ctor:
>>>
>>> se<-apply(dd,1,sd)
>>>
>>> How can I calculate the covariance matrix using apply? Thanks.
>>>
>>> __
>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>
273267965 0.0151896601 >
On 10/4/2024 4:57 PM, Uwe Ligges wrote:
Homework questions are not answered on this list.
Best,
Uwe Ligges
On 04.10.2024 10:32, Steven Yen wrote:
The following line calculates standard deviations of a column
vector:
se<-apply(dd,1,sd)
How can I calculat
iance matrix for them.
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Ivan
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one
number.
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-
> *Roslinazairimah Zakaria*
> *Tel: +609-5492370; Fax. No.+609-5492766*
>
> *Email: roslinazairi...@ump.edu.my ;
> roslina...@gmail.com *
> Faculty of Industrial Sciences & Technology
> University Malaysia Pahang
> Lebuhraya Tun Razak, 26300 Gambang, Pahang, Malaysia
>
into submission, sort of).
My overlooking unsplit() is somewhat impressive in view of "svn diff -c
18591"
-pd
> On 27 Sep 2024, at 17:08 , Martin Maechler wrote:
>
>>>>>> Chris Evans via R-help
>>>>>>on Fri, 27 Sep 2024 12:20:47 +0200 w
df$d2m)
>
> # Convert valid_time from numeric to POSIXct assuming it's in seconds since
> the epoch
> df$valid_time <- as.POSIXct(df$valid_time, origin = "1970-01-01")
>
> # Extract year, month, day, and hour from valid_time
> df$Year <- year(df$valid_time)
> df$Month
no longer available.
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Ivan
[1] https://eddelbuettel.github.io/r2u/
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install.packages("some_new_package")?
>
>I've done both over the years (perhaps a mistake that I will some day
>regret.)
>
>Pros and cons of these two methods?
>
>Thanks.
>
>--Chris Ryan
>
--
Sent from my phone. Please excuse my brevity.
___
both over the years (perhaps a mistake that I will some day
regret.)
Pros and cons of these two methods?
Thanks.
--Chris Ryan
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uador & Honorary Professor,
University of Roehampton, London, UK.
CORE site: http://www.coresystemtrust.org.uk
Other work web site: https://www.psyctc.org/psyctc/
Personal site: https://www.psyctc.org/pelerinage2016/
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of v,
>> > >>> corresponding to level l of f are the entries of x[[l]]. I.e. I want
>> > >>> v to equal
>> > >>>
>> > >>> c(7, 2, 6, 13, 5, 9, 1, 14, 15, 4, 8, 12, 10, 11, 3)
>> > >>>
>> > >>> I can create v
searched to read
> > this type of file in R, I found the Raster Package.
> > In python it is possible to do this using cdsapi and xarray library, but I
> > am not familiar with python.
> > Sincerely
> >
> > On Thu, Sep 26, 2024 at 2:33 AM Roy Mendelssohn - NOAA
hon it is possible to do this using cdsapi and xarray library, but I am
> not familiar with python.
> Sincerely
>
> On Thu, Sep 26, 2024 at 2:33 AM Roy Mendelssohn - NOAA Federal via R-help
> mailto:r-help@r-project.org>> wrote:
>> At least for me the dataset file did no
... or a timezone string.
... or do what I usually do and use POSIXct for dates as well as times,
self-managing use of midnight local time for "dates".
On September 25, 2024 5:40:37 AM EDT, Ivan Krylov via R-help
wrote:
>24 сентября 2024 г. 17:10:13 GMT+03:00, Luca Brinkma
on deleted]]
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and provide commented, minimal, self-contained, reproducible code.
move rows with NA values
>>> df <- na.omit(df)
>>>
>>> # Convert temperatures from Kelvin to Celsius
>>> df$t2m <- df$t2m - 273.15
>>> df$d2m <- df$d2m - 273.15
>>>
>>> # Calculate relative humidity
>>> calculate_relative
t work because 'termstrc' requires 'rgl' to load and your
'rgl' installation doesn't work.
