Hi,
I try to execute the seven lines of code below to plot a graph. But I
am failing as the messages below show. Where am I going wrong?
install.packages("rgl")
library(rgl)
y_hat = X%*%B_hat
open3d(windowRect = c(100,100,900,900),family = "serif")
color = rainbow(length(y_hat))[rank(y_hat)]
nd
> reply-to-all to the message you want to reply to. The threading is managed
> by hidden message ids, not subjects.
> --
> Sent from my phone. Please excuse my brevity.
>
> On April 5, 2017 11:26:27 AM PDT, "Tunga Kantarcı" <tungakanta...@gmail.com>
> wrote
this and I should read about it.
On Wed, Apr 5, 2017 at 7:28 PM, Marc Schwartz <marc_schwa...@me.com> wrote:
>
>> On Apr 5, 2017, at 11:34 AM, Tunga Kantarcı <tungakanta...@gmail.com> wrote:
>>
>> Thanks a lot Marc, for informing that R is object oriented, implying
hwa...@me.com> wrote:
>
>> On Apr 5, 2017, at 11:41 AM, Tunga Kantarcı <tungakanta...@gmail.com> wrote:
>>
>> OK I cannot figure this out clearly in the guidelines of posting. When
>> I reply to a message I should out "Re:" in front of the subject lin
OK I cannot figure this out clearly in the guidelines of posting. When
I reply to a message I should out "Re:" in front of the subject line
of the original post. So if the subject line of the original post it
is "this is a post", then I should use "Re: this is a post" in the
subject line, for my
Thanks a lot Marc, for informing that R is object oriented, implying
that one should always try to vectorise the code (although I am not so
clear why this should be the case) but also for all the references you
provide.
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R-help@r-project.org mailing
I have the MATLAB code pasted below that calculates yields to maturity.
IRR = zeros(length(c),length(M))
The ith row and jth column is the price of the bond with coupon c(i)
and maturity M(j).
for i = 1:3
for j = 1:3
if j == 1
IRR(i,j) =
Marc, thank you for this excellent answer.
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and provide
I have a data frame. One column (call this column a) contains years,
like 1871, and another column (call this column b) contains months,
like 2. I need to convert these year-month combinations, stored in
these two date vectors, into a single serial date number. E.g. year
1871 and month 2, stored
Thank you for all the helpful answers.
Tunga
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
Thank you for all the helpful answers.
Tunga
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
Consider a data frame named data. data contains 4 columns and 1000
rows. Say the aim is to bring together columns 1, 2, and 4, if the
values in column 4 is equal to 1. We could use the syntax
data(data[,4] == 1, c(1 2 4))
for this purpose. Suppose now that the aim is to bring together
columns 1,
I have a data frame that includes several columns representing
variables and variables names are indicated at the top row of the data
frame. That is, I had a csv file where variable names were stored in
the top row, and when I imported the csv file to R, R created a data
frame that appears with
Consider a data frame which I name as rwrdatafile. It includes several
variables stored in columns. For each variable there are 1000
observations and hence 1000 rows. The interest lies in the values of
the second column of this data frame, that is in rwrdatafile[,2]. What
I am trying to accomplish
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