Hello,I have the following food data with some NA values in the food prices. I
will like to replace the NA values in the food price column for each food item
by the mean price of the specific food item for each city. For example, the
price of bean for the household with hhid 102 in the data set
Hello,I have a column of my data of the Following format
10. Arnold125. Jessica1. Romeo117. Juliet
I need to eliminate the numbers, period, and the space before the names so that
I have the following:
ArnoldJessicaRomeoJuliet
I tried using the gsub function but my code came up with errors.
Any he
,NA,"cherry",NA,NA,NA),
col3=c(NA,NA,NA,NA,"pepper","mango",NA))
veg_df$col4<-apply(as.matrix(veg_df),1,function(x) x[!is.na(x)])
Jim
On Tue, Nov 22, 2016 at 8:26 AM, Olu Ola via R-help
wrote:
> Hello,I have the following data
> | colA | colB | colC | colD
Hello,I have the following data
| colA | colB | colC | colD |
| NA | pumpkin | NA | Pumpkin |
| Cassava | NA | NA | Cassava |
| yam | NA | NA | yam |
| NA | Cherry | NA | Cherry |
| NA | NA | Pepper | Pepper |
| NA | NA | Mango | Mango |
| maize | NA | NA | maize |
All I want to do is to combine
Hello,I have a data set called plabor and have the following format:
| ColA | ColB | Colc |
| 6 | 25 | 3 |
| NA | NA | NA |
| 3 | 2 | 19 |
| 4 | 7 | NA |
I wanted to find the product of the three columns for each of the rows and I
used the apply function follows:
plabor$colD = apply(plabor[c("
excuse my brevity.
On November 11, 2016 3:39:53 PM PST, Olu Ola via R-help
wrote:
>Here is the warning message that appears when I tried installing the
>apply package:
>install.packages("apply")Installing package into
>‘C:/Users/Olufemi/Documents/R/win-library/3.2’(as
sion 3.2.2)
Regards
On Friday, November 11, 2016 6:37 PM, Ista Zahn wrote:
What makes you think " apply' does not work in R 3.2.2"?
On Nov 11, 2016 6:24 PM, "Olu Ola via R-help" wrote:
Hello,I quite understand that apply is doing what it is supposed to do. I
actually
27
Livermore, CA 94550
925-423-1062
On 11/11/16, 12:45 PM, "R-help on behalf of Olu Ola via R-help"
wrote:
> Hello,I have a dataset that is similar to the one as follows:
>
>> Df.1 <- data.frame(A = c(5,4,7,6,8,4),B =
>>(c(1,5,2,4,9,1)),C=(c(2,3,NA,5,NA,9)))
>
Hello,I have a dataset that is similar to the one as follows:
> Df.1 <- data.frame(A = c(5,4,7,6,8,4),B =
> (c(1,5,2,4,9,1)),C=(c(2,3,NA,5,NA,9)))
> Df.1
A B C
1 5 1 2
2 4 5 3
3 7 2 NA
4 6 4 5
5 8 9 NA
6 4 1 9
> Df.1$D = apply(Df.1, 1, prod, na.rm=T)
> Df.1$D[1] 10 60 14 120 72 36
>
Hello,I am trying to create a dummy variable using the ifelse statement.
However, the ifelse statement does not recognize na.rm = True.
How can I create a dummy variable so that it still retains the missing data
denoted as "NA" ?
Regards
[[alternative HTML version deleted]]
Are you saving results at every iteration?
In a list, data frame, etc? People likely need that to help
answer your question.
Also probably have a look the control list
argument and the save.failures option, that might be
something you're interested in.
- Will
On Tue, Sep 15, 2015 at
1
Hello,
I am doing some estimation using optimx and after each round of estimation, I
store the coefficient. However, I need to drop the set of coefficients for
which the convergence code in optimx is GREATER than Zero. How do I go about
this?
A way forward will be highly appreciated.
Thank you
Hello,
I have a dataset that have a couple of missing values and I DO NOT want to
delete the observations with the missing values. I have read about na.action in
dealing with missing values but I do not know how it applies to user-specific
written code.
Is there a code you can use with your dat
Rolf Turner wrote:
Subject: Re: [FORGED] [R] Handling "NA" in summation
Date: Sunday, September 6, 2015, 7:16 PM
On 07/09/15 10:22, Olu
Ola via R-help wrote:
> Hello, I am
currently working with a dataframe which has some missing
> values represented by "NA".
whene
Hello,
I am currently working with a dataframe which has some missing values
represented by "NA". whenever, I add two columns in which at least one of the
pair of an observation is "NA", the sum returns zero. That is for the same
observation, if
dataframe$A = 20
dataframe$B = NA
dataframe$A +
Hello,
I am trying to estimate a non-linear GMM in R using Optimx. However, when I do
the start test to compare my analytical gradient with the numerical gradient, I
get the following error message
Error: Gradient function might be wrong - check it!
Below are the print out of my analytical and
Hello,I am running a nonlinear GMM using the optimx wrapper. I am trying to
estimate 37 variables however and my code for the optimx is:
nlgmm = optimx(par=b0, fn=obj,method = "BFGS", itnmax=1,
control=list(follow.on = TRUE,kkt=FALSE,starttests=TRUE,save.failures=TRUE,
trace=0))
My staring
Hello,
I have been running a nonlinear GMM using the nloptr wrapper since the last 7
days. The maximum time I have to run the code on the server that I am using to
run this code is 7 days which expires in about an hour when the server
automatically terminates it. I will like to know if there is
Hello,
I am running a 2 equation system of nonlinear GMM using BFGS in optimx. Using
the conventional way of calculating the standard error of the estimates gives
NAN's for some of the standard errors. As a result, I want to bootstrap the
standard error.
A way forward on how to bootsrap the st
Hello,
I am running a BFGS using optimx and would like to obtain the Hessian for the
last iteration.
How can I go about this?
Thank you
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Hello,
I am estimating a nonlinear GMM and I got the following error message. I have
searched online in other to understand what is going on but could not find help
> ngmm = optimx(par=b0, fn=object,gr=gred, method = c("BFGS","nlminb","nlm"),
> itnmax=1, control=list(follow.on = TRUE,startte
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