Try following the instructions in the README of the 'rgl' package
regarding the OpenGL support. Perhaps it needs to be reinstalled after
some updates you
24 сентября 2024 г. 17:10:13 GMT+03:00, Luca Brinkmann via R-help
пишет:
> My current
> understanding is, that a Date object does only save the days from the
> origin and no more information about timezones or other information
> (please correct me if I am wrong).
You are correct.
TE=German_Germany.utf8 LC_CTYPE=German_Germany.utf8
LC_MONETARY=German_Germany.utf8
[4] LC_NUMERIC=C LC_TIME=German_Germany.utf8
time zone: Europe/Berlin
tzcode source: internal
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Try wrapping the lm() expression in an extra list():
carsreg <- carsdt[, .(fit = list(lm(mpg ~ disp + hp + wt))), by = .(cyl)]
# [1] 3
carsreg
# cyl fit
#
# 1: 6
# 2: 4
# 3: 8
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Best regards,
Ivan
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# ...and finally attach to the original data.frame
cbind(c10Dt)
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Ivan
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happening in the console, the same if you send a loong loop and want to
abort...)
cheers
F.
On 9/11/24 15:44, stephen sefick wrote:
Stephen Sefick
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ot; "56" "59" "114" ...
..$ : chr "Year"
- attr(*, "assign")= int 1
Browse[1]> t(random[['Year']]) |> str()
num [1:19, 1:10] 0.175 0.181 0.102 0.119 0.158 ...
...and they are indeed non-conformable. Why is random$Year a matrix?
-
p in
your case.
--
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Ivan
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and provide commented,
7;t one to assume that it is big-endian data. But
in this case there is a BOM so your machine has a buggy decoder?
On September 7, 2024 2:43:24 PM PDT, Duncan Murdoch
wrote:
>On 2024-09-07 4:52 p.m., Jeff Newmiller via R-help wrote:
>> When you specify LE in the encoding type, you are lo
to contain embedded nulls
>>
>> Is there any way to read this data directly onto R?
>>
>> Thanks for your time
>>
>
>The looks like a byte-order mark
>(https://en.wikipedia.org/wiki/Byte_order_mark).
>Try this:
>
>fn <-
> file('https:
= header, sep = sep, quote = quote, :
>
> line 4 appears to contain embedded nulls
>
>5: In read.table(file = file, header = header, sep = sep, quote = quote, :
>
> line 5 appears to contain embedded nulls
>
>Is there any way to read this data directly onto R?
>
>Thank
work the
answers for atan(1i) & atan(-1i) make sense.
Regards,
Jorgen Harmse.
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PLEASE do read th
ive any typos please... I'm on a mobile device.
Kind regards,
Gregg Powell
Sent from Proton Mail Android
Original Message ----
On 06/09/2024 01:37, Koenker, Roger W wrote:
> Apologies, forgot to copy R-help on this response.
>
> Begin forwarded message:
>
&
used. Appreciate any suggestions. Thanks.
--Chris Ryan
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vision/multiplication on a
>> complex number. Which R actually does for these very particular cases; but
>> not when only Im(x) is Inf.
>>
>> Sincerely,
>>
>> Leonard
>>
>> --
>> *From:* Bert Gunter
>> *Sent:* Friday,
number.
Which R actually does for these very particular cases; but not when only Im(x)
is Inf.
Sincerely,
Leonard
From: Bert Gunter
Sent: Friday, September 6, 2024 1:12 AM
To: Duncan Murdoch
Cc: Leo Mada ; r-help@r-project.org
Subject: Re: [R] BUG: atan(1i) / 5
leted]]
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and provide commented, minimal, self-contained, reproducible code.
gt;For example in the code below, I want to test my sample to N(0, 10).
>
>shapiro.test(rnorm(100, mean = 5, sd = 3))
>
>Is there any way to pass the information of the benchmark normal distribution?
>
>__
>R-help@r-project.org mail
in the confidence interval of the new value. Is there any
> method available to obtain that?
>
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> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read th
'C', 'D'))
Since the factor is ordered and can be subject to comparison like
status[1] < status[2], you can now use max() on your groups. If the
sample contains any 'D's, max() will return a 'D', because it's larger
than any 'C's. If th
like strip.left() but for just one of the factors.
