mes = structure(list(
User = c("A", "B", "C", "D", "E")), .Names = "User"), call =
quote(by.default(data = Date,
INDICES = User, FUN = function(yy) diff(yy))), class = "by")
I can access it as: foo2$A for example.
I h
Apologies if the question is a but naïve, I am a novice in time series data
handling in R
I have the following type of data, in a long format ( as called by the
spacetime vignette the table contains also space, not noted here):
User | Date | Otherdata |
A | 01/01/2014 | aa
A | 01/01/2014 | b
35 PM, Steve Lianoglou wrote:
Hi,
On Thu, Nov 18, 2010 at 10:25 AM, Martin Tomko wrote:
Hi Gerrit,
indeed, that works. Excellent tip!
For reference, I did this:
subset1<-subset(summarystats,(Type==1)&(Class==1)&(Category==1))
I am still not totally sure when one uses "&am
ds for logical AND
Thanks a lot.
Martin
On 11/18/2010 3:58 PM, Gerrit Eichner wrote:
Hello, Martin,
as to your first problem, look at function subset(), and particularly
at its argument "subset".
HTH,
Gerrit
On Thu, 18 Nov 2010, Martin Tomko wrote:
Dear all,
I ha
Dear all,
I have searched the forums for an answer - and there is plenty of
questions along the same line - but none of the paproaches shown worked
to my problem:
I have a data frame that I get from a csv:
summarystats<-as.data.frame(read.csv(file=f_summary));
where I have the columns Datase
although
they evaluate in general inter/intra-cluster distance distributions.
For instance, you can maximise/minimise these indices to find the best
partition among a set of candidate ones.
Mattia Prosperi.
2010/11/17 Marc Schwartz:
On Nov 17, 2010, at 7:33 AM, Martin Tomko wrote:
D
ill probably have to implement this
yourself.
-Matt
On Wed, 2010-11-17 at 08:33 -0500, Martin Tomko wrote:
Dear all,
I am having a hard time to figure out a suitable test for the match
between two nominal classifications of the same set of data.
I have used hierarchical clustering with multiple me
Dear all,
I am having a hard time to figure out a suitable test for the match
between two nominal classifications of the same set of data.
I have used hierarchical clustering with multiple methods (ward,
k-means,...) to classify my dat into a set number of classesa, and I
would like to compare
Dear all,
I am converting a large process to a parallel backhend using doMC and
foreach. Basically, I havea long list of input graph files and each of
them calls soem basic igraph package functions. I am parallelizing the
run, in order to save time. All works fine, and each %dopar% call ends
w
Hi Steve,
thanks a lot, I will haev a look at the kernel appraoch ,that looks
promising. I will first have to study the theory behind before I use it,
I guess.
Cheers
M.
On 10/21/2010 5:42 PM, Steve Lianoglou wrote:
Hi,
On Thu, Oct 21, 2010 at 9:42 AM, Martin Tomko wrote:
Dear all,
I
significance in terms of column
properties, they are basically graphs of sort.
Is there a way out with the SVM, or I just forget that?
Martin
On 10/21/2010 5:42 PM, Steve Lianoglou wrote:
Hi,
On Thu, Oct 21, 2010 at 9:42 AM, Martin Tomko wrote:
Dear all,
I am exploring the possibilities
Dear all,
I am exploring the possibilities for automated classification of my
data. I have successfully used KNN, but was thinking about looking at
SVM (which I did nto use before).
I have a pairwise distance matrix of training observations which are
classified in set classes, and a distance mat
thank you guys, R CMD BATCH seems the way to go, and I will nudge my
admin to install screen /byobu
Thanks heaps,
Martin
On 10/14/2010 7:21 PM, Uwe Ligges wrote:
On 14.10.2010 18:07, Martin Tomko wrote:
Dear all,
I am sure this has been solved before, googling did not help much,.
Warning
Dear all,
I am sure this has been solved before, googling did not help much,.
