, within the calling function, while the
second will evaluated bar=harry within the called function. I think.
Thank you both very much; and thanks, too, to Martin Morgan, who
replied off-list pointing me at
bar - eval.parent(match.call()$bar)
.
Grateful regards,
Sietse
Sietse Brouwer
whether that's because I
didn't know the right words. How would you phrase/define this problem?
Kind regards, and thanks in advance,
Sietse
Sietse Brouwer
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