I can't remember or find how I did it, what options to set. Can anyone
remind me?
Thanks.
--Chris Ryan
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, 4L, 2L, 2L, NA,
>> NA, NA, 5L, 9L, NA, NA, 10L, 7L, 2L, NA, 7L, NA, NA, NA, NA,
>> 2L, 4L, 6L, 10L, NA, NA, NA), X2 = c(8L, 5L, 1L, 6L, 7L, 2L,
>> 4L, 7L, 7L, 3L, 2L, 4L, 6L, 5L, 5L, 6L, 3L, 2L, 1L, 7L, 2L, 8L,
>> 4L, 5L, 6L, 1L, 4L, 8L, 3L, 3L, 8L, 1L)), class = "
.. .. ..@ projargs: chr "+proj=somerc +lat_0=46.952405556
+lon_0=7.439583 +k_0=1 +x_0=260 +y_0=120 +ellps=bessel +units=m
+no_defs"
.. .. ..$ comment: chr "PROJCRS[\"unknown\",\nBASEGEOGCRS[\"unknown\",\n
DATUM[\"Unknown based
ome>*
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В Mon, 26 Aug 2024 14:33:02 +0200
SIBYLLE STÖCKLI via R-help пишет:
> > # Extract raster values within the shapefile
> > extracted_values <- extract(raster_file, shape_file)
> > # Assuming the shapefile has multiple polygons and you want to
> > # create a box
[[1]]
> names(raster_file)
[1] "Andrena.barbilabris_glo_ensemble"
>
> # Extract raster values within the shapefile
> extracted_values <- extract(raster_file, shape_file)
>
>
>
> # Assuming the shapefile has multiple polygons and you want to create a
boxplot
В Sun, 25 Aug 2024 20:32:07 +
Søren Højsgaard via R-help пишет:
> checking for unstated dependencies in examples ... ERROR
> Warning: parse error in file 'lines':
> 77:20)
Looks like one of your Rd \examples{} has a syntax error in it. If
there is a file gRain.Rcheck
> On 08/25/2024 1:32 PM PDT Søren Højsgaard via R-help
> wrote:
>
>
> Dear all,
> When checking a package (ubuntu) I get
>
> checking for unstated dependencies in examples ... ERROR
> Warning: parse error in file 'lines':
> 77:20)
>
> Can
memoise_2.0.1 broom_1.0.6
[76] httpuv_1.6.15 xfun_0.47 fs_1.6.4
[79] pkgconfig_2.0.3
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PLEASE do rea
rs_pres[[1]]
> names(r)
[1] "Andrena.barbilabris_glo_ensemble"
>
>
> rs <- stack(r, s)
> names(rs) <- c('r', 's')
Error in `names<-`(`*tmp*`, value = c("r", "s")) :
incorrect number of layer names
> names(rs)
[1] "Andrena.barbilabris
ed. However I
>just wanted to get some insight on above problem related to Statistics
>from some of the great Statisticians in this forum.
>
>Thanks for your time.
>
>__
>R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
s' is a list of rasters, 'r' could
also contain more than one layer, resulting in stack(r, s) containing
more than two layers.
In order to avoid the error, you need to see names(rs) and either give
the same number of names to the object instead of two, or additionally
extract one
quot;DEBioBedeu" "FRBioBedeu" "ITBioBedeu"
[15] "geometry"
> s<-sf$Unterregio
> r<-allrasters_pres[[1]]
Kind regards
Sibylle
-Original Message-
From: Ivan Krylov
Sent: Friday, August 23, 2024 5:30 PM
To: sibylle.stoec...@gmx.ch
Cc: 'SIB
) :
> incorrect number of layer names
It looks like at least one of the rasters 'r' and 's' has multiple
layers. What does names(rs) return? I would offer more detailed advice,
but I don't know 'raster' that well.
The "R Inferno" book [1] offer
ITBioBedeu"
[15] "geometry"
> s<-sf$Unterregio
> r<-allrasters_pres[[1]]
>
>
> rs <- stack(r, s)
> names(rs) <- c('r', 's')
Error in `names<-`(`*tmp*`, value = c("r", "s")) :
incorrect number of layer names
t from which you can extract the values you are
interested in (see ?summary.lm). When in doubt, call
help(name_of_the_function).
