i in n){
list_of_vecs[[i]]<-rnorm(10,0,1)
}
If you really want to use "assign":
for (i in n){
vecname<-paste('vec_', i, sep = '')
assign(vecname, rnorm(10,0,1))
list_of_vecs[[i]]<-get(vecname)
}
Jim
On Tue, Dec 6, 2016 at 8:44 PM,
Hi,
As an exercise, I am trying to create a list of 10 random number vectors in a
loop. I can create the vectors but am unsure how to assemble them in the list
as part of the loop. Any advice?
# Number of vectors to create
n <- c(1:10)
# Create empty list to store vectors
list_of_vecs <- list
Thank you very much Peter - very enlightening to do it from first principles!
Regards,
Paul
On 4 October 2016 at 10:23:52 am, peter dalgaard (pda...@gmail.com) wrote:
> On 04 Oct 2016, at 00:30 , Paul Sanfilippo wrote:
>
> Hi,
>
> I am trying to replicate a tes
the coefficients are
sufficiently dissimilar.
Regards,
Paul Sanfilippo
On 4 October 2016 at 10:08:12 am, Bert Gunter (bgunter.4...@gmail.com) wrote:
See inline.
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things in
Hi,
I am trying to replicate a test in the Hosmer - Applied Logistic regression
text (pp 289, 3rd ed) that uses a Multivariable Wald test to test the equality
of coefficients across the 2 logits of a 3 category response multinomial model.
I’d like to see whether (from a statistical standpoint)
I am trying to create a grouped barplot that uses marginal (row) proportions
rather than cell proportions and can't figure out how to change:
y = (..count..)/sum(..count..)
in ggplot to do this.
Using the mtcars dataset as an example and considering two categorical
variables (cyl and am - purel
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