Warning, I am not great with putty/linux servers
Situation: I have been given access to an R installation on a Linux
server to do some larger number crunching that was killing my machine. I
use putty to connect, and
Thank you Marc, that was an elegant solution, works perfectly!
Martin
On 9/21/2010 10:24 PM, Marc Schwartz wrote:
DF[, -c(1:2)]<- DF[, -c(1:2)] * DF$Group
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do re
I am sure there is a simple solution to this... I have a column in a
data frame specifying a grouping (1, -1) for my observations, and need
to mutliply each observation in all the other columns of the data frame
by the corresponding value in the given column. I played with apply, and
saw some s
Hi ,
thanks, the lower.tri idea is I guess the best way. Will try that.
Cheers
Martin
On 8/25/2010 2:21 PM, Sarah Goslee wrote:
Hi,
On Wed, Aug 25, 2010 at 8:11 AM, Martin Tomko wrote:
Hi Sarah,
thank you very much for your answer. I have been spitting things out on
screen, but
something more elegant, but these solutions have all worked
well for me in various situations.
Sarah
On Wed, Aug 25, 2010 at 3:46 AM, Martin Tomko wrote:
Dear all,
I am using an R 2.10 installation on a Windows 203 server that I have no
control over. After a multi-day run I found that it
Dear all,
I am using an R 2.10 installation on a Windows 203 server that I have no
control over. After a multi-day run I found that it was
terminated/crashed. Is there any log kept by R where I could see whether
something/what happened? The same process has been run beofre on a
smaller dataset
I did. Did not work. Did you try your code? The matrix did not result into
integer numbers as expected. MY approach resulted in a correct scan
result, at least.
M.
> Martin Tomko wrote:
>> Hi Peter,
>> apologies, too fast copying and pasting.
>> So, here is the explan
to
naive questions, I am a newbie, in principle.
Cheers
Martin
On 8/12/2010 4:29 PM, peter dalgaard wrote:
On Aug 12, 2010, at 1:34 PM, Martin Tomko wrote:
Hi Peter,
thank you for your reply. I still cannot get it to work.
I have modified your code as follows:
rows<-length(R)
cols<
d<- read.table(file, colClasses = classes, nrows=Nb[ii], skip=skip[ii], comment.char
= "")
if(save.inter){
save(d, file=paste(out, ".", ii, ".rda", sep=""))
}
print(ii)
results[seq(1+skip[ii], skip[ii]+Nb[ii]), ]<- as.matrix(d
ger,15 Integer,15 Integer,15 Integer,15 Integer,15 Integer,15
Any idea where the values are gone?
Thanks
Martin
Hence, I filled it into the matrix of dimensions
On 8/12/2010 12:24 PM, peter dalgaard wrote:
On Aug 12, 2010, at 11:30 AM, Martin Tomko wrote:
c<-scan(file=f,what=li
Dear all,
I have a few points that I am unsure about using scan. I know that it is
covered in the intro to R, and also has been discussed here:
http://www.mail-archive.com/r-help@r-project.org/msg04869.html
but nevertheless, I cannot get it to work.
I have a potentially very large matrix that
.fields(file)) # max
# now setup read.table for max number
input <- read.table(file, colClasses=rep(NA, maxFields), fill=TRUE,
col.names=paste("V", seq(maxFields), sep=''))
On Sun, May 31, 2009 at 6:06 AM, Martin Tomko
wrote:
Dear Jim,
with the help of Ted, we d
in the dataframe. All of this can
be done in R if you can state what the criteria is.
On Sat, May 30, 2009 at 4:32 AM, Martin Tomko <mailto:martin.to...@geo.uzh.ch>> wrote:
Jim,
the two lines I put in are the actual problematic input lines.
In these examples, there are no quo
holtman wrote:
You need to supply the actual input line so we can see what is
happening. Are you sure you do not have unbalanced quotes in your
input (try quote='') or do you have comment characters ("#") in your
input?