--
Best regards,
Ivan
[1]
https://cran.r-project.org/doc/manuals/R-intro.html
[2]
http://web.archive.org/web/20230106210646/http://ashipunov.info/shipunov/sch
n one of its dependencies, which I didn't look
at.
--
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Ivan
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В Thu, 22 Aug 2024 08:46:03 +0200
SIBYLLE STÖCKLI via R-help пишет:
> rr2s <- stack(r, r2,s)
> > names(rs) <- c('r', 's', 'r2')
>
> Error in `names<-`(`*tmp*`, value = c("r", "s", "r2")) :
>
> incor
27;) set:
# time zone information successfully lost and replaced by UTC
Sys.time() |> format() |> as.POSIXct(tz = 'UTC')
--
Best regards,
Ivan
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rr2s <- stack(r, r2,s)
names(rs) <- c('r', 's', 'r2')
d <- as.data.frame(rr2s)
boxplot(r~s, data= d)
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r2_resampled <- resample(r2, r1)
compareRaster(r1, r2_resampled)
CompareRaster:
Evaluate whether a two or more Raster* objects have the same extent, number of
rows and columns, projection, resolution, and origin (or a subset of these
comparisons).
Kind regards
Sibylle
-Original Message
Message-
From: Ivan Krylov
Sent: Friday, August 16, 2024 11:45 AM
To: sibylle.stoec...@gmx.ch
Cc: 'SIBYLLE STÖCKLI via R-help'
Subject: Re: [R] allequal diff
В Fri, 16 Aug 2024 11:32:58 +0200
пишет:
> # values and mask r1
> r1 <- getValues(r1)
> mask1 <- is.na(r
Many thanks for your help.
I will consider the processx package.
Best regards
Nicolas
Le 17 août 2024 à 16:07, Ivan Krylov a écrit :
В Sat, 17 Aug 2024 11: 47: 30 + SIMON Nicolas via R-help пишет: > nmrun <- paste0("cmd. exe /k ",nm_log,". bat ",nmi,".
c
В Sat, 17 Aug 2024 11:47:30 +
SIMON Nicolas via R-help пишет:
> nmrun <- paste0("cmd.exe /k ",nm_log,".bat ",nmi,".ctl ",nmi,".lst")
You are using the /k option that instructs cmd.exe to keep the command
prompt open. Does the batch file con
t;.ctl ",nmi,".lst")
# run
system(nmrun, invisible = F, show.output.on.console = T, wait = T)
Le 17 août 2024 à 13:31, Duncan Murdoch a écrit :
On 2024-08-17 6: 21 a. m. , SIMON Nicolas via R-help wrote: > I would like to
stop a dos shell windows following the cmd (execute) command. Is there a
I would like to stop a dos shell windows following the cmd (execute) command.
Is there a way to do that from R?
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PLEASE do read the posting
what you are trying to
do in the geom_boxplot() call and how it uses the summarised data tibble.
It may even be that if you do that, you will find what's causing the
problem! (I speak from bitter experience!!)
Very best (all),
Chris
On 16/08/2024 17:51, SIBYLLE STÖCKLI via R-help wrote:
("red","darkgreen"), labels=c("ÖLN", "BIO"))+
scale_fill_manual(values=c("red","darkgreen"), labels= c("ÖLN", "BIO"))+
theme(legend.title = element_blank())+
theme(legend.text=element_text(size=20))
p1<-p
olor_manual(values=c("red","darkgreen"), labels=c("�LN", "BIO"))+
scale_fill_manual(values=c("red","darkgreen"), labels= c("�LN", "BIO"))+
theme(legend.title = element_blank())+
theme(legend.text=element_text(size
mask1 | mask2 # drops elements 1, 3, 4, 8
# [1] TRUE FALSE TRUE TRUE FALSE FALSE FALSE TRUE FALSE FALSE
--
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Ivan
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ask1 & mask2)])
[1] "'is.NA' value mismatch: 389 in current 56989152 in target"
--> so there is just a mismatch in NA not in the xy pixels, right?
