interactively with the display. But
> in many ways grid's programmatic editing and redisplay of modified
> grobs is more flexible and powerful, I would say. In any case, the
> editing capabilities exist.
>
> -- Bert
>
> On Sun, Mar 10, 2013 at 3:47 PM, Jim Lemon wrote:
>
Dear all,
I am curious if anyone knows of a command/program that would enable one to
edit a figure in R once it is created (akin to Matlab). Currently, if I
need to make any changes to the figure I do so and then have to run the
plotting portion of the code again. I have searched the R site mail
I
need. Any help is greatly appreciated.
Thanks in advance!
Sherri Heck
Graduate Research Assistant
National Center for Atmospheric Research, Boulder CO
University of Colorado, Boulder CO
[[alternative HTML version deleted]]
__
R-help@r-project.org m
Dear all-
I have a data set that looks as follows (data are taken every 5 minutes):
LST in mphDeg DegF DegF2%volts Degmph2 w/m2
090501 -9997.5 259.3 33.0 -999 41.5 -999 -9999.10.2
0905010005 -999 11.0 261.2 33.1 -999 42.6
Dear All-
I am trying to create a legend where the first 9 terms are represented as
pch=16 in one column (which I am able to do); but, I would like the last two
terms in that column to be 'lines" (which are black and red - just as it looks
like in the plot). I have read through many help pages
code file. Then, if the code
is run on a Windows machine, the function call windows() does the
Windows thing; but if the code is run on Linux then the above test
detects that, and defines a function windows() which does the same
as X11().
Ted.
On 26-Feb-09 01:25:36, Sherri Heck wrote:
i am askin
hahaha! okay. at least your responses are positive! thx!
David Winsemius wrote:
Definitely "maybe". Possibly "yes". Usually.
Pick one of the above.
-- David Winsemius
On Feb 25, 2009, at 8:25 PM, Sherri Heck wrote:
i am asking if, in general, r code can be writ
i am asking if, in general, r code can be written on a linux-based
system and then run on a windows-based system.
Rolf Turner wrote:
On 26/02/2009, at 2:08 PM, Sherri Heck wrote:
Dear All-
I have been given some Rcode that was written using a Linux OS, but I
use Windows-based R. The
Dear All-
I have been given some Rcode that was written using a Linux OS, but I
use Windows-based R. The person that is giving it to me said that it
needs to run on a Linux system. Does anyone have any insight and/or can
verify this. I haven't yet obtained the code, so I haven't been able t
Dear All-
I am trying to merge two data files - they have different date formats
and different times zones. I need to match up the date/time of the
datasets and then invoke a conditional statement, such as: if dataC$mph
is >= 12 then keep dataM$co23 for the corresponding time/date stamp.
sn
and help and happy new year:
sherri heck
Gabor Grothendieck wrote:
Try this:
aggregate(z$mph, trunc(time(z), "hour"), mean)
(09/01/05 00:00:00) (09/01/05 01:00:00) (09/01/05 02:00:00)
9.2750010.08333 9.2
On Tue, Dec 30, 2008 at 6:30 PM,
("character", rep("numeric", 10)))
z.ts <- ts(z, frequency=12)#avging 5 min intervals to get hourly
avg.
ww <- matrix(aggregate(z.ts[,2], FUN=mean))
any thoughts as to how to add the time stamp is greatly welcomed!
sherri heck
__
Dear all-
I have a dataset (see a sample below - but the whole dataset is June
2005 - June 2008). The "LST" format is "YYMMDDHHmm" and I would like to
get the hourly average of the "mph" for the summer months (spanning all
years). I have been trying to use "aggregate" but am not having much
Hi everyone-
I have a dataset that I created using the aggregate command:
Hour LevelC2
1 1 1 -3.517117e+00
2 2 1 -2.536083e+00
3 3 1 -1.429000e+00
4 4 1 -1.148667e-01
5 5 1 1.345333e+00
6 6 1 3
Fantastic! Each suggestion worked beautifully. Thanks so much.
Henrique Dallazuanna wrote:
Try this:
is.na <http://is.na>(spdco2[,2]) <- which(spdco2[,2] < 4.7)
spdco2
On Thu, Sep 4, 2008 at 4:21 PM, Sherri Heck <[EMAIL PROTECTED]
<mailto:[EMAIL PROTECTED]>> wro
Hi All-
I have a data set (spdco2)
> spdco2
[,1] [,2] [,3]
[1,]1 5.4 382.4212
[2,]2 5.1 383.0315
[3,]3 4.8 383.9520
[4,]4 4.7 384.4376
[5,]5 4.7 384.5929
[6,]6 4.4 384.8864
[7,]7 4.1 385.2156
[8,]8 3.8 385.2919
[9,]9 3.7 385.5925
[10,] 10
text
to the plot in the appropriate place? Or both?
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Sherri Heck
Sent: Tuesday, September
Hi All-
I have 24 boxplots on one graph. I do not have the whiskers extending
to the outliers, but I would like to label the maximum value of each
outlier above the whiskers. I have the stats but am having trouble
figuring out how to label the whiskers.
Any suggestions would be great!
she
Dear All-
I have a dataset that is comprised of the following:
doy yr mon day hr hgt1 hgt2 hgt3 co21 co22 co23 sig1 sig2 sig3 dif flag
244.02083 2005 09 01 00 2.6 9.5 17.8 375.665 373.737 373.227 3.698 1.107
0.963 -0.509 PRE
244.0625 2005 09 01 01 2.6 9.5 17.8 393.66 384.773 379.466 15.336 11
hat you want?
>
> sherri <- data.frame(grp=rep(letters[1:6], 20), value=rnorm(6*20)+6)
> temp <- with(sherri, boxplot(value~grp, xaxt='n'))
> axis(1, 1:5+0.5, rep('', 5))
>
> Peter Alspach
>
>
>
>> -Original Message-
>> From: [EMA
hi all-
i am creating a boxplot and would like to shift the x-axis tick marks
(named 1:23) so that the ticks are in between the boxes and not centered
in the middle of the boxes. i have searched the help files and google
and have not found what i am looking for.
does anyone know how to do this
th Hour co2 num1 num2
>>> 2006 110 383.3709 28 28
>>> 2006 111 383.3709 28 28
>>> 2006 112 383.3709 28 28
>>> 2006 113 383.3709 28 28
>>> 2006 114 383.3709 28 28
>>> 2006 115 383.3709
ion(Lines), header = TRUE)
> aggregate(DF[4:6],
>with(DF, data.frame(Year, Qtr = (Month - 1) %/% 3 + 1, Hour)),
>mean)
>
> On Dec 1, 2007 3:57 PM, Sherri Heck <[EMAIL PROTECTED]> wrote:
>
>> Hi all-
>>
>> I have a dataset (year, month, hour, co2(p
Hi all-
I have a dataset (year, month, hour, co2(ppm), num1,num2)
[49,] 2006 110 383.3709 28 28
[50,] 2006 111 383.3709 28 28
[51,] 2006 112 383.3709 28 28
[52,] 2006 113 383.3709 28 28
[53,] 2006 114 383.3709 28 28
[54,] 2006 115 383.3709
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