237e-07
This is covered in ?formula
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Marc Schwartz
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at:
https://github.com/marcschwartz/R-IQ-OQ
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Marc Schwartz
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http://cran.r-project.org/web/packages/betareg/vignettes/betareg-ext.pdf
Regards,
Marc Schwartz
On Apr 16, 2013, at 3:20 PM, Noah Silverman noahsilver...@ucla.edu wrote:
@Duncan, You make a very good point. Somehow I overlooked that 0 is not
positive. I guess that rules out the log
?summary.survfit and note the 'table' part of the Value section.
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Marc Schwartz
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On Apr 11, 2013, at 1:34 PM, Fisher Dennis fis...@plessthan.com wrote:
Colleagues
During the transition to R3.0.0 (OS X), one of the packages that I used --
SASxport -- did not work until I used the type=source option in
install.packages.
This led to an adventure:
1. I
1.405 2.365 8.6 72
2 7.20 1.790 2.270 6.2 55
3 7.16 2.480 2.685 10.1 56
4 7.87 1.725 2.250 9.3 63
5 7.24 2.745 2.785 11.5 68
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somebody help me why is it so?
Thanks and regards
The dollar sign is a metacharacter in regular expressions (see ?regex), thus
has to be escaped to be interpreted as a literal character:
gsub(\\$|,, , $232,685.35436)
[1] 232685.35436
Regards,
Marc Schwartz
to keep
them separated. Most e-mail clients and/or online services have some type of
filtering or rule configuration available to do this.
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Marc Schwartz
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PLEASE
On Mar 27, 2013, at 7:53 PM, David Winsemius dwinsem...@comcast.net wrote:
On Mar 27, 2013, at 12:18 PM, Marc Schwartz wrote:
On Mar 27, 2013, at 1:58 PM, Katherine Gobin katherine_go...@yahoo.com
wrote:
Dear R helpers,
Everyday I do receive many many mails from R forum and after
In full agreement with Sarah's comments.
That being said, the Magic 8 Ball has the following in the little window for
the OP:
?rle
Regards,
Marc Schwartz
On Mar 25, 2013, at 2:44 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
This is unreadable. Please repost in plain text, ideally
passed to the
model function, to replicate what takes place internally in many modeling
functions. The result of model.frame() will be a data frame, again, subject to
similar limitations as above.
Regards,
Marc Schwartz
[1]: http://developer.r-project.org/model-fitting-functions.txt
like this?
xtabs(Y ~ X1 + X2, data = tmp.n)
X2
X1 0 2 4
0 83 12 14
1 107 25 27
2 47 14 28
3 27 4 13
4 38 9 18
99 1 0 0
See ?xtabs
Regards,
Marc Schwartz
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K2 207
X4 X4 63
Regards,
Marc Schwartz
On Mar 15, 2013, at 12:37 PM, arun smartpink...@yahoo.com wrote:
Hi,
Try:
data.frame(Forecast=with(PeriodSKUForecast,tapply(Forecast,SKU,head,1)))
# Forecast
#A1 99
#K2 207
#X4 63
#or
aggregate(Forecast~SKU
in the character vector:
Vec - c(sada, asdsa, sa)
format(Vec)
[1] sada asdsa sa
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Marc Schwartz
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the function.
I would however, urge you to reconsider what you are doing and take advantage
of R's philosophy and therefore, strengths. It may be that coercing your source
vector to a list would serve you well.
Regards,
Marc Schwartz
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This could be done in a single step using gsub() with back references in the
regex.
gsub(^(.{3}).* (.{3}).*$, \\1\\2, Tom Cruise)
[1] TomCru
Regards,
Marc Schwartz
On Mar 13, 2013, at 9:21 AM, SH empti...@gmail.com wrote:
What I want to do is to extrac three letters from first and last
= FALSE))
or directly on the data:
attr(ns(women$height, df = 5), knots)
20% 40% 60% 80%
60.8 63.6 66.4 69.2
attr(ns(women$height, df = 5), Boundary.knots)
[1] 58 72
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Marc Schwartz
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of page 23
B. Footnote 15 on page 26
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Marc Schwartz
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and the reply from Peter also:
http://tolstoy.newcastle.edu.au/R/devel/06/06/5868.html
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Marc Schwartz
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, there are two R SIG lists that you may want to be aware of:
https://stat.ethz.ch/mailman/listinfo/r-sig-debian
and:
https://stat.ethz.ch/mailman/listinfo/r-sig-db
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Marc Schwartz
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are delimiters, separating what you have as a single
argument into multiples.
Use ?shQuote to put single quotes around each argument that contains spaces, so
that it is treated as a single argument:
shQuote(This is a single argument)
[1] 'This is a single argument'
Regards,
Marc Schwartz
, then you might want to look at simulation.
If the latter, you might want to look at the Clinical Trials Task View:
http://cran.r-project.org/web/views/ClinicalTrials.html
as there are various packages that might fit what you need, but again,
simulation is always an option.
