hello
I have covariance stacionary proces, and i want to estimate some parameter
of this proces via gmm.
My problem is with write g -function.
0 order autocovariance is not problem
1 and higher order autocavariance are problem, because add order from 0 mean
that I loose one observacion
if I
I have dataframe with 17factors variables (for example every factor have
3levels)
I have maybe 5000 observation.
And i need to do table where is in every raw 1 of possible combination of
this factors and the numbur how many time is this combination in my dataset.
I wrote one code, but this is
Hi, my data looks this:
id forma program kod obor
rocnik
1 10001 kombinovaná Matematika M1101 matematika 1
2 10002 prezenční Informatika N1801 teoretická informatika 1
3 10002 prezenční Informatika
Thank you Jim, it works very well. I do not need do it using tapply, but i
think that it is the way.
And Patrick thank you too
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Petr
David Winsemius wrote:
On Nov 25, 2009, at 9:15 AM, Peterko wrote:
Is there function what aproximate vector of parameters some function
to
minimum ?
tet={tet1,tet2} i have they starting value
and i want to find the tet what minimalizing some function
Is there function what aproximate vector of parameters some function to
minimum ?
tet={tet1,tet2} i have they starting value
and i want to find the tet what minimalizing some function of tet ?
thanks
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vector
(x_1,x_2...,x_n)`
David Winsemius wrote:
On Nov 25, 2009, at 9:15 AM, Peterko wrote:
Is there function what aproximate vector of parameters some function
to
minimum ?
tet={tet1,tet2} i have they starting value
and i want to find the tet what minimalizing some function
Is there in some pacakage this test? i mean that input will be only the value
of periodogram, and the function will say that are significant.
or is there only the way to calcule Fishers statistics W =Vi/V1 + · · · +
Vm, for i =1 m and test it step by step ?
thanks
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hi i am creating some variables from same data, but somewhere is different
rouding.
look:
P = abs(fft(d.zlato)/480)^2
hladane= sort(P,decreasing=T)[1:10]/480
pozicia=c(0,0,0,0,0)
for (j in 1:5){ for (i in 2:239){
if (P[i]/480==hladane[2*j-1]){pozicia[j]=i-1}}}
period=479/pozicia
all.equal is what i need, many thanks to help me
baptiste auguie-2 wrote:
Hi,
you probably want to use ?all.equal instead of ==
I couldn't run your example, though
Hope this helps,
baptiste
On 27 Feb 2009, at 10:32, Peterko wrote:
hi i am creating some variables from same
Hi, may be simle question, but a do not find it anywhere.
Is there same function like max() ,but giving more results.
max() give 1number-maximum
I need funcion what give p bigest number.
many thanks
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*pi*f1*t)
s1-sin(2*pi*f1*t)
.
.
.
s5-sin(2*pi*f5*t)
and now a can do lm(y~mean+c1+s1+c2+s2+...+s5)
.
Dieter Menne wrote:
Peterko lanikpeter at gmail.com writes:
Hello, i need to find in time serie, k=1,2,3...(how if possible) most
domain
frequencies and than smooth original serie
Dieter Menne wrote:
Peterko lanikpeter at gmail.com writes:
Original serie have 225 observing, but program use only 224.
the most domain frequencies are f1=1/224 f2=1/122 f3=1/74,66 f4=1/56
f5=1/24,88
When i know these frequencies a can do, new variable ,nubmers of variavle
is
2
Hello, i need to find in time serie, k=1,2,3...(how if possible) most domain
frequencies and than smooth original serie by Fourier row y=mean +
a1*Cos(2*pi/freq*t)+b1*Sin(2*pi/freq*t)+a2..
numbers a1,b1 ... i will have from simple regresion, i need only to find k
msot domain frequensies a
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