Sibylle
-Original Message-
From: Ivan Krylov
Sent: Friday, August 16, 2024 10:51 AM
To: sibylle.stoec...@gm
Here my idea including the error:
> m1=r1[r1="NA",]
> m2=r2_resampled[r2_resampled="NA",]
>
>
> all.equal(getValues(r1)[!m1], getValues(r2_resampled)[!m2])
[1] "Numeric: lengths (80706867, 65806339) differ"
-Original Message-
From
(), using is.na(getValues(...)) should definitely work.
--
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Ivan
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LLE STÖCKLI via R-help
Cc: sibylle.stoec...@gmx.ch
Subject: Re: [R] allequal diff
В Fri, 16 Aug 2024 07:19:38 +0200
SIBYLLE STÖCKLI via R-help пишет:
> Is it possible to consider na.rm=TRUE?
> > all.equal(getValues(r1), getValues(r2_resampled), tolerance = 0)
>
> [1] "
В Fri, 16 Aug 2024 07:19:38 +0200
SIBYLLE STÖCKLI via R-help пишет:
> Is it possible to consider na.rm=TRUE?
> > all.equal(getValues(r1), getValues(r2_resampled), tolerance = 0)
>
> [1] "'is.NA' value mismatch: 9544032 in current 66532795 in target"
x27;is.NA' value mismatch: 9544032 in current 66532795 in target"
Kind regards
Sibylle
-Original Message-
From: R-help On Behalf Of Ben Bolker
Sent: Friday, August 16, 2024 1:06 AM
To: r-help@r-project.org
Subject: Re: [R] allequal diff
Digging into
Its where n.per.grp is first calculated. I rounded. Gosh do I feel stupid.
Thanks to all who weighed in.
Best Regards,
Grant Izmirlian
From: Duncan Murdoch
Sent: Thursday, August 15, 2024 2:59 PM
To: Izmirlian, Grant (NIH/NCI) [E] ;
r-help@r-project.org
me values
> print(result)
[1] FALSE
>
Kind regards
Sibylle
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PLEASE do read the
;ÖLN", "BIO"))+
scale_fill_manual(values=c("red","darkgreen"), labels= c("ÖLN", "BIO"))+
theme(legend.title = element_blank())+
theme(legend.text=element_text(size=20))
p1<-p1 + expand_limits(y=c(0, 80))
p1
[[alternative HT
actorial design.
node <- 29
n.per.grp <- n.per.grp.lst[conds[node, 1]]
trnd <- trnds[conds[node, 2]]
h <- H[conds[node, 3]]
delta.j <- delta + h*shapes[[trnd]]
## covariates:
ID.i <- c(outer(rep(1:n.per.grp,each=n.tt),c(0,n.per.grp),FUN="+"))
arm.i <- rep(0:1, ea
ts,
package:methods, Autoloads, package:base
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t: Sunday, August 11, 2024 6:30 PM
To: sibylle.stoec...@gmx.ch
Cc: R-help@r-project.org
Subject: Re: [R] geom_smooth with sd
Hi!
This is probably completely off base, but your ymin and y max setup lines are
different. One uses sqrt(y), while the second uses sqrt(length(y)).
Could that p
Dear community
Using after_stat() I was able to visualise ggplot with standard deviations
instead of a confidence interval as seen in the R help.
p1<-ggplot(data = MS1, aes(x= Jahr, y= QI_A,color=Bio, linetype=Bio)) +
geom_smooth(aes(fill=Bio,
ymax=after_stat(y+se*s
(printing) branch? Then you would be able to always
return(invisible(list("ei"=ap,"vi"=vap))), whether printing is TRUE or
not.
--
Best regards,
Ivan
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e.rpkm$purity2)
then running result2 <- residuals(lm.fit( x= pur2.1, y = dat));
now I am thinking whether an intercept is required or not.
Ding
From: R-help On Behalf Of Yuan Chun Ding via
R-help
Sent: Saturday, August 10, 2024 12:30 PM
To: Bert Gunter ; Ben Bolker
Cc: r-help@r-project.org
Subjec
You are right. I also just thought about that, no intercept is not applicable
to my case.