Regards,
Marc
2
Regards,
Marc Schwartz
On Mar 6, 2013, at 8:42 PM, arun smartpink...@yahoo.com wrote:
Hi,
dfrm- read.table(text=
Point_counts Psi_Sp
1A 0
2A 1
3B 1
4B
-doesn_0027t-R-think-these-numbers-are-equal_003f
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-fedora:
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minutes reading the manuals is typically enlightening.
Regards,
Marc Schwartz
On Feb 22, 2013, at 9:48 AM, Gyanendra Pokharel gyanendra.pokha...@gmail.com
wrote:
I can't see your attached file. Can you re-attache it?
Thanks
Gyanendra Pokharel
University of Guelph
Guelph, ON
On Fri, Feb
the requisite
compiler related tools installed.
Perhaps I need more coffee late on a Friday, but something seems inconsistent
here.
Regards,
Marc Schwartz
On Feb 22, 2013, at 12:15 PM, londonphd wrote:
Hi, I have not been able to use R in my macbook pro. I am getting the
following error
/07/6331.html
Regards,
Marc Schwartz
On Feb 20, 2013, at 9:58 AM, Bruce McCullough bdmccullo...@drexel.edu wrote:
The idea that the Excel solver has a good reputation for being fast and
accurate does not withstand an examination of the Excel solver's
ability to solve the StRD nls test
the NA's, then the result is undefined:
sum(c(NA, NA))
[1] NA
See:
http://rwiki.sciviews.org/doku.php?id=tips:surprises:emptysetfuncs
for more information.
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Marc Schwartz
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0
I want to have some way to distinguish the 1st '0' and the 3rd '0'. I
want to see NA directly for the 3rd. Any possibility how to do that
through the rowSum() function?
Thanks and regards,
On Sat, Feb 16, 2013 at 11:52 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Feb 16, 2013
by rows,
or how to operate assuming you have the column names. I'd like to pull
by type.
Thanks!
Barry
Something like the following should work. If your data frame is DF:
NewDF - DF[, sapply(DF, is.numeric)]
Regards,
Marc Schwartz
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) :
object 'localData' not found
test - function() {
localData - split(iris, iris$Species)
WriteXLS(localData, LocalData.xls)
}
test() # Works fine
Hope that clarifies.
Regards,
Marc Schwartz
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https
/technetwork/topics/bigdata/r-offerings-1566363.html
Regards,
Marc Schwartz
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
from there, or consider using a different R package that has more
flexibility in defining the specific Excel worksheet cell ranges that you want
to extract.
Others may have different ideas for you.
Regards,
Marc Schwartz
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, angle = 90, length = 0.25)
where the 'length' argument to arrows() defines the width of the upper and
lower boundary lines.
There are a fair number of other functions around that can add CI's to plots as
well and a search of the archives should bear fruit.
Regards,
Marc Schwartz
On Jan
On Jan 11, 2013, at 10:35 PM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
Tried to do a plot just now and got an error:
Error in text.default(2, 6, main, cex = cex) :
X11 font -adobe-helvetica-%s-%s-*-*-%d-*-*-*-*-*-*-*, face 1 at size 16
could not be loaded
This is reproducible (in
.
Regards,
Marc Schwartz
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
See ?regex for more information and if appropriate, consider gregexpr():
gregexpr(\\$, x$Expensive$MoreText)
[[1]]
[1] 2 12
attr(,match.length)
[1] 1 1
attr(,useBytes)
[1] TRUE
Regards,
Marc Schwartz
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https
are beyond the scope
of this discussion, so I won't get into details here.
I hope that the above is helpful.
Regards,
Marc Schwartz
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PLEASE do read the posting guide http
is not represented exactly, the rounding rule applies to the
represented number and not to the printed number, and so round(0.15, 1) could
be either 0.1 or 0.2).
...
Regards,
Marc Schwartz
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(t(apply(cbind(v1, v2), 1, sort)))
[,1] [,2]
[1,]05
[2,]13
[3,]22
[4,]04
Basically, sort each row so that you don't have to worry about the permutations
of values, then get the unique rows as a result.
Regards,
Marc Schwartz
!
That is great, thank you very much!
Emmanuel
On 27 December 2012 22:39, Marc Schwartz marc_schwa...@me.com wrote:
unique(t(apply(cbind(v1, v2), 1, sort)))
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PLEASE do
of
where else to search, please?
Thanks!
David Osborne
MSc student
Department of Archaeology, University of Nottingham
Might be Shiny:
http://www.rstudio.com/shiny/
Regards,
Marc Schwartz
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the results that
you want to output. So that could perhaps be either a matrix or a data frame,
which ever is more suitable for your case.
Regards,
Marc Schwartz
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PLEASE do read
of a typical Fedora install these days.
If you get to the point where you have R package development questions that are
not really Fedora specific, those should be posted to the R-Devel list:
https://stat.ethz.ch/mailman/listinfo/r-devel
Regards,
Marc Schwartz
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