I'm trying to build a data.frame row-by-row like so:
df <- data.frame(rbind(list('a',1), list('b', 2), list('c', 3)))
I was surprised to see that the columns of the resulting data.frame
are stored in lists rather than vectors.
str(df)
'data.frame': 3 obs. of 2 variables:
$ X1:List of 3
..$ :
actor of around sqrt(2),right?), even if
> both are for the mean or both are for the median.
>
> Cheers,
> Bert
>
> On Fri, Jul 5, 2013 at 11:28 AM, David Winsemius
> wrote:
>>
>> On Jul 5, 2013, at 11:15 AM, Shaun Jackman wrote:
>>
>>> Hi Bert, Dennis,
>
lower = conf[1,],
upper = conf[2,]))
Cheers,
Shaun
On 5 July 2013 11:28, David Winsemius wrote:
>
> On Jul 5, 2013, at 11:15 AM, Shaun Jackman wrote:
>
>> Hi Bert, Dennis,
>>
>> I'll agree that using a barchart was a poor choice. I was in fact using a
>> notched
rrent/ for an expanded
> version of the package help pages, which include the graphs generated
> by the code. I believe there's also a base graphics version that you
> can get from the gplots package, but I don't know a lot about it.
>
> Dennis
>
> On Thu, Jul 4, 201
Hi,
I'd like to draw a lattice barchart of means with error bars to show
the standard deviation. I have the barchart, how do I add the error
bars?
require(datasets)
require(lattice)
x <- aggregate(weight ~ Diet, ChickWeight, function(x) c(mean=mean(x),
sd=sd(x)))
barchart(weight[,'mean'] ~ Diet,
June 2013 05:50, Adams, Jean wrote:
> Shaun,
>
> See the help on contrasts ...
> ?contr.treatment
>
> Jean
>
>
> On Tue, Jun 25, 2013 at 7:07 PM, Shaun Jackman wrote:
>>
>> Hi,
>>
>> I've used `lm` to create a linear model of a continuou
Hi,
I've used `lm` to create a linear model of a continuous variable
against a factor variable with four levels using an example R data set
(see below). By default, it uses a treatment contrast matrix that
compares each level of the factor variable with the first reference
level (three comparisons
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