Yes. That's correct. The main problem is to solve a matrix where the
colSums and rowSums are known. Credits to dwinsem...@comcast.net for
pointing out the function "r2dtable" to me. Just feed it with the
known margins and the number of matrices You want. And Bob is Your
uncle!
Look at the thread "
17550 50
> [11,] 107 23 24 19 112 19 25 20 349
>
>
> -
> David L Carlson
> Department of Anthropology
> Texas A&M University
> College Station, TX 77840-4352
>
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-hel
looking to fill at 10x8 matrix (i.e. 80 values).
> If you can clarify better we may be better able to help you.
>
> Charles
>
>
> On Thu, Sep 11, 2014 at 3:47 AM, Stefan Petersson wrote:
>>
>> Hi,
>>
>> I have two vector of margins. Now I want to cre
Hi,
I have two vector of margins. Now I want to create "fill" matrix that
reflects the margins.
seats <- c(17,24,28,30,34,36,40,44,46,50)
mandates <- c(107,23,24,19,112,19,25,20)
Both vectors adds up to 349. So I want a 10x8 matrix with row sums
corresponding to "seats" and column sums corresp
Hi,
Is there any package (or homegrown function) that can produce
"Parliament Seats Graph"? I'm referring to the nice looking concentric
half circles of colored "seats" as seen on Wikipedia (for example).
I can pretty easily plot the points and color them. But I can't group
the colored points in
I have three media channels where I can push public health information (tv,
radio and newspaper). Any given citizen can be touched by the information
from one, two or three channels (let's ignore for the moment that citizens
might miss the information all together). Hence these sets:
library(sets
Hi,
I use a regular web hosting service to build a web site under windows .NET.
Now I need statistical functionality on the site, and I would really like
to use R for that. However, I'm not allowed to install anything (e.g. R) on
the host. Are there any implementations/workarounds of R that doesn'
I want to create a sequence, repeating each element according to a vector.
I have this:
v <- c(4, 4, 4, 3, 3, 2)
And want to create this:
1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 5 5 5 6 6
TIA
// s
R version 3.0.0 (2013-04-03)
Platform: x86_64-pc-linux-gnu (64-bit)
locale:
[1] LC_CTYPE=en_US.UTF-8 L
Hi,
I have two groups, and I want to find the dissimiarity between the members
of the two groups. Since I have mixed level variables on the members, I opt
for the daisy function in the cluster package.
Let's pretend that the following represent my groups:
x <- data.frame(sex=factor(c(1,0,0,1,0,1
Hi,
I've set up a discrete choice experiment on magazine preference
following the guidelines from Azaiki. H & Nishimura K. "Design and
Analysis of Choice Experiments Using R. A Brief Introuction" from
Agricultural Informatin Research 17(2), 2008. 86-94.
I'm working with the clogit() function from
> >>
> >
> > The helpfiles for 'download.file' was not that helpful. But maybe it's just
me
> > not being able to read them correctly.
>
> Yes, looks like this is the case.
>
> > I tried to call install.packages with the 'method=wget', and hoped for a
> > username and password dialog. But no luc
CKAGES[.gz] file. It then calls
> download.file to get the packages.
>
> So please read the help for download.file (as the help pages say), and
> try the solutions described there.
>
> On Wed, 28 Sep 2011, Stefan Petersson wrote:
>
The helpfiles for 'download.file
inizio.se> writes:
>
>
> Hi,
>
> I've set up a very simple R repository. Just a single source
> library. Everything works fine. I can install the package on my client
> using:
>
> install.packages(repos='http://www.myServer.se/myRepo/',
> pkgs='myLib', dep=TRUE)
>
> However, I want to prote
Hi,
I've set up a very simple R repository. Just a single source
library. Everything works fine. I can install the package on my client
using:
install.packages(repos='http://www.myServer.se/myRepo/',
pkgs='myLib', dep=TRUE)
However, I want to protect the repo, so I use a
.htaccess, placed di
Hi,
Sorry for my ignorance, but how can I see if a function is 'compiled code' or
plain R? E.g. the daisy
function from the cluster package.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Hi,
I'm trying to create a distance matrix. And it works out somewhat ok. However,
I suspect that there are
some efficiency issues with my efforts. Plz have a look at this:
donor <- matrix(c(3,1,2,3,3,1,4,3,5,1,3,2), ncol=4)
receiver <-
matrix(c(1,4,3,2,4,3,1,5,1,3,2,1,4,5,3,5,1,3,2,4,5,1,2,3
First, I don't have the correct lingo for this topic, so I can't really find a
solution for my problem. And
maybe I formulate it incorrectly, so bear with me.