On Fri, May 29, 2009 at 3:15 PM, Martin Tomko <mailto:
Dear All,
I am observing a strange behavior and searching the archives and help
pages didn't help much.
I have a csv with a variable number of fields in each line.
I use
dataPoints <- read.csv(inputFile, head=FALSE, sep=";",fill =TRUE);
to read it in, and it works. But - some lines are long an
Yes, will do. I just was not in need to upgrade as everything worked...
An R is not my primary development environment - i.e., I need it a
couple of times a year.
But you are right, it is good to be on an updated version.
Cheers
Martin
Duncan Murdoch wrote:
On 3/24/2009 8:55 AM, Martin Tomko
package is visible to
other under install packages in any repository?
Thanks
Martin
Duncan Murdoch wrote:
On 3/24/2009 7:05 AM, Martin Tomko wrote:
I have troubles make TinnR 2.2.0.2 work, it seems that the dependency
on the package TinnR that cannot be found (I tried also manual
downloads, but
-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Martin Tomko
Sent: Tuesday, March 24, 2009 8:25 AM
To: David Winsemius
Cc: r-help@r-project.org
Subject: Re: [R] install.package("TinnR") - there is no package called 'TinnR'
David,
th
semius wrote:
Tinn-R is not an R package. It is a standalone text editor:
http://www.lmgtfy.com/?q=tinn-r
-- David Winsemius
On Mar 24, 2009, at 7:05 AM, Martin Tomko wrote:
I have troubles make TinnR 2.2.0.2 work, it seems that the dependency
on the package TinnR that cannot be found (I tr
I have troubles make TinnR 2.2.0.2 work, it seems that the dependency on
the package TinnR that cannot be found (I tried also manual downloads,
but I cannot find the package anywhere on any CRAN mirror).
I even set a default cran mirror in the Rprofile.site file, so that the
later command can
Dear All,
I have interval data (for Mon-Sun, 00-24h) of an activity and would like
to visually plot them in a matrix-like plot, where color A would be
assigned to the activity, and color X to unspecified time usage. Note
that the activities are not in standardised units (hours or so), but
from
any wiser.
What if I had a vector v <- vector(c(1,10,100,1000,1)) and wanted to
perform it on that?
Thanks a lot
Martin
Chuck Cleland wrote:
> Martin Tomko wrote:
>> Dear list,
>> I have a vector (array, table row, whatever is best) of frequency values
>> for categori
Dear list,
I have a vector (array, table row, whatever is best) of frequency values
for categories (or bins), and I need to find the median category.
Trivial to do by hand, but I was wondering if there is a means to do it
in R in an elegant way.
The obvious medioan(vector) returns the median f
Hello Haris,
no, that is not the problem. But thank you anyway. I figured that paste
has a funny behavior.
But the object resulting from pam is complex, and cannot be cast into a
table frame easily...
Charilaos Skiadas wrote:
> On Nov 27, 2007, at 7:41 AM, Martin Tomko wrote:
>
>&
Hello list,
the following approach did not work:
clustersA <- pam(distances, nkA, diss=TRUE);
gc();
filenameclu = paste("filenameclu", ".txt");
write.table(clustersA , file=filenameclu,sep=",");
although it worked with
clustersA <- hclust(distances, method="ward");
and a consecutive
kclassA <- c
Hi all,
I have a set of patterns which can occur in a series of (3) matrices. I
want to identify those and create a fourth one with the identifiers of
the cases.
Something like:
for (i in 1:l) {
for (j in 1:w) {
A[A[i,j]==1 & D[i,j]==1 & P[i,j]=
Hi all,
I have a set of patterns which can occur in a series of (3) matrices. I
want to identify those and create a fourth one with the identifiers of
the cases.
Something like:
for (i in 1:l) {
for (j in 1:w) {
A[A[i,j]==1 & D[i,j]==1 & P[i,j]=
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