Ding
From: Bert Gunter
Sent: Saturday, August 10, 2024 1:06 PM
To: Yuan Chun Ding
Cc: Ben Bolker ; r-help@r-project.org
Subject: Re: [R] a fast way to do my job
Ah, messages crossed. A no-intercept
after add intercept, all residuals are the same from lm or lm.fit.
Ding
From: Bert Gunter
Sent: Saturday, August 10, 2024 1:00 PM
To: Yuan Chun Ding
Cc: Ben Bolker ; r-help@r-project.org
Subject: Re: [R] a fast way to do my job
Probably because you inadvertently ran different models. Without
0.99.
I have not found the reason.
Thanks,
Ding
From: Bert Gunter
Sent: Friday, August 9, 2024 7:11 PM
To: Ben Bolker
Cc: Yuan Chun Ding ; r-help@r-project.org
Subject: Re: [R] a fast way to do my job
Better idea, Ben! It would work as you might expect it to to produce the same
results as the
ng the
list.
Martin
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
nd
inform the sender that you do not wish to receive further e-mail from the
sender. (LCP301)
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ss discriminated against by Cloudflare. Maybe petition the
WDI maintainer to export a function that parses a JSON file manually
downloaded with a browser?
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Best regards,
Ivan
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https:
st by
accessing it through Tor.
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Best regards,
Ivan
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.ht
oval
must be 'o' or 'O', not the digit '0'. (Digits after the first character are
standard.)
Regards,
Jorgen Harmse.
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pick d before a.
A greedy algorithm for K variables out N tests N + (N-1) + ... +
(N-K+1) = N*K - K(K-1)/2 models. An exhaustive search would have to test
choose(N,K) = N!/(N-K)!/K! models.
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Best regards,
Ivan
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latter case, why
stash them in a variable? For more control of the display, consider sprintf (or
a wrapper that combines sprintf with cat).
Regards,
Jorgen Harmse.
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optim() doesn't support the truncated (line search) Newton-CG method.
See the 'optimx' and 'nloptr' packages for an implementation of a
truncated Newton method (not necessarily exactly the same one).
--
Best regards,
Ivan
______
O'Keefe ; r-help@r-project.org
Subject: Re: [R] please help generate a square correlation matrix
Your expanded explanation helps clarify your intent. Herewith some comments. Of
course, feel free to ignore and not respond. And, as always, my apologies if I
have failed to comprehend your intent.
mutation,
then it is informative to know how strong the negative correlation when
considering different combination of treatment strategies.
Ding
From: R-help On Behalf Of Richard O'Keefe
Sent: Saturday, July 27, 2024 4:47 AM
To: Bert Gunter
Cc: r-help@r-project.org
Subject: Re: [R] please
; package:
https://cran.r-project.org/package=caret/vignettes/caret.html
If you do encounter an error on your way or get stuck not knowing how
exactly to continue, please ask a more specific question.
--
Best regards,
Ivan
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R-help@r-project.org ma
(4, 2/3),
adjustcolor("orange4", 2/3))
lwds <- c(3, 2, 2)
matlines(xx, fits, col = cols, lwd = lwds, lty=1)
legend("topleft", c("true f(x)", "smooth.spline()", "earth()"),
col=cols, lwd=lwds, bty = "n")
title(paste("earth
.test(tem2[,1],tem2[,2])
r[i, j] <- tmp3$estimate
P[i, j] <- tmp3$p.value
}
}
}
r<-as.data.frame(r)
P<-as.data.frame(P)
From: R-help On Behalf Of Yuan Chun Ding via
R-help
Sent: Thursday, July 25, 2024 11:26 AM
To: Rui Barradas ; r-help@r-project.org
Subject: Re: [
HI Rui,
Thank you for the help!
You did not remove a row if zero values exist in both column pair, right?
Ding
From: Rui Barradas
Sent: Thursday, July 25, 2024 11:15 AM
To: Yuan Chun Ding ; r-help@r-project.org
Subject: Re: [R] please help generate a square correlation matrix
Às 17: 39 de
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