How would I calculate a 'constant transition matrix' if I know a given value at
a given time?
Let's say I know that my value is 54,0
>
> Just double all the backslashes and you are fine.
> In order to see the outcome, use cat() (not print).
>
> Uwe Ligges
>
> On 16.06.2010 09:49, Stefan Petersson wrote:
> >
> > Hi,
> >
> > I'm trying to build a vector of latex commands. H
Hi,
I'm trying to build a vector of latex commands. However, I need the command
strings to begin with a backslash "\". I have:
test <- c('foo','bar')
and I need to rebuild the array, encapsulating the text items with latex stuff,
like this:
paste("\parbox[b]{3cm}{", test, "}", fill=TRUE)
Ac
I often read SPSS system files (*.sav) into R using the 'read.spss' function
from the 'foreign' library. To retain all the meta data, i.e. 'variable
labels', I call the function like this:
test.sav <-
read.spss('http://www.cdc.gov/healthyYouth/shpps/2006/spss/envs2006.sav',
to.data.frame=FAL
>
>
> I'm trying to dynamically build variable names to use on a list. Let's say I
have a list like this one:
>
> l <- list(V1_1=c(1,2,3), V1_2=c('One','Two','Three'))
>
> And I succesfully build my variable name like this:
>
> paste('l$', 'V1_1', sep='')
>
> Why can't I just run a mean call
I'm trying to dynamically build variable names to use on a list. Let's say I
have a list like this one:
l <- list(V1_1=c(1,2,3), V1_2=c('One','Two','Three'))
And I succesfully build my variable name like this:
paste('l$', 'V1_1', sep='')
Why can't I just run a mean call with the pasted variab
S: Works! Thanx...
2010-01-29 Henrique Dallazuanna wrote:
Try this:
>
>invisible(mysqlCloseConnection(con))
>
>On Fri, Jan 29, 2010 at 9:10 AM, Stefan Petersson
> wrote:
>>
>> Hi,
>>
>> A small (but annoying) problem with RMySQL library. When a connec
Hi,
A small (but annoying) problem with RMySQL library. When a connection is
closed, it echoes 'TRUE' to the console. Like this:
R> mysqlCloseConnection(con)
[1] TRUE
The real problem comes when I use RMySQL with Sweave, since the TRUE echo gets
into my final Sweave document. Even when I ex
I'm trying to typeset at simple crosstable with the Hmisc latex function. And I
have two problems.
1. How do I make all columns the same width? The Latex function seems very
unwilling to break the 'cgroup' labels and the factor level labels. Please have
look at this screenshot that shows my pr
hi,
I have some session data in a dataframe, where each session is recorded with a
start and a stop date. Like this:
session_start session_stop
===
2009-01-03 2009-01-04
2009-01-01 2009-01-05
2009-01-02 2009-01-09
A session is at least one day long. Now I want
I'm trying to create a new column in my data.frame where subjects are
categorized depending on values on four other columns. In any other case I
would just nest a few ifelse statements, however, in this case i have
4*6*2*3=144 combinations and i get weird 'context overflow' errors. So I wonder
I have an MS Access database with one table and one column holding rep(1:10)
I use:
library(RODBC)
channel <- odbcConnect("test")
sqlQuery(channel, paste("SELECT col FROM tblTest"), believeNRows=FALSE)
and get:
49
50
51
52
53
54
55
56
57
12337
What? The above should, of course, read
r-help,
I'm currently using 'lp.transport' from 'lpSolve' to solve a transportation
problem. However, I've experienced some performence issues, and have been told
that other solvers may perform better. I've looked briefly at 'Rsymphony' and
'rglpk', but I can't seem to figure out how/if they s
ng,
I have a matrix (x) with binary content. Each row of the matrix holds exactly
one 1, and the rest of the row is zeros. The thing is that I need to 'collapse'
the matrix to one column where each row holds the original column index of the
1's (y). Sometimes, the matrix is quite large, so I h
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